Problem 14
Question
Evaluate the trigonometric limits. $$ \lim _{x \rightarrow 0} \frac{1-\cos ^{2} x}{x^{2}} $$
Step-by-Step Solution
Verified Answer
The limit evaluates to 1.
1Step 1: Recognize the Expression
The given limit is \( \lim _{x \rightarrow 0} \frac{1 - \cos^2 x}{x^2} \). Recognize that \(1 - \cos^2 x\) is an identity related to sine: \(1 - \cos^2 x = \sin^2 x\).
2Step 2: Rewrite Using Identity
Rewrite the given limit expression using the identity \(1 - \cos^2 x = \sin^2 x\), resulting in \(\lim _{x \rightarrow 0} \frac{\sin^2 x}{x^2}\).
3Step 3: Apply Limit Laws
The limit \(\lim _{x \rightarrow 0} \frac{\sin^2 x}{x^2}\) can be rewritten as \(\left(\lim_{x\rightarrow 0} \frac{\sin x}{x}\right)^2\). The well-known limit \(\lim_{x\rightarrow 0} \frac{\sin x}{x} = 1\) can be applied.
4Step 4: Compute the Final Limit
Since \(\lim_{x\rightarrow 0} \frac{\sin x}{x} = 1\), substitute into the expression: \(\left(\lim_{x\rightarrow 0} \frac{\sin x}{x}\right)^2 = 1^2 = 1\). Thus, the value of the limit is 1.
Key Concepts
Limit LawsTrigonometric IdentitiesSine and Cosine Functions
Limit Laws
Limit Laws are essential tools in calculus. They help evaluate the behavior of functions as inputs get arbitrarily close to a certain point. In the context of trigonometric limits, these laws are particularly helpful because they simplify otherwise complex problems.
When using limit laws, remember a few key points:
When using limit laws, remember a few key points:
- Limits of individual terms can be combined, i.e., the limit of a sum is the sum of the limits.
- For products, the limit of a product is the product of the limits.
- The same applies for quotients, provided the limit of the denominator is not zero.
Trigonometric Identities
Trigonometric Identities are equations involving trigonometric functions that hold for all values of the variables involved. They are essential in manipulating and simplifying trigonometric expressions, especially in calculus.
One classic identity is \[1 - \cos^2 x = \sin^2 x\]which plays a crucial role in simplifying limits like the one in the exercise. By recognizing and substituting this identity, the problem becomes much more manageable.
The power of these identities lies in their ability to transform complex trigonometric expressions into simpler forms, which are often easier to handle. Other key identities include:
One classic identity is \[1 - \cos^2 x = \sin^2 x\]which plays a crucial role in simplifying limits like the one in the exercise. By recognizing and substituting this identity, the problem becomes much more manageable.
The power of these identities lies in their ability to transform complex trigonometric expressions into simpler forms, which are often easier to handle. Other key identities include:
- \(\sin^2 x + \cos^2 x = 1\)
- \(\tan^2 x + 1 = \sec^2 x\)
- \(1 + \cot^2 x = \csc^2 x\)
Sine and Cosine Functions
Sine and Cosine are fundamental trigonometric functions that describe the ratios of sides in a right-angled triangle. Understanding their properties is crucial in evaluating trigonometric limits.
The Sin function \(\sin x\) is periodic, with values ranging between -1 and 1. Its curve starts at the origin and completes a full cycle every \(2\pi\). Similarly, the Cosine function \(\cos x\) has the same range and periodicity, but starts at 1.
When working with limits involving these functions, it's helpful to remember:
The Sin function \(\sin x\) is periodic, with values ranging between -1 and 1. Its curve starts at the origin and completes a full cycle every \(2\pi\). Similarly, the Cosine function \(\cos x\) has the same range and periodicity, but starts at 1.
When working with limits involving these functions, it's helpful to remember:
- Both \(\sin x\) and \(\cos x\) are continuously differentiable functions.
- Near zero, \(\sin x\) approximates to \(x\) and both approach 0 as \(x\) approaches 0.
- The identity \(\lim_{x \rightarrow 0} \frac{\sin x}{x} = 1\) is especially helpful.
Other exercises in this chapter
Problem 13
Show that the floor function \(f(x)=\lfloor x\rfloor\) is continuous at \(x=5 / 2\) but discontinuous at \(x=3\).
View solution Problem 13
Evaluate the limits in problems. $$ \lim _{x \rightarrow \infty} \frac{4}{1+e^{-2 x}} $$
View solution Problem 14
Use the formal definition of limits to prove each statement. $$ \lim _{x \rightarrow 0} \frac{-2}{x^{2}}=-\infty $$
View solution Problem 14
Explain why a polynomial of degree \(n\), where \(n\) is an odd number, has at least one root.
View solution