Problem 14
Question
In \(3-41\) , express each product in simplest form. Variables in the radicand with an even index are non-negative. $$ (-2 \sqrt{5})^{2} $$
Step-by-Step Solution
Verified Answer
The simplest form of \((-2 \sqrt{5})^{2}\) is 20.
1Step 1: Understand the Expression
We have the expression \((-2 \sqrt{5})^{2}\). This implies we will square everything inside the parentheses: \(-2\) and \(\sqrt{5}\).
2Step 2: Square the Coefficient
Square the coefficient \(-2\). Calculating \((-2)^{2}\), we get: \[ (-2)^{2} = 4 \]
3Step 3: Square the Radical Part
Now, square the radical part \(\sqrt{5}\). Squaring \(\sqrt{5}\), we get: \[ (\sqrt{5})^{2} = 5 \]
4Step 4: Multiply the Results
Multiply the results from Steps 2 and 3. We have: \[ 4 \times 5 = 20 \]
5Step 5: Express in Simplest Form
The expression \((-2 \sqrt{5})^{2}\) simplifies to 20.
Key Concepts
Squaring RadicalsSquaring IntegersMultiplying ResultsExpressing in Simplest Form
Squaring Radicals
Understanding how to square a radical expression is essential in algebra. A radical expression involves a root, such as the square root. When squaring the radical part of an expression, like \(\sqrt{5}\), you essentially reverse the square root operation. By definition, when you square a square root, you "cancel out" the square root symbol, leaving the value under the root. Here's what happens in our example:
- Given \((\sqrt{5})^{2}\), the square and the square root neutralize each other.
- The result is simply the radicand itself: \(5\).
Squaring Integers
Squaring an integer involves multiplying the number by itself. This is straightforward: take the number and find the product of multiplying it by itself. Let's look closely at how we apply this to our example:
- Consider the integer coefficient \(-2\) in the expression \((-2 \sqrt{5})^{2}\).
- Square it by calculating \((-2)\times (-2)\), which results in \(4\).
Multiplying Results
After squaring each part of the expression separately, the next step is to combine those results. This involves multiplying the squared integer and the squared radical part together. Here's how that works in this context:
- We've determined from our previous steps that \((-2)^{2} = 4\) and \((\sqrt{5})^{2} = 5\).
- Multiply these results: \(4 \times 5\).
- This gives us the product of \(20\).
Expressing in Simplest Form
The final step in simplifying the expression involves presenting your result in its simplest form. Simplification means reducing your answer to its most basic version, without any radicals or unnecessary components. In our case, the initial expression was \((-2 \sqrt{5})^{2}\). After processing each part of the expression separately:
- We squared all components, yielding an integer result.
- The final product obtained was \(20\).
Other exercises in this chapter
Problem 13
In \(3-38\) , write each radical in simplest radical form. Variables in the radicand of an even index are non-negative. Variables occurring in the denominator o
View solution Problem 13
In \(3-14,\) determine whether each of the numbers is rational or irrational. $$ \frac{\pi}{\pi} $$
View solution Problem 14
In \(11-38,\) evaluate each expression in the set of real numbers. $$ \sqrt{625} $$
View solution Problem 14
In \(3-38\) write each expression in simplest form. Variables in the radicand with an even index are non-negative. Variables occurring in the denominator of a f
View solution