Problem 14
Question
Exer. 9-14: (a) Find the distance \(d(A, B)\) between \(A\) and \(B\). (b) Find the midpoint of the segment \(A B\). $$ A(-4,7), \quad B(0,-8) $$
Step-by-Step Solution
Verified Answer
The distance is \(\sqrt{241}\) and the midpoint is \((-2, -\frac{1}{2})\).
1Step 1: Find the difference in coordinates
To find the distance between points \(A\) and \(B\), we first need the differences in the \(x\) and \(y\) coordinates. Given the coordinates \(A(-4, 7)\) and \(B(0, -8)\), calculate the difference in \(x\)-coordinates: \( \Delta x = 0 - (-4) = 4\). Calculate the difference in \(y\)-coordinates: \( \Delta y = -8 - 7 = -15\).
2Step 2: Use the distance formula
The formula for the distance between two points \((x_1, y_1)\) and \((x_2, y_2)\) is \( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \). Substitute the differences into this formula: \( d = \sqrt{4^2 + (-15)^2} = \sqrt{16 + 225} = \sqrt{241} \).
3Step 3: Calculate the midpoint coordinates
To find the midpoint of the segment \(AB\), use the midpoint formula: \( M(x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \). Substitute the given coordinates: \( M = \left( \frac{-4 + 0}{2}, \frac{7 + (-8)}{2} \right) = \left( -2, -\frac{1}{2} \right) \).
Key Concepts
midpoint formulacoordinate geometrydistance between points
midpoint formula
To find the midpoint of a line segment connecting two points, we use the midpoint formula. This formula helps us calculate the coordinates of a point that divides the segment into two equal halves. The midpoint ensures that the line segment is perfectly balanced.The formula for determining the midpoint, \( M(x, y) \), given two endpoints \( (x_1, y_1) \) and \( (x_2, y_2) \), is given by:
- \( M(x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \)
- \( M = \left( \frac{-4 + 0}{2}, \frac{7 + (-8)}{2} \right) = \left( -2, -\frac{1}{2} \right) \)
coordinate geometry
Coordinate geometry, also known as analytic geometry, is a branch of mathematics that uses numbers to represent geometric shapes and their properties. It allows us to analyze and solve geometric problems using a coordinate plane where each point is represented by a pair of numbers (coordinates), typically as \((x, y)\).This approach enables clear and precise calculations of distances, angles, and other geometric properties. With coordinate geometry, one can easily:
- Determine distances between points using the distance formula.
- Find midpoints of line segments using the midpoint formula.
- Identify relationships and intersections of lines, curves, and figures.
distance between points
To calculate the distance between two points on a coordinate plane, we utilize the distance formula. This formula derives from the Pythagorean theorem and is essential for finding the exact length of the segment that connects the two points.Assuming points \((x_1, y_1)\) and \((x_2, y_2)\), the distance \(d\) between these points is given by:
- \( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \)
- \(\Delta x = 0 - (-4) = 4\)
- \(\Delta y = -8 - 7 = -15\)
- \(d = \sqrt{4^2 + (-15)^2} = \sqrt{16 + 225} = \sqrt{241}\)
Other exercises in this chapter
Problem 14
Exer. 11-14: If \(a\) is a positive real number, find (a) \(g\left(\frac{1}{a}\right)\) (b) \(\frac{1}{g(a)}\) (c) \(g(\sqrt{a})\) (d) \(\sqrt{g(a)}\) $$ g(x)=\
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Exer. 13-26: Sketch, on the same coordinate plane, the graphs of \(f\) for the given values of \(c\). (Make use of symmetry, shifting, stretching, compressing,
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Exer. 11-20: Find (a) \((f \circ g)(x)\) (b) \((g \circ f)(x)\) (c) \(f(g(-2))\) (d) \(g(f(3))\) $$ f(x)=2 x^{2}+3 x-4, \quad g(x)=2 x-1 $$
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