Problem 14
Question
Find the exact value of the expression whenever It is defined. (a) \(\sin \left(\tan ^{-1} \sqrt{3}\right)\) (b) \(\cos \left(\sin ^{-1} 1\right)\) (c) \(\tan \left(\cos ^{-1} 0\right)\)
Step-by-Step Solution
Verified Answer
(a) \( \frac{\sqrt{3}}{2} \), (b) 0, (c) undefined.
1Step 1: Understand the Inverse Function
To find the exact values of these expressions, we need to use the properties of inverse trigonometric functions. Each expression involves substituting an inverse trigonometric value into a trigonometric function.
2Step 2(a): Simplify \( \sin( \tan^{-1} \sqrt{3}) \)
We begin by setting \( \theta = \tan^{-1} \sqrt{3} \). This means \( \tan \theta = \sqrt{3} \). This matches the known value \( \tan(\frac{\pi}{3}) = \sqrt{3} \), indicating \( \theta = \frac{\pi}{3} \). Use the identity \( \sin(\tan^{-1}(x)) = \frac{x}{\sqrt{1+x^2}} \). Thus, \( \sin(\tan^{-1} \sqrt{3}) = \frac{\sqrt{3}}{2} \).
3Step 2(b): Simplify \( \cos(\sin^{-1} 1) \)
Set \( \theta = \sin^{-1} 1 \). This implies \( \sin \theta = 1 \), which only happens when \( \theta = \frac{\pi}{2} \). Hence, \( \cos(\sin^{-1} 1) = \cos(\frac{\pi}{2}) = 0 \).
4Step 2(c): Simplify \( \tan(\cos^{-1} 0) \)
Set \( \theta = \cos^{-1} 0 \). This implies \( \cos \theta = 0 \), occurring when \( \theta = \frac{\pi}{2} \) or \( \theta = \frac{3\pi}{2} \). Since \( \cos^{-1} \) is confined to \([0, \pi]\), \( \theta = \frac{\pi}{2} \). Therefore, \( \tan(\cos^{-1} 0) = \tan(\frac{\pi}{2}) \), which is undefined as it involves division by zero.
Key Concepts
Trigonometric IdentitiesExact Values of Trigonometric FunctionsProperties of Inverse Functions
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that are true for all values of the occurring variables for which both sides of the equation are defined. These identities are extremely useful when simplifying expressions and proving the equality of two sides of an equation.
Some of the fundamental trigonometric identities include:
Some of the fundamental trigonometric identities include:
- Pythagorean identities, such as \( \sin^2 \theta + \cos^2 \theta = 1 \).
- Quotient identities like \( \tan \theta = \frac{\sin \theta}{\cos \theta} \).
- Reciprocal identities, exemplified by \( \csc \theta = \frac{1}{\sin \theta} \).
Exact Values of Trigonometric Functions
Exact values of trigonometric functions involve finding the precise trigonometric ratios for specific angles. Instead of using a calculator for approximate values, we rely on known values and identities to determine the exact ratios.
Some common angles with known exact trigonometric values are \( 0, \frac{\pi}{6}, \frac{\pi}{4}, \frac{\pi}{3}, \frac{\pi}{2} \, \text{and others} \). For example:
Grasping these exact values is crucial for students to tackle problems without relying on numerical approximation software.
Some common angles with known exact trigonometric values are \( 0, \frac{\pi}{6}, \frac{\pi}{4}, \frac{\pi}{3}, \frac{\pi}{2} \, \text{and others} \). For example:
- \( \sin(\frac{\pi}{3}) = \frac{\sqrt{3}}{2} \)
- \( \cos(\frac{\pi}{3}) = \frac{1}{2} \)
- \( \tan(\frac{\pi}{3}) = \sqrt{3} \)
Grasping these exact values is crucial for students to tackle problems without relying on numerical approximation software.
Properties of Inverse Functions
Inverse functions essentially reverse the action of the original function. For trigonometric functions, the inverse functions are \( \sin^{-1}, \cos^{-1}, \tan^{-1} \), and they return an angle whose trigonometric function equals the given value.
These inverse trigonometric functions have specific ranges to ensure they are functions, meaning each input results in one output.
These inverse trigonometric functions have specific ranges to ensure they are functions, meaning each input results in one output.
- The range of \( \sin^{-1} \) is \([-\frac{\pi}{2}, \frac{\pi}{2}]\).
- For \( \cos^{-1} \) it is \([0, \pi]\).
- For \( \tan^{-1} \), it's \((-\frac{\pi}{2}, \frac{\pi}{2})\).
Other exercises in this chapter
Problem 13
Verify the identity. \(4 \sin \frac{x}{2} \cos \frac{x}{2}=2 \sin x\)
View solution Problem 13
Find all solutions of the equation. $$\sqrt{3} \tan \frac{1}{3} t=1$$
View solution Problem 14
Express as a product. $$\cos \theta-\cos 5 \theta$$
View solution Problem 14
Verify the Identity. $$\cos ^{4} 2 \theta+\sin ^{2} 2 \theta=\cos ^{2} 2 \theta+\sin ^{4} 2 \theta$$
View solution