Problem 14
Question
(II) A sled is initially given a shove up a frictionless \(23.0^{\circ}\) incline. It reaches a maximum vertical height \(1.12 \mathrm{~m}\) higher than where it started. What was its initial speed?
Step-by-Step Solution
Verified Answer
The initial speed of the sled was approximately 4.684 m/s.
1Step 1: Understanding the problem
We need to find the initial speed of a sled given that it climbs a frictionless incline with an initial shove and reaches a maximum vertical height of 1.12 meters.
2Step 2: Utilizing Energy Conservation
According to the law of conservation of energy, the initial kinetic energy of the sled should equal the potential energy at the maximum height. The equation to express this is \( \frac{1}{2} mv^2 = mgh \), where \( m \) is mass, \( v \) is the initial velocity, \( g \) is the acceleration due to gravity (9.8 m/s²), and \( h \) is the height (1.12 m).
3Step 3: Cancel out mass and solve for velocity
Since mass \( m \) appears on both sides of the equation, it can be canceled out. We then solve for \( v \). The equation simplifies to \( \frac{1}{2} v^2 = gh \). Rearranging for \( v \), we get \( v = \sqrt{2gh} \).
4Step 4: Substitute known values
Substitute \( g = 9.8 \, \text{m/s}^2 \) and \( h = 1.12 \, \text{m} \) into the expression \( v = \sqrt{2gh} \) which results in \( v = \sqrt{2 \times 9.8 \times 1.12} \).
5Step 5: Calculation
Calculate \( v = \sqrt{2 \times 9.8 \times 1.12} \). This results in \( v = \sqrt{21.952} \approx 4.684 \text{ m/s} \).
Key Concepts
Kinetic EnergyPotential EnergyInclined Plane
Kinetic Energy
Kinetic energy is the energy possessed by an object due to its motion. It can be thought of as the energy that keeps things moving.
This type of energy depends on the mass of the object and its velocity. The formula to calculate kinetic energy is given by \( KE = \frac{1}{2} m v^2 \), where:
Consider a sled going uphill; the initial push gives it a velocity, endowing it with kinetic energy. This energy propels the sled up the incline.This is crucial because, on a frictionless incline, the sled needs enough kinetic energy to reach a given height or it might not make it.
This type of energy depends on the mass of the object and its velocity. The formula to calculate kinetic energy is given by \( KE = \frac{1}{2} m v^2 \), where:
- \( m \) is the mass of the object
- \( v \) is the velocity of the object
Consider a sled going uphill; the initial push gives it a velocity, endowing it with kinetic energy. This energy propels the sled up the incline.This is crucial because, on a frictionless incline, the sled needs enough kinetic energy to reach a given height or it might not make it.
Potential Energy
Potential energy is the stored energy in an object due to its position or state. In the context of an inclined plane, it’s the energy an object has when it is elevated.
The important equation for gravitational potential energy is \( PE = mgh \), where:
Thus, reaching a maximum vertical height means the sled's potential energy is at its peak, ready to be converted back into kinetic energy when descending or to do other work.
The important equation for gravitational potential energy is \( PE = mgh \), where:
- \( m \) is the mass of the object
- \( g \) is the acceleration due to gravity (approximately \(9.8 \, \text{m/s}^2\) on Earth)
- \( h \) is the height above the ground
Thus, reaching a maximum vertical height means the sled's potential energy is at its peak, ready to be converted back into kinetic energy when descending or to do other work.
Inclined Plane
An inclined plane is a flat surface tilted at an angle. It’s a simple machine that aids in moving objects to a different elevation.
Understanding inclined planes involves some geometry and physics principles. The plane allows a smoother conversion of energies.In scenarios involving conservation of energy, motion on inclined planes is especially insightful.
On a frictionless incline, like in our sled problem, energy transitions smoothly between kinetic and potential forms. The slope affects this transition. The angle of inclination, in this case, \(23^{\circ}\), plays a role in determining the height gained or the distance traveled. As the sled moves up the incline, its kinetic energy decreases while potential energy increases, until it stops momentarily before sliding back down.
Understanding inclined planes involves some geometry and physics principles. The plane allows a smoother conversion of energies.In scenarios involving conservation of energy, motion on inclined planes is especially insightful.
On a frictionless incline, like in our sled problem, energy transitions smoothly between kinetic and potential forms. The slope affects this transition. The angle of inclination, in this case, \(23^{\circ}\), plays a role in determining the height gained or the distance traveled. As the sled moves up the incline, its kinetic energy decreases while potential energy increases, until it stops momentarily before sliding back down.
Other exercises in this chapter
Problem 12
(I) Jane, looking for Tarzan, is running at top speed \((5.0 \mathrm{~m} / \mathrm{s})\) and grabs a vine hanging vertically from a tall tree in the jungle. How
View solution Problem 13
(II) In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy without the aid of a pole. With what minimum speed mu
View solution Problem 15
(1I) A 55 -kg bungee jumper leaps from a bridge. She is tied to a bungee cord that is 12 \(\mathrm{m}\) long when unstretched, and falls a total of 31 \(\mathrm
View solution Problem 16
(II) A 72 -kg trampoline artist jumps vertically upward from the top of a platform with a \(\begin{array}{llll}\text { speed of } & 4.5 \mathrm{~m} / \mathrm{s}
View solution