Problem 14
Question
Find the quotient \(\frac{z_{1}}{z_{2}}\) and express it in rectangular form. $$z_{1}=4\left(\cos 280^{\circ}+i \sin 280^{\circ}\right) \text { and } z_{2}=4\left(\cos 55^{\circ}+i \sin 55^{\circ}\right)$$
Step-by-Step Solution
Verified Answer
The quotient is \(-\frac{\sqrt{2}}{2} - i \frac{\sqrt{2}}{2}\).
1Step 1: Identify Given Complex Numbers
We have two complex numbers in trigonometric form: 1. \( z_1 = 4(\cos 280^{\circ} + i \sin 280^{\circ}) \)2. \( z_2 = 4(\cos 55^{\circ} + i \sin 55^{\circ}) \)
2Step 2: Apply the Division Formula for Complex Numbers in Polar Form
The quotient \( \frac{z_1}{z_2} \) in polar form is given by:\[ \frac{z_1}{z_2} = \frac{r_1}{r_2} \left( \cos(\theta_1 - \theta_2) + i \sin(\theta_1 - \theta_2) \right) \]For this problem:\[ \frac{z_1}{z_2} = \frac{4}{4} \left( \cos(280^{\circ} - 55^{\circ}) + i \sin(280^{\circ} - 55^{\circ}) \right) \]
3Step 3: Simplify the Expression
Since \( r_1 = r_2 = 4 \), the magnitudes cancel out, leaving:\[ z = \cos(225^{\circ}) + i \sin(225^{\circ}) \]
4Step 4: Convert from Polar to Rectangular Form
To express the result in rectangular form, convert \( \cos(225^{\circ}) \) and \( \sin(225^{\circ}) \) using known trigonometric values:\[ \cos(225^{\circ}) = -\frac{\sqrt{2}}{2}, \quad \sin(225^{\circ}) = -\frac{\sqrt{2}}{2} \]Thus, the rectangular form is:\[ z = -\frac{\sqrt{2}}{2} - i \frac{\sqrt{2}}{2} \]
5Step 5: Final Answer
The quotient \( \frac{z_1}{z_2} \) in rectangular form is:\[ -\frac{\sqrt{2}}{2} - i \frac{\sqrt{2}}{2} \]
Key Concepts
Rectangular FormPolar FormTrigonometric Form
Rectangular Form
Complex numbers can be expressed in several forms, one of which is the rectangular form. This is the standard way we usually see complex numbers written, as they consist of a real part and an imaginary part. For example, consider a complex number written as \( a + bi \), where:
This form is particularly useful because it directly aligns with how we often interpret points or vectors in a two-dimensional plane. It shows both horizontal and vertical changes clearly. Understanding and being able to convert complex numbers into their rectangular form is crucial because it makes them easier to visualize and manipulate, especially when adding or subtracting complex numbers.
- \( a \) is the real part.
- \( bi \) is the imaginary part.
This form is particularly useful because it directly aligns with how we often interpret points or vectors in a two-dimensional plane. It shows both horizontal and vertical changes clearly. Understanding and being able to convert complex numbers into their rectangular form is crucial because it makes them easier to visualize and manipulate, especially when adding or subtracting complex numbers.
Polar Form
The polar form of a complex number is used extensively in mathematics because of its ability to simplify multiplication, division, and the taking of powers and roots of complex numbers. In this form, a complex number is represented as \( r(\cos \theta + i \sin \theta) \), where:
When dividing complex numbers in polar form, as done in the solution, the magnitudes are divided, and the angles are subtracted: \[ \frac{z_1}{z_2} = \frac{r_1}{r_2} \left( \cos(\theta_1 - \theta_2) + i \sin(\theta_1 - \theta_2) \right) \]. Here, since the magnitudes \( r_1 \) and \( r_2 \) are equal, they cancel out, and we mainly focus on the result of the angle subtraction. This simplification is one of the primary advantages of using polar form.
- \( r \) is the magnitude (or absolute value) of the complex number.
- \( \theta \) is the angle, known as the argument, measured from the positive x-axis to the line segment representing the complex number.
When dividing complex numbers in polar form, as done in the solution, the magnitudes are divided, and the angles are subtracted: \[ \frac{z_1}{z_2} = \frac{r_1}{r_2} \left( \cos(\theta_1 - \theta_2) + i \sin(\theta_1 - \theta_2) \right) \]. Here, since the magnitudes \( r_1 \) and \( r_2 \) are equal, they cancel out, and we mainly focus on the result of the angle subtraction. This simplification is one of the primary advantages of using polar form.
Trigonometric Form
Trigonometric form, often synonymous with polar form, is a way of expressing complex numbers to emphasize their real and imaginary components through trigonometric functions. In this form, a complex number \( z \) is expressed as: \[ z = r (\cos \theta + i \sin \theta) \] where:
For instance, in the division of two numbers \( z_1 \) and \( z_2 \) given in trigonometric form, the concept of subtracting angles (\( \theta_1 - \theta_2 \)) simplifies the calculation, as seen in the exercise. Furthermore, understanding these fundamentals supports converting them back into forms that fit contexts where combinations are easier or more consistent to work with, like the rectangular form for addition/subtraction.
- \( r \) indicates the modulus, which is the distance from the origin to the point \( z \) in the complex plane.
- \( \theta \) represents the angle (or argument) formed with the positive x-axis.
For instance, in the division of two numbers \( z_1 \) and \( z_2 \) given in trigonometric form, the concept of subtracting angles (\( \theta_1 - \theta_2 \)) simplifies the calculation, as seen in the exercise. Furthermore, understanding these fundamentals supports converting them back into forms that fit contexts where combinations are easier or more consistent to work with, like the rectangular form for addition/subtraction.
Other exercises in this chapter
Problem 14
Find the angle (round to the nearest degree) between each pair of vectors. $$\langle 2,-4\rangle \text { and }\langle 4,-1\rangle$$
View solution Problem 14
Convert each point to exact polar coordinates. Assume that \(0 \leq \theta
View solution Problem 14
Express each complex number in polar form. $$\sqrt{5}-\sqrt{5} i$$
View solution Problem 14
Find the magnitude and direction angle of the given vector. $$\mathbf{u}=\langle 0,7\rangle$$
View solution