Problem 14
Question
In \(3-14,\) write each exponential equation in logarithmic form. $$ 0.001=100^{-\frac{3}{2}} $$
Step-by-Step Solution
Verified Answer
\(-\frac{3}{2} = \log_{100} 0.001\).
1Step 1: Identify the Exponential Equation Components
An exponential equation is of the form \(a = b^c\). In our case, \(a = 0.001\), \(b = 100\), and \(c = -\frac{3}{2}\).
2Step 2: Understand the Logarithmic Form
The logarithmic form answers the question: 'To what power must we raise the base to get the given number?' It is written as \( c = \log_b a \).
3Step 3: Rewriting in Logarithmic Form
Using the values identified: \(a = 0.001\), \(b = 100\), and \(c = -\frac{3}{2}\), the logarithmic form is: \(-\frac{3}{2} = \log_{100} 0.001\).
Key Concepts
Exponential EquationsConverting Exponentials to LogarithmsLogarithmic Form
Exponential Equations
An exponential equation is an equation in which a constant base is raised to a variable exponent. Consider this form:
Exponential equations enable us to model scenarios where quantities grow or shrink rapidly.
To solve these, observe the relationships among the base, exponent, and the result.
Understand the roles of these components to change between exponential and logarithmic forms.
- General form: \(a = b^c\)
- Components: \(a\) (result), \(b\) (base), \(c\) (exponent)
Exponential equations enable us to model scenarios where quantities grow or shrink rapidly.
To solve these, observe the relationships among the base, exponent, and the result.
Understand the roles of these components to change between exponential and logarithmic forms.
Converting Exponentials to Logarithms
Changing an exponential statement into logarithmic form helps us understand the relationships within an equation.
Follow these steps to convert:
This conversion is beneficial for solving problems that involve unknown exponents and for simplifying complex equations.
Follow these steps to convert:
- Identify the equation structure (\(a = b^c\))
- Flip it to determine the unknown exponent: (\(c = \log_b a\))
This conversion is beneficial for solving problems that involve unknown exponents and for simplifying complex equations.
Logarithmic Form
Once an exponential equation is transformed, it appears in logarithmic form. This new format reveals unique insights:
In our exercise, rewriting \(0.001 = 100^{-\frac{3}{2}}\) yields \(-\frac{3}{2} = \log_{100} 0.001\).
This confirms that \(-\frac{3}{2}\) is the exponent needed to make base \(100\) equal to \(0.001\). By understanding and utilizing this form, further complexities in mathematics can be resolved with ease.
- Formula: \(c = \log_b a\)
- Reading: "\(c\) is the power to which base \(b\) must be raised to obtain \(a\)."
In our exercise, rewriting \(0.001 = 100^{-\frac{3}{2}}\) yields \(-\frac{3}{2} = \log_{100} 0.001\).
This confirms that \(-\frac{3}{2}\) is the exponent needed to make base \(100\) equal to \(0.001\). By understanding and utilizing this form, further complexities in mathematics can be resolved with ease.
Other exercises in this chapter
Problem 14
In \(3-14,\) solve each equation for the variable. Express each answer to the nearest hundredth. $$ 75-4^{b}=20 $$
View solution Problem 14
Solve each equation for the variable and check. \(3 \ln x+\ln 24=\ln 3\)
View solution Problem 14
In \(3-14,\) find the common logarithm of each number to the nearest hundredth. $$ 0.1 $$
View solution Problem 14
In \(11-22,\) solve each equation for \(y\) in terms of \(x\) $$ x=(0.1)^{y} $$
View solution