Problem 14
Question
In \(3-14,\) use the quadratic formula to find the imaginary roots of each equation. $$ 2 x=x^{2}+3 $$
Step-by-Step Solution
Verified Answer
The imaginary roots are \( x = 1 \pm i\sqrt{2} \).
1Step 1: Write the equation in standard form
First, we need to rearrange the given equation to the standard form of a quadratic equation, which is \( ax^2 + bx + c = 0 \). The provided equation is \( 2x = x^2 + 3 \). We rearrange this to: \( x^2 - 2x + 3 = 0 \).
2Step 2: Identify coefficients
Now that we have the standard form \( x^2 - 2x + 3 = 0 \), we identify the coefficients: \( a = 1 \), \( b = -2 \), and \( c = 3 \). These coefficients will be used in the quadratic formula.
3Step 3: Write the quadratic formula
The quadratic formula is given by \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). We'll use this formula to find the roots of the equation.
4Step 4: Calculate the discriminant
Calculate the discriminant \( b^2 - 4ac \), which is part of the quadratic formula. Using the coefficients, we have: \((-2)^2 - 4 \cdot 1 \cdot 3 = 4 - 12 = -8\). A negative discriminant indicates the roots are imaginary.
5Step 5: Compute the roots using the quadratic formula
Since the discriminant \( -8 \) is negative, the roots are imaginary. Plug the values into the formula: \( x = \frac{-(-2) \pm \sqrt{-8}}{2 \cdot 1} \). Simplifying, we get \( x = \frac{2 \pm \sqrt{-8}}{2} \).
6Step 6: Simplify the imaginary roots
To simplify \( \sqrt{-8} \), we express it as \( \sqrt{-1 \times 4 \times 2} = 2i\sqrt{2} \), where \( i \) is the imaginary unit. Substitute this back to get \( x = \frac{2 \pm 2i\sqrt{2}}{2} \), which simplifies to \( x = 1 \pm i\sqrt{2} \).
Key Concepts
Imaginary RootsDiscriminantStandard FormCoefficients
Imaginary Roots
In mathematics, when dealing with quadratic equations, there are occasions when the solutions, also known as roots, are not real numbers. This happens when the part of the quadratic formula under the square root (the discriminant) is negative. In such cases, we have what are known as **imaginary roots.** Imaginary roots occur because the square root of a negative number is not a real number but an imaginary number.
- Imaginary numbers are created by multiplying a real number by the imaginary unit, represented as \( i \), where \( i = \sqrt{-1} \).
- For example, in the context of finding roots, when the discriminant is \( -8 \), the square root of \( -8 \) simplifies to \( 2i\sqrt{2} \).
Discriminant
The discriminant is a critical part of the quadratic formula used to determine the nature of the roots of a quadratic equation. It is given by the expression \( b^2 - 4ac \), where \( a \), \( b \), and \( c \) are coefficients from the standard form of the quadratic equation \( ax^2 + bx + c = 0 \). The value of the discriminant provides insight into the types of solutions you can expect:
- If the discriminant is positive, there are two distinct real roots.
- If the discriminant is zero, there is exactly one real root, also known as a repeated or double root.
- If the discriminant is negative, as in our example equation, the roots are imaginary.
Standard Form
A quadratic equation is most usefulness presented in its **standard form**. This is expressed as \( ax^2 + bx + c = 0 \). Here, each aspect of the equation serves a specific role:
- \( x^2 \) represents the quadratic term.
- \( x \) is the linear term.
- The constant term is \( c \).
Coefficients
In quadratic equations, coefficients are crucial as they directly influence the form and solutions of the equation. They are the numerical factors of the equation, denoted as \( a \), \( b \), and \( c \) in the standard form \( ax^2 + bx + c = 0 \).
- \( a \): The coefficient of the quadratic term \( x^2 \). This value can affect the parabola's width and direction.
- \( b \): The coefficient of the linear term \( x \). It influences the slope and position of the parabola.
- \( c \): The constant term, influencing the y-intercept of the parabola.
Other exercises in this chapter
Problem 14
In \(9-17,\) graph each system and determine the common solution from the graph. $$ \begin{array}{l}{y=2 x^{2}-6 x+5} \\ {y=x+2}\end{array} $$
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In \(3-18,\) find all roots of each given function by factoring or by using the quadratic formula. $$ \mathrm{f}(x)=x^{5}-x^{4}-2 x^{3} $$
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Without solving each equation, find the sum and product of the roots. \(x^{2}+2 x=0\)
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In \(9-14\) : a. For each given value of the discriminant of a quadratic equation with rational coefficients, determine if the roots of the quadratic equation a
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