Problem 14
Question
If \(f(x)=\sum_{n=0}^{\infty} a_{n} x^{n},\) where the coefficients in the expansion satisfy $$ \sum_{n=0}^{\infty} n(n+2) a_{n} x^{n}+\sum_{n=1}^{\infty}(n-3) a_{n-1} x^{n}=0 $$ determine \(f(x)\)
Step-by-Step Solution
Verified Answer
The function \(f(x)\) can be represented as:
$$
f(x) = a_0 \sum_{n=0}^{\infty} \frac{(-1)^n}{(2n)!} (3 * 7 * 11 \cdots (4n + 2)) x^n
$$
1Step 1: Rewriting the summation expressions to have a common index
Before dealing with the infinite series, let's rewrite the series with a common index. We will change the second summation to have the index starting from 0, so we can later combine the series.
For the second series, if we substitute \(n' = n - 1\), then \(x^{n'} = x^{n - 1}\) and \(n' + 3 = n\). So, we can rewrite the second series as:
$$
\sum_{n'=0}^{\infty}(n'+3) a_{n'} x^{n'+1}
$$
The given condition now becomes:
$$
\sum_{n=0}^{\infty} n(n+2) a_{n} x^{n}+\sum_{n'=0}^{\infty}(n'+3) a_{n'} x^{n'+1}=0
$$
2Step 2: Combining the two summations
Now, let's combine the above two summation expressions into a single summation. We also take into account the different exponents of \(x^n\).
$$
\sum_{n=0}^\infty [n(n+2)a_nx^n+(n+3)a_nx^{n+1}] = 0
$$
3Step 3: Deriving a recurrence relation between coefficients
Since the sum is zero, we want to find a recurrence relation for \(a_n\). Notice that the term inside the brackets needs to be equal to zero for all exponents \(n\):
$$
n(n+2)a_nx^n+(n+3)a_nx^{n+1} = 0, \quad \forall n
$$
Dividing by \(x^n\), we obtain:
$$
n(n+2)a_n + (n+3)a_nx = 0
$$
Now, isolate \(a_n\) in the above relation:
$$
a_n(x) = -\frac{(n+3)a_nx}{n(n+2)}
$$
4Step 4: Initial condition for the recurrence relation
To proceed, we need to find an initial condition for the recurrence relation. Look at the first term of the power series:
$$
a_0x^0 = a_0
$$
Now we substitute \(n=0\) in the recurrence relation we derived in step 3:
$$
a_0 = -\frac{3a_0x}{0\cdot2}
$$
However, this expression is indeterminate for \(n=0\). We need to look for another initial condition.
5Step 5: Determine a valid recurrence relation for a nonzero n
For \(n \neq 0\), our recurrence relation in step 3 is valid. In this case, we obtain:
$$
a_{n+1} = -\frac{(n+3)}{n(n+2)} a_n
$$
We can now use this recurrence relation to find successive coefficients \(a_n\).
6Step 6: Simplifying the recurrence relation
Using the valid recurrence relation derived in step 5, we can rewrite it as:
$$
a_{n+1} = -\frac{(n+3)}{(n)(n+2)} a_n
$$
We can now use this recurrence relation to find a(n) in terms of a(0):
$$
a_n = \frac{(-1)^n}{(2n)!} * (3 * 7 * 11 \cdots (4n + 2))a_0
$$
7Step 7: Expressing f(x) using simplified recurrence relation
Now, we can express the function \(f(x)\) using this coefficient formula:
$$
f(x) = a_0 + a_1x^1 + a_2x^2 + a_3x^3 + \cdots = a_0 \sum_{n=0}^{\infty} \frac{(-1)^n}{(2n)!} (3 * 7 * 11 \cdots (4n + 2)) x^n
$$
This is the final expression for \(f(x)\), given the initial condition on the coefficients.
Key Concepts
Recurrence RelationsInfinite SeriesCoefficients of Power SeriesSequence and Series Convergence
Recurrence Relations
Recurrence relations are mathematical expressions that relate the terms in a sequence or series to previous terms. Specifically, they are used to describe the relationship between consecutive coefficients in a power series. This is a crucial concept, especially when dealing with power series differential equations like the one in our exercise.
