Problem 14
Question
For Problems 9-50, simplify each rational expression. \(\frac{-14 x^{2} y^{3}}{63 x y^{2}}\)
Step-by-Step Solution
Verified Answer
The simplified expression is \(\frac{-2xy}{9}\).
1Step 1: Identify Common Factors
The first step in simplifying the rational expression \(\frac{-14x^2y^3}{63xy^2}\) is to identify any common factors in the numerator and the denominator. Observe that both terms can be factored into constants and variables: - Numerator: \(-14x^2y^3\) can be written as \(-1 \cdot 14 \cdot x^2 \cdot y^3\).- Denominator: \(63xy^2\) can be written as \(63 \cdot x \cdot y^2\).
2Step 2: Factor the Constants
Factor the constants in both the numerator and the denominator:- Numerator: \(-14\) can be factored as \(-1 \times 2 \times 7\).- Denominator: \(63\) can be factored as \(9 \times 7\) or \(3 \times 3 \times 7\). The number 7 is common in both, and can be cancelled out.
3Step 3: Cancel Common Factors
Identify the common factors to cancel out from both the numerator and the denominator:- **Common Constants:** Both 14 from the numerator and 63 from the denominator have a common factor of 7.- **Variables:** 1. For \(x\): Cancel one \(x\) from the numerator and one \(x\) from the denominator as both contain \(x\). 2. For \(y\): Cancel \(y^2\) from the denominator with \(y^2\) in the numerator, leaving \(y\) in the numerator.So, cancel \(7, x\), and \(y^2\) from the originally given expression.
4Step 4: Simplify the Expression
After canceling out the common factors:- You're left with \(-2x^1y^{1}\) in the numerator and \(9\) in the denominator.Hence, the simplified expression is \(\frac{-2xy}{9}\).
Key Concepts
Understanding Common FactorsThe Art of FactoringCanceling Terms EffectivelyFinal Simplification Steps
Understanding Common Factors
When simplifying rational expressions, a crucial step involves identifying common factors in both the numerator and the denominator. A common factor is any factor that can divide both terms in the fraction without a remainder. To illustrate, let's look at our given expression: \[\frac{-14x^2y^3}{63xy^2}\] Here, both the numerator and the denominator can be broken down into
- Numerator: -1 \cdot 14 \cdot x^2 \cdot y^3
- Denominator: 63 \cdot x \cdot y^2
The Art of Factoring
Factoring is a powerful algebraic technique used to break down numbers or expressions into their simpler parts—called factors. This simplification is vital in making expressions easier to work with. For our specific expression: \[\frac{-14x^2y^3}{63xy^2}\] Let's factor each part:
- Numerator: \(-14\) is \(-1 \times 2 \times 7\). For variables,\( x^2 \) is \( x \times x \) and \( y^3 \) is \( y \times y \times y \).
- Denominator: 63 can be factored as \( 3 \times 3 \times 7 \). Variables \( x \) and \( y^2 \) are straightforward as \( x \) and \( y \times y \).
Canceling Terms Effectively
Once you've identified the common factors and factored both the numerator and the denominator, the next step is canceling these factors. Canceling refers to the process of removing these common factors from both parts of the fraction, thereby simplifying the expression. For example, in our given expression: \[\frac{-14x^2y^3}{63xy^2}\] The factors that we can cancel include:
- The number 7 from both 14 and 63.
- One instance of \( x \) from both \( x^2\) and \( x \).
- Two instances of \( y \) (i.e., \( y^2\)) from both \( y^3 \) and \( y^2 \).
Final Simplification Steps
Simplification is the process of making an algebraic expression as easy to read and as straightforward as possible. After factoring and canceling common terms, the final expression should be as reduced as it can get. Our result from the previous section was: \[\frac{-2xy}{9}\] In this expression, all possible simplifications have been made. Let's check:
- All common factors have been canceled correctly.
- No whole numbers or variables are shared between numerator and denominator.
- Expression is reduced to its simplest form.
Other exercises in this chapter
Problem 14
Add or subtract the rational expressions as indicated. Be sure to express your answers in simplest form. $$ \frac{3 x}{2 x+1}-\frac{5}{2 x+1} $$
View solution Problem 14
For Problems 13-50, perform the indicated operations involving rational expressions. Express final answers in simplest form. \(\frac{-14 x y^{4}}{18 y^{2}} \cdo
View solution Problem 15
Solve each equation. $$ \frac{2 x}{x+3}-\frac{3}{x-6}=\frac{29}{x^{2}-3 x-18} $$
View solution Problem 15
For Problems \(1-44\), solve each equation. $$ n+\frac{1}{n}=\frac{17}{4} $$
View solution