Problem 14
Question
}(I, G)\( be the set of f… # Let \)I\( be a set and \)G\( be an abelian group, and consider the group \)\operatorname{Map}(I, G)\( of functions \)f: I \rightarrow G .\( Let Map \)^{\\#}(I, G)\( be the set of functions \)f \in \operatorname{Map}(I, G)\( such that \)f(i) \neq 0_{G}\( for at most finitely many \)i \in I\(. Show that \)\operatorname{Map}^{\\#}(I, G)\( is a subgroup of \)\operatorname{Map}(I, G)$
Step-by-Step Solution
Verified Answer
Question: Prove that the subset of functions $\operatorname{Map}^{\#}(I, G)$ is a subgroup of the group $\operatorname{Map}(I, G)$.
Solution: To prove that $\operatorname{Map}^{\#}(I, G)$ is a subgroup of $\operatorname{Map}(I, G)$, we showed:
1. The identity element of $\operatorname{Map}(I, G)$ is in $\operatorname{Map}^{\#}(I, G)$.
2. If a function is in $\operatorname{Map}^{\#}(I, G)$, its inverse is also in $\operatorname{Map}^{\#}(I, G)$.
3. The product of any two functions in $\operatorname{Map}^{\#}(I, G)$ is also in $\operatorname{Map}^{\#}(I, G)$.
Since all three criteria were satisfied, we concluded that $\operatorname{Map}^{\#}(I, G)$ is a subgroup of $\operatorname{Map}(I, G)$.
1Step 1: Identity element
The identity element of \(\operatorname{Map}(I, G)\) is the constant map \(f_{id}(i) = 0_{G}\) for all \(i \in I\). This function satisfies the condition of \(\operatorname{Map}^{\\#}(I, G)\) since it's non-zero for no elements in \(I\). Therefore, \(f_{id} \in \operatorname{Map}^{\\#}(I, G)\).
2Step 2: Inverse element
Let \(f \in \operatorname{Map}^{\\#}(I, G)\). We want to show that its inverse is also in \(\operatorname{Map}^{\\#}(I, G)\). The inverse of \(f\) is given by \(f^{-1}(i) = -f(i)\). Since \(f(i) \neq 0_{G}\) for only finitely many \(i\), its inverse, \(f^{-1}(i)\), will also be non-zero for the same finite set of elements in \(I\). Hence, \(f^{-1} \in \operatorname{Map}^{\\#}(I, G)\).
3Step 3: Closed property
We now need to prove that the product of any two functions in \(\operatorname{Map}^{\\#}(I, G)\) is also in \(\operatorname{Map}^{\\#}(I, G)\). Suppose \(f, g \in \operatorname{Map}^{\\#}(I, G)\). Let \(h: I \rightarrow G\) be the product of \(f\) and \(g\), such that \(h(i) = f(i) + g(i)\).
Since \(f(i) \neq 0_{G}\) and \(g(i) \neq 0_{G}\) for only finitely many \(i\), it follows that \(h(i) \neq 0_{G}\) for the union of the two finite sets of elements where \(f(i)\) and \(g(i)\) are non-zero. Since the union of two finite sets is also finite, \(h(i) \neq 0_{G}\) for only finitely many \(i\). Therefore, \(h \in \operatorname{Map}^{\\#}(I, G)\).
Since we have proven all three criteria (identity element, inverse element, and closed property), we can conclude that \(\operatorname{Map}^{\\#}(I, G)\) is indeed a subgroup of \(\operatorname{Map}(I, G)\).
Key Concepts
Abelian GroupSubgroupMap FunctionIdentity Element
Abelian Group
An Abelian group is a special kind of structure in group theory where the operation is commutative. This means that no matter in which order you apply the operation between two elements, the result will be the same. In more formal terms, if you have two elements \(a\) and \(b\) in an Abelian group \(G\), then \(a + b = b + a\).
- Commutativity: The defining property of Abelian groups, as discussed above, ensures ease in the calculation and manipulation of elements.
- Examples: Common examples of Abelian groups include the integers \(\mathbb{Z}\) under addition, and the non-zero real numbers \(\mathbb{R} \setminus \{0\}\) under multiplication.
Subgroup
A subgroup is simply a smaller group that lives inside a bigger group and follows the same operation rules. Formally, if \(H\) is a subgroup of \(G\), every element of \(H\) is also an element of \(G\). Additionally, \(H\) must be closed under the operations of the group and contain the identity element of \(G\).
- Identity: The subgroup contains the identity element of its parent group \(G\).
- Inverse: Every element in the subgroup has an inverse, which is also within the subgroup.
- Closure: If you take two elements from \(H\) and combine them using the group operation, you will end up with another element that is still in \(H\).
Map Function
A map function in the context of group theory is essentially a function that carries elements from one set to another, respecting the group's operations. Here, we consider functions from a set \(I\) to an Abelian group \(G\), which is denoted by \(\operatorname{Map}(I, G)\).
- Functionality: Each element of \(I\) is mapped to an element of \(G\), possibly the same or a different one.
- Applications: Functions in this context are useful for abstractly representing transformations and symmetries within a given mathematical structure.
Identity Element
In any group, the identity element holds the central position, as it is the neutral element in the operation of the group. In an Abelian group \(G\), the identity element is denoted by \(0_{G}\). It has the following key properties:
- Neutral Behavior: When the identity element is combined with any other element in the group, it leaves that element unchanged. Mathematically, for any \(g\) in \(G\), \(g + 0_{G} = g\).
- Existence: Every group, by definition, includes an identity element, which is unique to that group.
Other exercises in this chapter
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