Problem 14
Question
Find an equation in \(x\) and \(y\) whose graph contains the points on the curve
\(C\). Sketch the graph of \(C\), and indicate the orientation.
$$x=\csc t, \quad y=\cot t, \quad-\pi
Step-by-Step Solution
Verified Answer
The equation is \( y = -\sqrt{x^2 - 1} \), with the graph tracing from left to right in the fourth quadrant.
1Step 1: Understand Trigonometric Relationships
Recall that the cosecant and cotangent functions are related to sine and cosine. Specifically, \( \csc t = \frac{1}{\sin t} \) and \( \cot t = \frac{\cos t}{\sin t} \).
2Step 2: Express Sine in Terms of x
Given \( x = \csc t \), write this as \( x = \frac{1}{\sin t} \). Thus, \( \sin t = \frac{1}{x} \).
3Step 3: Express y in Terms of x
Since \( y = \cot t = \frac{\cos t}{\sin t} \) and \( \sin t = \frac{1}{x} \), we can substitute to get \( y = \cos t \cdot x \).
4Step 4: Use Pythagorean Identity to Find cos(t)
Using the identity \( \sin^2 t + \cos^2 t = 1 \), substitute \( \sin t = \frac{1}{x} \) to find \( \cos t = \sqrt{1 - \sin^2 t} = \sqrt{1 - \frac{1}{x^2}} \).
5Step 5: Substitute cos(t) in Expression for y
Substitute \( \cos t = \sqrt{1 - \frac{1}{x^2}} \) into \( y = \cos t \cdot x \) to get \( y = x \cdot \sqrt{1 - \frac{1}{x^2}} \), simplifying to \( y = \sqrt{x^2 - 1} \), taking into account the negative range of \( t \).
6Step 6: Analyze Range of t for Orientation and Sketch
Given \(-\pi < t < 0\), \( x \) (which is \( \csc t \)) ranges from \(-\infty\) to \(-1^-\), and \( y \) is non-positive. The curve is traced from left to right as \( t \) increases, sketching an arc in the fourth quadrant.
Key Concepts
Trigonometric FunctionsPythagorean IdentityGraphing TechniquesCoordinate Geometry
Trigonometric Functions
Trigonometric functions are fundamental in understanding periodic phenomena, often used to model waves and repetitive patterns. These functions include sine (\( \sin t \)), cosine (\( \cos t \)), and their reciprocals such as cosecant (\( \csc t = \frac{1}{\sin t} \)) and cotangent (\( \cot t = \frac{\cos t}{\sin t} \)). When working with parametric equations, these functions help to describe the movement of a point along a curve over time.
- \( \csc t \) represents the reciprocal of the sine function, helpful in expressing angles and their relative positions.
- \( \cot t \) is the ratio of cosine to sine, giving us another perspective in trigonometric contexts.
Pythagorean Identity
The Pythagorean Identity is a key tool in trigonometry, expressing the fundamental relationship between sine and cosine:\[ \sin^2 t + \cos^2 t = 1 \]. It reminds us that for any angle, the sum of the squares of sine and cosine is always equal to one.
This identity helps solve equations where you can express one trigonometric function in terms of another. For instance, if you know \( \sin t = \frac{1}{x} \), substituting into the identity allows you to find \( \cos t = \sqrt{1 - \frac{1}{x^2}} \). This expression is critical when transitioning from parametric to Cartesian equations by eliminating the parameter \( t \).
Such identities streamline our calculations and make solving parametric equations more manageable.
This identity helps solve equations where you can express one trigonometric function in terms of another. For instance, if you know \( \sin t = \frac{1}{x} \), substituting into the identity allows you to find \( \cos t = \sqrt{1 - \frac{1}{x^2}} \). This expression is critical when transitioning from parametric to Cartesian equations by eliminating the parameter \( t \).
Such identities streamline our calculations and make solving parametric equations more manageable.
Graphing Techniques
Graphing parametric equations requires understanding how components \( x(t) \) and \( y(t) \) draw a path in the coordinate plane. Observing the behavior of \( x \) and \( y \) as \( t \) varies helps in accurately plotting the curve on a graph.
To graph the function \( x = \csc t \) and \( y = \cot t \), observe both:
To graph the function \( x = \csc t \) and \( y = \cot t \), observe both:
- As \( t \) ranges from \(-\pi \) to \(0 \), \( \csc t \) influences \( x \) to vary from \(-\infty \) to values close to \(-1 \). This indicates the path traversing from left to right.
- Simultaneously, \( \cot t \) affects \( y \) values to remain non-positive, indicating the journey through the fourth quadrant.
Coordinate Geometry
Coordinate Geometry, or analytic geometry, connects algebra and geometry to describe the positions of points, lines, and figures in space. Using coordinates, we can express relations and quantify geometric properties.
When reworking parametric equations into Cartesian coordinates, as in transforming \( x = \csc t \) and \( y = \cot t \) into \( y = \sqrt{x^2 - 1} \), this field helps describe geometrical shapes and their characteristics.
When reworking parametric equations into Cartesian coordinates, as in transforming \( x = \csc t \) and \( y = \cot t \) into \( y = \sqrt{x^2 - 1} \), this field helps describe geometrical shapes and their characteristics.
- Useful for calculating distances and midpoints along a graph.
- Helps in deriving equations of geometrical figures, such as lines or circles, in a Cartesian plane.
- Enables easier interpretation through graphical representation.
Other exercises in this chapter
Problem 13
Find a polar equation that has the same graph as the equation in \(x\) and \(y\). $$x=-3$$
View solution Problem 13
Exer. 1-14: Find the vertices and foci of the ellipse. Sketch its graph, showing the foci. $$25 x^{2}+4 y^{2}-250 x-16 y+541=0$$
View solution Problem 14
Find the vertices, the foci, and the equations of the asymptotes of the hyperbola. Sketch its graph, showing the asymptotes and the foci. $$y^{2}-4 x^{2}-12 y-1
View solution Problem 14
Find a polar equation that has the same graph as the equation in \(x\) and \(y\). $$y=2$$
View solution