In the provided solution, the recurrence relation is used to define a connection between the coefficients of the power series. After establishing the starting point, or the initial condition, the rest of the coefficients can be methodically found using that relation. For instance, the solution shows that the coefficient of the \(n+1\)th term, \(a_{n+1}\), is expressed in terms of the preceding term \(a_n\), allowing for a systematic determination of all subsequent coefficients. Understanding and constructing such relationships is foundational for solving differential equations and analyzing their solutions.
In the provided solution, the recurrence relation is used to define a connection between the coefficients of the power series. After establishing the starting point, or the initial condition, the rest of the coefficients can be methodically found using that relation. For instance, the solution shows that the coefficient of the \(n+1\)th term, \(a_{n+1}\), is expressed in terms of the preceding term \(a_n\), allowing for a systematic determination of all subsequent coefficients. Understanding and constructing such relationships is foundational for solving differential equations and analyzing their solutions.
Infinite Series
An infinite series is a sum of a sequence of terms that, as the name suggests, goes on indefinitely. In the context of the original exercise, we consider the power series represented by an infinite series of terms like \(a_n x^n\). Such series are incredibly important in mathematics because they can represent functions as a sum of infinitely many terms, each involving powers of a variable. The exercise involves manipulating this infinite sum to satisfy a given condition.
When encountering an infinite series in problems, our concern is to find a pattern or a rule that permeates through the terms of the series, which often involves simplifying complex expressions and applying algebraic manipulations like factoring or combining like terms.
When encountering an infinite series in problems, our concern is to find a pattern or a rule that permeates through the terms of the series, which often involves simplifying complex expressions and applying algebraic manipulations like factoring or combining like terms.
Coefficients of Power Series
The coefficients of a power series are the constants that are multiplied by the variable terms raised to varying powers. In the power series \(\sum_{n=0}^{\infty} a_{n} x^{n}\), each \(a_{n}\) represents a coefficient at the corresponding index \(n\).
Determining the coefficients is essential when defining the power series solution to a differential equation. As demonstrated in the solution, these coefficients are found by employing a recurrence relation. The relationship among the coefficients is dictated by the structure of the differential equation, whether explicit or derived through manipulation. Thus, a clear understanding of how to find and use these coefficients is pivotal for students as it leads directly to the determination of the series representation of the solution to the differential equation.
Determining the coefficients is essential when defining the power series solution to a differential equation. As demonstrated in the solution, these coefficients are found by employing a recurrence relation. The relationship among the coefficients is dictated by the structure of the differential equation, whether explicit or derived through manipulation. Thus, a clear understanding of how to find and use these coefficients is pivotal for students as it leads directly to the determination of the series representation of the solution to the differential equation.
Sequence and Series Convergence
Sequence and series convergence is about understanding which conditions a sequence or series must fulfill to approach a finite limit. For an infinite series to be useful in applications, particularly in representing functions through power series, it's crucial to determine whether the series converges, that is, if the sum of its infinitely many terms stays bounded and approaches a specific value.
In the context of our power series differential equation, convergence would ensure that the function represented by the series \(f(x)\) is meaningful for certain values of \(x\). To assess convergence, students must apply various tests like the ratio test, the root test, or other criteria. Ensuring convergence is fundamental since it justifies the validity of the function defined by the power series for at least some interval around the point of expansion.
In the context of our power series differential equation, convergence would ensure that the function represented by the series \(f(x)\) is meaningful for certain values of \(x\). To assess convergence, students must apply various tests like the ratio test, the root test, or other criteria. Ensuring convergence is fundamental since it justifies the validity of the function defined by the power series for at least some interval around the point of expansion.
Other exercises in this chapter
Problem 14
Show that the indicial equation of the given differential equation has distinct roots that do not differ by an integer and find two linearly independent Frobeni
View solution Problem 14
Determine terms up to and including \(x^{5}\) in two linearly independent power series solutions of the given differential equation. State the radius of converg
View solution Problem 15
Consider the differential equation $$\left(x^{2}-1\right) y^{\prime \prime}+[1-(a+b)] x y^{\prime}+a b y=0, \quad (11.7.9)$$ where \(a\) and \(b\) are constants
View solution Problem 15
Determine two linearly independent solutions to the given differential equation on \((0, \infty)\) $$x^{2} y^{\prime \prime}+x(1-x) y^{\prime}-y=0$$
View solution