Problem 14
Question
find the distance between each pair of points. If necessary, round answers to two decimals places. $$ (0,-\sqrt{2}) \text { and }(\sqrt{7}, 0) $$
Step-by-Step Solution
Verified Answer
So, the distance between points (0,-\sqrt{2}) and (\sqrt{7}, 0) is 3.
1Step 1 - Identify the coordinates of both points
Here are our two points:Point 1 = (0, -\sqrt{2}) = (x_1, y_1)Point 2 = (\sqrt{7}, 0) = (x_2, y_2)
2Step 2 - Plugging the coordinates into the distance formula
Substitute the coordinates into the formula. Follow the order (Point 2 - Point 1) for both x and y to avoid negative square roots. That gives us: d = \sqrt{{(\sqrt{7} - 0)^2 + (0 - (-\sqrt{2}))^2}}
3Step 3 - Simplify the terms within the square root
Simplify the terms inside the square root. That gives us: d = \sqrt{{7 - 0^2 + 0 - (\sqrt{2})^2}}
4Step 4 - Simplify further and Calculate the square root
d = \sqrt{{7 - 0 + 2}} = \sqrt{9}. Now, calculate the square root of 9, which is 3.
Key Concepts
Pythagorean theoremCoordinate systemRadicals
Pythagorean theorem
The Pythagorean theorem is a fundamental principle in geometry that relates to the sides of a right triangle. It states that in any right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. In mathematical terms, it is expressed as:\[ c^2 = a^2 + b^2 \]where \( c \) is the hypotenuse, and \( a \) and \( b \) are the other two sides. This theorem is not just limited to triangles on paper, but also very useful in a coordinate plane, where it helps find distances between points.When you have two points in a coordinate system, you can imagine a right triangle between them. The line connecting the points on the coordinate plane is the hypotenuse of the triangle. By applying the Pythagorean theorem, we can find the length of this line, or the distance between the two points.
Coordinate system
The coordinate system is a way of using numbers to represent points in space. In its simplest form, a coordinate plane is made up of two perpendicular lines: the x-axis (horizontal) and the y-axis (vertical). These axes divide the plane into four quadrants. Points are expressed as pairs of numbers (\(x, y\)), known as coordinates.
- The first number in the pair, \(x\), tells you how far to move right (positive) or left (negative) from the origin point (0,0).
- The second number, \(y\), tells you how far to move up (positive) or down (negative).
Radicals
Radicals involve root operations, such as square roots, which simplify an expression under a radical sign. A square root, for example, is written as \(\sqrt{x}\) and represents the number that multiplies by itself to create \(x\). Radicals are crucial when dealing with the distance formula because we often end up needing to simplify expressions that include square roots.When working with radicals, it's key to remember some fundamental arithmetic rules which can make simplification easier:
- Simplifying \(\sqrt{x^2}\) gives \(x\).
- To add or subtract radicals, they must be like terms (have the same radicand).
Other exercises in this chapter
Problem 13
In Exercises \(13-18\), find the average rate of change of the function from \(x_{1}\) to \(x_{2}\). \(f(x)=3 x\) from \(x_{1}=0\) to \(x_{2}=5\)
View solution Problem 13
Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Slope \(=6,\) passing through \((-2,5)\)
View solution Problem 14
The functions in Exercises \(11-28\) are all one-to-one. For each function, a. Find an equation for \(f^{-1}(x),\) the inverse function. b. Verify that your equ
View solution Problem 14
Find the domain of each function. $$h(x)=\frac{5}{\frac{4}{x}-1}$$
View solution