Problem 14
Question
In \(3-14,\) find the natural logarithm of each number to the nearest hundredth. $$ \frac{1}{e} $$
Step-by-Step Solution
Verified Answer
The natural logarithm of \( \frac{1}{e} \) is approximately \(-1.00\).
1Step 1: Recall the Property of Logarithms
Understand that the natural logarithm of a number is the power to which the base of the natural logarithm (which is Euler's number \( e \)) must be raised to obtain that number.
2Step 2: Express the Number in Terms of e
Recognize that \( \frac{1}{e} \) can be rewritten as \( e^{-1} \). This makes it easier to calculate the natural logarithm because it directly involves the base \( e \).
3Step 3: Use Logarithmic Identity
Use the identity \( \ln(a^b) = b \cdot \ln(a) \) to find \( \ln(e^{-1}) \). Here, \( a = e \) and \( b = -1 \). Therefore, \( \ln(e^{-1}) = -1 \cdot \ln(e) \).
4Step 4: Compute the Logarithm of e
Since the natural logarithm of \( e \) is 1, it follows that \( \ln(e) = 1 \).
5Step 5: Calculate the Natural Logarithm
Substitute the value from Step 4 into the equation in Step 3: \( \ln(e^{-1}) = -1 \times 1 = -1 \).
6Step 6: Round to the Nearest Hundredth
Since \(-1\) is already a round number with two decimal places, the final result is \(-1.00\).
Key Concepts
Logarithmic IdentitiesEuler's NumberProperties of Logarithms
Logarithmic Identities
Logarithmic identities are powerful tools in mathematics that help us manipulate logarithmic expressions to simplify calculations and solve equations. One of the most common identities is the power rule of logarithms, which states that the logarithm of a number raised to a power is equal to the exponent times the logarithm of the base:
- \( \ln(a^b) = b \cdot \ln(a) \)
- \( \ln(a \cdot b) = \ln(a) + \ln(b) \)
- \( \ln\left(\frac{a}{b}\right) = \ln(a) - \ln(b) \)
Euler's Number
Euler's number, denoted by \( e \), is a fundamental constant in mathematics. It is approximately equal to 2.71828 and is the base of natural logarithms. The number \( e \) has important properties that are widely used in various fields such as calculus, complex analysis, and number theory.One of the defining characteristics of \( e \) is its natural growth properties. It arises naturally in the process of compounding interest continuously or when calculating limits that lead to exponential growth. For instance, when interest is compounded continuously, the formula \( A = P \cdot e^{rt} \) is used, where \( P \) is the principal amount, \( r \) is the rate, and \( t \) is time.In the realm of natural logarithms, \( e \) is significant because the natural logarithm is defined such that \( \ln(e) = 1 \). This property is crucial when working with exponential growth or decay problems, simplifying logarithmic computations dramatically. Euler's number also plays a key role in calculus, particularly when calculating derivatives and integrals of exponential functions.The importance of \( e \) cannot be overstated, as it serves as a cornerstone of higher-level mathematics. It provides a vital link between algebra, calculus, and natural growth processes in the real world.
Properties of Logarithms
Understanding the properties of logarithms is essential for solving logarithmic equations and simplifying expressions. These properties, which extend from the logarithmic identities, provide a framework for manipulating logarithmic expressions concisely.One vital property is the identity:
- \( \ln(e) = 1 \)
- \( \ln(e^x) = x \)
- \( \log_b(a) = \frac{\ln(a)}{\ln(b)} \)
Other exercises in this chapter
Problem 13
In \(3-14,\) find the common logarithm of each number to the nearest hundredth. $$ 100 $$
View solution Problem 13
In \(11-22,\) solve each equation for \(y\) in terms of \(x\) $$ x=8^{y} $$
View solution Problem 14
In \(3-14,\) solve each equation for the variable. Express each answer to the nearest hundredth. $$ 75-4^{b}=20 $$
View solution Problem 14
Solve each equation for the variable and check. \(3 \ln x+\ln 24=\ln 3\)
View solution