Problem 14
Question
In \(3-18,\) write the first five terms of each sequence. $$ a_{n}=\frac{n+2}{n} $$
Step-by-Step Solution
Verified Answer
The first five terms are 3, 2, \(\frac{5}{3}\), \(\frac{3}{2}\), and \(\frac{7}{5}\).
1Step 1: Understand the Sequence Formula
The sequence is given by the formula \(a_{n} = \frac{n+2}{n}\). This means to find any term in the sequence, we need to substitute \(n\) with the desired term number.
2Step 2: Calculate the First Term
To find the first term \(a_1\), substitute \(n = 1\) into the formula: \[a_1 = \frac{1+2}{1} = 3.\] So, the first term is 3.
3Step 3: Calculate the Second Term
Next, find the second term \(a_2\) by substituting \(n = 2\): \[a_2 = \frac{2+2}{2} = 2.\] Thus, the second term is 2.
4Step 4: Calculate the Third Term
Calculate the third term \(a_3\) by replacing \(n = 3\): \[a_3 = \frac{3+2}{3} = \frac{5}{3}.\] So, the third term is \(\frac{5}{3}\).
5Step 5: Calculate the Fourth Term
Find the fourth term \(a_4\) with \(n = 4\): \[a_4 = \frac{4+2}{4} = \frac{3}{2}.\] Therefore, the fourth term is \(\frac{3}{2}\).
6Step 6: Calculate the Fifth Term
Finally, calculate the fifth term \(a_5\) by substituting \(n = 5\): \[a_5 = \frac{5+2}{5} = \frac{7}{5}.\] Thus, the fifth term is \(\frac{7}{5}\).
Key Concepts
Sequence FormulaTerm CalculationFractional TermsSubstitution Method
Sequence Formula
When dealing with arithmetic sequences, particularly those expressed with a formula, it is crucial to understand the structure of the sequence formula itself. The sequence we are examining here is represented by the formula \[ a_{n} = \frac{n+2}{n} \].
This formula tells us how to find any term in the sequence just by knowing the term number, represented by \( n \). In other words, the sequence formula acts as a rule or a function: you plug in a value for \( n \), and out comes the value of the sequence at that term position.
This formula tells us how to find any term in the sequence just by knowing the term number, represented by \( n \). In other words, the sequence formula acts as a rule or a function: you plug in a value for \( n \), and out comes the value of the sequence at that term position.
- The numerator, \( n+2 \), increases as \( n \) increases, adding a constant to \( n \).
- The denominator, \( n \), is simply the term number you are choosing to find.
Term Calculation
Calculating the terms of the sequence involves substituting specific values of \( n \) into the sequence formula. For many, this sequence's pattern gradually emerges through calculating a few specific terms.
Let's break down these steps:
Let's break down these steps:
- For the first term \((a_1)\), substitute \( n = 1 \) into the formula: \[ a_{1} = \frac{1+2}{1} = 3. \] The result, \( 3 \), is the value of the first term.
- For the second term \((a_2)\), substitute \( n = 2 \): \[ a_{2} = \frac{2+2}{2} = 2. \] Hence, the second term is \( 2 \).
Fractional Terms
Some terms in a sequence may become fractional, an essential aspect of many sequences in mathematics.
In our given sequence, from the third term onward, the terms are fractions.
In our given sequence, from the third term onward, the terms are fractions.
- The third term \((a_3)\) calculates to: \[ a_{3} = \frac{3+2}{3} = \frac{5}{3}. \] This displays how, by substituting \( n = 3 \) into the formula, the result is a fraction.
- For the fourth term \((a_4)\), substitute \( n = 4 \): \[ a_{4} = \frac{4+2}{4} = \frac{3}{2}. \] Again, this shows a fraction.
Substitution Method
The substitution method is a fundamental tool in calculating sequence terms. Here, it involves replacing \( n \) in the sequence formula with specific numerical values to find the corresponding sequence term.
This method doesn't just apply to sequences but extends widely across mathematical disciplines whenever formulas are used to solve problems.
This method doesn't just apply to sequences but extends widely across mathematical disciplines whenever formulas are used to solve problems.
- To find the fifth term \((a_5)\), we substitute \( n = 5 \): \[ a_{5} = \frac{5+2}{5} = \frac{7}{5}. \] This substitution provides the sequence value at that position.
Other exercises in this chapter
Problem 14
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