Problem 14

Question

If \(T_{2} / T_{3}\) in the expansion of \((a+b)^{n}\), and \(T_{3} /\) \(T_{4}\) in the expansion of \((a+b)^{n+3}\) are equal, then \(n=\) (a) 3 (b) 4 (c) 5 (d) 6

Step-by-Step Solution

Verified
Answer
Based on calculations, none of the options can be selected unless reevaluation is conducted.
1Step 1: Understanding Binomial Terms
For a binomial expansion, the general term in the expansion of (a+b)^n is given by the formula: \( T_k = \binom{n}{k-1} a^{n-k+1} b^{k-1} \). For example, \( T_2 = \binom{n}{1} a^{n-1} b \) and \( T_3 = \binom{n}{2} a^{n-2} b^2 \) for the expansion of \((a+b)^n\).
2Step 2: Set Up the Given Ratio for (a+b)^n
The given expression is \( \frac{T_2}{T_3}\). Using the terms derived in the previous step, we have:\[ \frac{T_2}{T_3} = \frac{\binom{n}{1} a^{n-1} b}{\binom{n}{2}a^{n-2}b^2} = \frac{n}{\frac{n(n-1)}{2}b} = \frac{2(n-1)}{n}. \]
3Step 3: Set Up the Given Ratio for (a+b)^{n+3}
Similarly, for the binomial expansion of \((a+b)^{n+3}\), derive \( T_3 \) and \( T_4 \): \[ \frac{T_3}{T_4} = \frac{\binom{n+3}{2} a^{n+1} b^2}{\binom{n+3}{3}a^n b^3} = \frac{\frac{(n+3)(n+2)}{2}a}{\frac{(n+3)(n+2)(n+1)}{6}b} = \frac{3}{n+1}. \]
4Step 4: Equate the Two Ratios
We know that \( \frac{T_2}{T_3} = \frac{T_3}{T_4} \), leading to the equation: \[ \frac{2(n-1)}{n} = \frac{3}{n+1} \]. Cross-multiply to get: \( 2(n-1)(n+1) = 3n \).
5Step 5: Solve for n
Expand and simplify the equation: \( 2(n^2 - 1) = 3n \). This gives: \( 2n^2 - 3n -2 = 0 \). Factor it as: \( (2n+1)(n-2) = 0 \). The solutions are \( n = -\frac{1}{2} \) and \( n = 2 \).
6Step 6: Choose the Appropriate Answer
Since \( n \) must be a positive integer (as it represents the power in the binomial expansion), only \( n = 2 \) is valid, but none of the given options match, an oversight should be noted. Hence select the closest, which infers back-calculations need checking or assuming presentation oversight.

Key Concepts

Binomial ExpansionBinomial CoefficientAlgebraic ExpressionsPolynomial Equations
Binomial Expansion
Binomial Expansion is a way to expand expressions that are raised to a power. It's an extension of using the distributive law and involves multiplying terms by one another repeatedly. The formula for expanding (a + b)^n is derived using the Binomial Theorem, which states: \[(a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\]This expansion results in a polynomial with terms like \(T_1, T_2, ... T_{n+1}\), each having its own characteristics based on arrangements of 'a' and 'b'. Understanding how to apply the expansion helps simplify complex algebraic expressions and solve various polynomial equations.Some key points about binomial expansion:
  • The number of terms in the expansion is \(n+1\).
  • Each term involves binomial coefficients \(\binom{n}{k}\), which are crucial in determining the contribution of each pair \(a^p b^q\).
  • Binomial expansion is helpful in approximating values, especially where direct computation is complex.
Learning binomial expansion can seem challenging, but practice with different values of n, including smaller powers, greatly enhances understanding.
Binomial Coefficient
The Binomial Coefficient appears in the binomial expansion and is represented by \(\binom{n}{k}\). It is a simple yet powerful concept that indicates the number of ways to choose k items from a total of n, capturing combinations and not permutations.Its mathematical formula is given by:\[\binom{n}{k} = \frac{n!}{k!(n-k)!}\]Here:
  • \(n!\) is the factorial of n, the product of all positive integers up to n.
  • \(k!\) is the factorial of k.
  • Binomial coefficients are symmetrical: \(\binom{n}{k} = \binom{n}{n-k}\).
  • Appears in Pascal's Triangle, a simple computation tool for finding coefficients.
Understanding these coefficients is vital as they depict how terms in the expansion scale, reflecting different possible combinations. In complex polynomials, these coefficients simplify calculations and illustrate how combinations of terms affect the power summation.
Algebraic Expressions
Algebraic Expressions are fundamental components of algebra, involving variables, constants, and arithmetic operations. They express general forms of equations or represent quantities using symbols.An algebraic expression might look like:\[3x^2 + 2y - 7\]Here:
  • "3x²" is called a term, where "3" is the coefficient and "x²" the variable part.
  • They can be constants like "-7" or more complex forms, using multiple operations.
  • Expressions might be polynomial (involving exponents) or simple linear transformations.
In macroscopic algebraic problems, converting real-life situations into algebraic expressions aids in solving them using mathematical rules and operations. This conversion is pivotal in both theoretical and applied mathematics.
Polynomial Equations
Polynomial Equations involve expressions containing variables and exponents. They represent complex curves and can be anything from straightforward lines to intricate graphs.The general form of a polynomial equation is:\[a_nx^n + a_{n-1}x^{n-1} + ... + a_1x + a_0 = 0\]Where:
  • Each \(a_i\) is a coefficient and \(x\) the variable.
  • These equations range from linear \(a_1x + a_0 = 0\) to more complex higher orders \(x^n\).
  • Solving involves finding values of x that make the equation true, known as "roots" or "solutions".
  • Different techniques such as factoring, graphing, and using the quadratic formula are employed for this purpose.
In mathematics, polynomial equations play a central role in various analysis methods, from physics to economics, helping understand and model relationships between components or entities.