Problem 14
Question
If \(f(x)=k x^{3}-9 x^{2}+9 x+3\) is monotonically increasing in each interval, then (a) \(k<3\) (b) \(k \leq 3\) (c) \(k>3\) (d) None of these
Step-by-Step Solution
Verified Answer
The correct option is (c) \( k>3 \).
1Step 1: Understanding Monotonic Function
For a function to be monotonically increasing, its derivative must be non-negative for all values in its domain. This means we need to find the derivative and set conditions for it to be greater than or equal to zero.
2Step 2: Find the Derivative
Derive the function \( f(x) = kx^3 - 9x^2 + 9x + 3 \). The derivative is \( f'(x) = 3kx^2 - 18x + 9 \).
3Step 3: Set the Derivative as Non-negative
To ensure the function is monotonically increasing, set \( f'(x) \geq 0 \). Therefore, \( 3kx^2 - 18x + 9 \geq 0 \).
4Step 4: Simplify the Inequality
Simplify the inequality \( 3kx^2 - 18x + 9 \geq 0 \) by dividing the entire inequality by 3: \( kx^2 - 6x + 3 \geq 0 \).
5Step 5: Analyzing the Quadratic Inequality
For the quadratic \( kx^2 - 6x + 3 \geq 0 \) to be positive for all \( x \), the determinant (discriminant) must be less than or equal to zero.
6Step 6: Calculating the Discriminant
The discriminant of the quadratic equation \( kx^2 - 6x + 3 \) is \( (-6)^2 - 4(k)(3) \), leading to \( 36 - 12k \).
7Step 7: Condition for Non-positive Discriminant
To ensure the quadratic is non-positive, set \( 36 - 12k \leq 0 \).
8Step 8: Solve the Discriminant Inequality
Solving \( 36 - 12k \leq 0 \) provides \( k \geq 3 \).
9Step 9: Interpret the Solution
The solution \( k \geq 3 \) means the function can never be monotonically increasing for k less than 3. Hence, only \( k > 3 \) makes hold for all \( x \).
10Step 10: Conclusion
Therefore, for the function to be monotonically increasing in its intervals, the correct condition for \( k \) is \( k > 3 \).
Key Concepts
Derivative of a functionQuadratic discriminantInequality solving
Derivative of a function
The derivative of a function is a measure of how the function's output changes with respect to a change in its input. This is a fundamental concept in calculus and is essential for understanding the behavior of functions.
The derivative can be viewed as the slope of the tangent line to the graph of the function. It gives us the rate at which the function is increasing or decreasing at any given point.
For a function like \( f(x) = kx^3 - 9x^2 + 9x + 3 \), calculating the derivative involves applying standard derivative rules.
The derivative can be viewed as the slope of the tangent line to the graph of the function. It gives us the rate at which the function is increasing or decreasing at any given point.
For a function like \( f(x) = kx^3 - 9x^2 + 9x + 3 \), calculating the derivative involves applying standard derivative rules.
- The power rule says that the derivative of \( x^n \) is \( nx^{n-1} \).
- Combine like terms accordingly, which results in \( f'(x) = 3kx^2 - 18x + 9 \).
Quadratic discriminant
The discriminant is a part of the quadratic formula and plays a critical role in determining the nature of the roots of a quadratic equation. If the quadratic equation is written in the form \( ax^2 + bx + c \), the discriminant is given by \( b^2 - 4ac \).
The discriminant helps us understand:
The discriminant helps us understand:
- If the discriminant is positive, the quadratic has two distinct real roots.
- If it is zero, the quadratic has exactly one real root (a repeated root).
- If negative, the quadratic has no real roots (the roots are complex).
Inequality solving
Inequality solving involves finding ranges of values for which expressions satisfy a certain condition. In our problem, we worked with the inequality derived from the derivative of the function.
Upon deriving the inequality \( kx^2 - 6x + 3 \geq 0 \), we simplify this by first analyzing its discriminant.
Solving \( 36 - 12k \leq 0 \) gives:
This technique highlights the process of solving quadratic inequalities by leveraging their components and understanding their behavior.
Upon deriving the inequality \( kx^2 - 6x + 3 \geq 0 \), we simplify this by first analyzing its discriminant.
Solving \( 36 - 12k \leq 0 \) gives:
- Rearrange to find \( 36 \leq 12k \).
- Divide by 12 to isolate \( k \), resulting in \( k \geq 3 \).
This technique highlights the process of solving quadratic inequalities by leveraging their components and understanding their behavior.
Other exercises in this chapter
Problem 12
The function \(f(x)=\cos x-2 a x\) is monotonically decreasing for [RPET-1987; MPPET-2002] (a) \(a\frac{1}{2}\) (c) \(a2\)
View solution Problem 13
The length of a longest interval in which the function \(3 \sin x-4 \sin ^{3} x\) is increasing is IIIT (Screening-2002] (a) \(\pi / 3\) (b) \(\pi / 2\) (c) \(3
View solution Problem 15
The function \(x^{x}\) is increasing, when [MPPET-2003] (a) \(x>1 / e\) (b) \(x
View solution Problem 16
The function \(f(x)=\tan ^{-1}(\sin x+\cos x)\) is an increasing function in [AIEEE-2007] (a) \((\pi / 4, \pi / 2)\) (b) \((-\pi / 2, \pi / 4)\) (c) \((0, \pi /
View solution