Problem 14
Question
Find a vector that is perpendicular to both a and b. $$ \mathbf{a}=(-1,-2,4), \mathbf{b}=\langle 4,-1,0\rangle $$
Step-by-Step Solution
Verified Answer
The vector perpendicular to both is \((4, 16, 9)\).
1Step 1: Understand the Concept of Cross Product
The cross product of two vectors \(\mathbf{a}\) and \(\mathbf{b}\) results in a vector \(\mathbf{c}\) that is perpendicular to both \(\mathbf{a}\) and \(\mathbf{b}\). We will calculate the cross product \(\mathbf{a} \times \mathbf{b}\) to find such a vector.
2Step 2: Use the Formula for Cross Product
The formula for the cross product \(\mathbf{a} \times \mathbf{b}\) is given by: \[\mathbf{a} \times \mathbf{b} = (a_2b_3 - a_3b_2, a_3b_1 - a_1b_3, a_1b_2 - a_2b_1)\] We substitute the values from \(\mathbf{a}=(-1,-2,4)\) and \(\mathbf{b}=(4,-1,0)\).
3Step 3: Calculate the Individual Components
Calculate each component of the cross product using the formula:\(a_2b_3 - a_3b_2 = (-2)(0) - (4)(-1) = 0 + 4 = 4a_3b_1 - a_1b_3 = (4)(4) - (-1)(0) = 16 + 0 = 16a_1b_2 - a_2b_1 = (-1)(-1) - (-2)(4) = 1 + 8 = 9\)
Key Concepts
Perpendicular Vectors and Their Cross ProductBasics of Vector Algebra: Understanding Vector OperationsThree-Dimensional Vectors: Navigating 3D Space
Perpendicular Vectors and Their Cross Product
Perpendicular vectors are vectors that intersect at a right angle, forming a 90-degree angle between them. This concept is crucial in vector algebra, particularly when working in three-dimensional space. An important operation used to find a vector perpendicular to two given vectors is the **cross product**. If you have two vectors, \( \mathbf{a} \) and \( \mathbf{b} \), the cross product \( \mathbf{a} \times \mathbf{b} \) results in a third vector that is perpendicular to both \( \mathbf{a} \) and \( \mathbf{b} \). This resulting vector is often denoted as \( \mathbf{c} \). In practical terms, if you imagine \( \mathbf{a} \) and \( \mathbf{b} \) laying on a plane, the cross product vector will "stick out" of the plane.
- If a vector \( \mathbf{c} \) is perpendicular to any vectors \( \mathbf{a} \) and \( \mathbf{b} \), it satisfies: \( \mathbf{a} \cdot \mathbf{c} = 0 \) and \( \mathbf{b} \cdot \mathbf{c} = 0 \)
Basics of Vector Algebra: Understanding Vector Operations
Vector algebra deals with operations involving vectors, critical in fields like physics and engineering and when working with three-dimensional vectors. A vector is essentially a quantity that has both a magnitude and a direction, represented as an ordered list of numbers, like \((x, y, z)\). Two principal operations in vector algebra are the **dot product** and the **cross product**.
- The dot product is a scalar result obtained from two vectors. It tells you how much of one vector goes in the direction of another. A result of zero implies the vectors are perpendicular.
- The cross product results in a vector, important for determining perpendicular vectors as we've seen earlier.
Three-Dimensional Vectors: Navigating 3D Space
Three-dimensional vectors are vectors that exist in space with three distinct dimensions—height, width, and depth, often denoted as \( x, y, z \). In the context of 3D space, vectors are especially useful for modeling and solving problems related to physical phenomena, like force, velocity, and acceleration.Some useful pointers for understanding 3D vectors include:
- A 3D vector can be represented as \( \langle x, y, z \rangle \), which indicates its position or direction in 3D space.
- Operations on 3D vectors, such as addition, subtraction, and cross product, maintain their three-dimensional nature.
- Visualizing 3D vectors often involves using a coordinate system where each axis represents one dimension.
Other exercises in this chapter
Problem 14
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