Problem 14
Question
Find each product and write the result in standard form. $$ (8-4 i)(-3+9 i) $$
Step-by-Step Solution
Verified Answer
The product of \((8-4i)\) and \((-3+9i)\) in standard form is \(12 + 84i\).
1Step 1: Distribute the first set of terms
Multiply each term in the first complex number by each term in the second complex number: \((8 * -3) + (8 * 9i) + (-4i * -3) + (-4i * 9i)\)
2Step 2: Perform the multiplication
Perform the multiplication for each term: \(-24 + 72i + 12i - 36i^2\)
3Step 3: Simplify
As \(i^2\) is equals to -1, replace \(i^2\) with -1 and combine like terms: \(-24 + 72i + 12i + 36 = 12 + 84i\) which is the result in standard form.
Key Concepts
Multiplication of Complex NumbersStandard Form of Complex NumbersDistributive Property
Multiplication of Complex Numbers
Multiplying complex numbers may seem like a complex task - pun intended - but it's quite like multiplying binomials. The key here is to use the distributive property, which allows you to break down the multiplication into manageable steps. This approach is often referred to as the "FOIL method" when multiplying two binomials, where each letter stands for First, Outside, Inside, and Last, representing the pairs of terms you'll multiply.
- First: Multiply the first terms from each complex number.
- Outside: Multiply the outer terms from each complex number.
- Inside: Multiply the inside terms.
- Last: Multiply the last terms.
- First: \(8 \times -3 = -24\)
- Outside: \(8 \times 9i = 72i\)
- Inside: \(-4i \times -3 = 12i\)
- Last: \(-4i \times 9i = -36i^2\)
Standard Form of Complex Numbers
A complex number is usually written in the form \(a + bi\), where \(a\) and \(b\) are real numbers. The term \(a\) represents the real part, while \(bi\) contains the imaginary part, with \(i\) being the imaginary unit \(i = \sqrt{-1}\). Writing complex numbers in this standard form makes them easier to read and manipulate in mathematical operations.
In our example, after performing the multiplication, we obtained: \[-24 + 72i + 12i - 36i^2\]The term \(-36i^2\) simplifies because \(i^2 = -1\), so it becomes \(36\).After combining like terms, which are the real numbers and the imaginary coefficients, you should get \(12 + 84i\), which is the standard form of the result. This form allows you to understand clearly the real and imaginary contributions to the number, making it practical for further calculations.
In our example, after performing the multiplication, we obtained: \[-24 + 72i + 12i - 36i^2\]The term \(-36i^2\) simplifies because \(i^2 = -1\), so it becomes \(36\).After combining like terms, which are the real numbers and the imaginary coefficients, you should get \(12 + 84i\), which is the standard form of the result. This form allows you to understand clearly the real and imaginary contributions to the number, making it practical for further calculations.
Distributive Property
The distributive property is a fundamental concept in algebra that makes multiplication over addition more straightforward. It states simply that:For any real numbers \(a, b, c\): \[a(b + c) = ab + ac\]This property is vital in simplifying expressions and is extensively used in multiplying complex numbers.
- In the expression \/ step -- \((8-4i)(-3+9i)\)
- We distribute each term in the first complex number to each term in the second complex number.
- This breaks the problem down into smaller sums that are easier to handle.
Other exercises in this chapter
Problem 14
Solve each equation in Exercises \(1-14\) by factoring. $$10 x-1=(2 x+1)^{2}$$
View solution Problem 14
Express interval in set-builder notation and graph the interval on a number line. \((-\infty, 3.5]\)
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Graph each equation .Let $x=-3,-2,-1,0,1,2, and 3. $$ y=x^{2}+2 $$
View solution Problem 15
Solve cach equation in Exercises \(15-34\) by the square root property. $$3 x^{2}=27$$
View solution