Problem 14
Question
Evaluate each expression without using a calculator. $$ \left(\frac{1}{3}\right)^{-2}-\left(\frac{1}{2}\right)^{-2} $$
Step-by-Step Solution
Verified Answer
The expression evaluates to 5.
1Step 1: Understanding Negative Exponents
When we have a negative exponent, it means we take the reciprocal of the base and then raise it to the positive of that exponent. For example, for any nonzero number \(a\) and any integer \(n\), \(a^{-n} = \frac{1}{a^n}\). So, \( \left(\frac{1}{3}\right)^{-2} = 9 \) and \( \left(\frac{1}{2}\right)^{-2} = 4 \).
2Step 2: Evaluate the First Term
Using the rule for negative exponents, evaluate \( \left(\frac{1}{3}\right)^{-2} \). This gives: \( \left(\frac{1}{3}\right)^{-2} = 3^2 = 9 \).
3Step 3: Evaluate the Second Term
Similarly, evaluate \( \left(\frac{1}{2}\right)^{-2} \). This results in: \( \left(\frac{1}{2}\right)^{-2} = 2^2 = 4 \).
4Step 4: Subtract the Values
Now subtract the second term from the first: \( 9 - 4 \).
5Step 5: Find the Final Answer
Calculate the subtraction: \( 9 - 4 = 5 \).
Key Concepts
Exponent RulesReciprocalsSimplifying Expressions
Exponent Rules
Exponent rules, especially when dealing with negative exponents, can initially seem daunting, but they become much simpler with practice.
Understanding these rules is crucial for evaluating expressions efficiently. Let's break down how to handle negative exponents:
* The key idea behind a negative exponent is the reciprocal.
* If you see a negative exponent, it tells you to flip the base to its reciprocal.
* Then raise this reciprocal to the absolute value of the exponent.
For example, consider an expression like \( \left(\frac{1}{3}\right)^{-2} \). Here, the base \( \frac{1}{3} \) flips to \( 3 \), and then it's squared because the exponent is \(-2\). This means:\[\left(\frac{1}{3}\right)^{-2} = 3^2 = 9\] Similarly, for \( \left(\frac{1}{2}\right)^{-2} \), the base \( \frac{1}{2} \) becomes \(2\), and it's raised to the power of 2 due to the negative exponent:\[\left(\frac{1}{2}\right)^{-2} = 2^2 = 4\] These rules of negative exponents apply universally to any nonzero base and integer exponent.
Understanding these rules is crucial for evaluating expressions efficiently. Let's break down how to handle negative exponents:
* The key idea behind a negative exponent is the reciprocal.
* If you see a negative exponent, it tells you to flip the base to its reciprocal.
* Then raise this reciprocal to the absolute value of the exponent.
For example, consider an expression like \( \left(\frac{1}{3}\right)^{-2} \). Here, the base \( \frac{1}{3} \) flips to \( 3 \), and then it's squared because the exponent is \(-2\). This means:\[\left(\frac{1}{3}\right)^{-2} = 3^2 = 9\] Similarly, for \( \left(\frac{1}{2}\right)^{-2} \), the base \( \frac{1}{2} \) becomes \(2\), and it's raised to the power of 2 due to the negative exponent:\[\left(\frac{1}{2}\right)^{-2} = 2^2 = 4\] These rules of negative exponents apply universally to any nonzero base and integer exponent.
Reciprocals
Reciprocals play an essential role in understanding negative exponents. If you grasp how reciprocals work, managing negative exponents will seem much easier.
Simply put, the reciprocal of a number is what you multiply it by to get 1.
For instance:
The fraction becomes its reciprocal, and the negative exponent becomes a positive one. That’s why \( \left(\frac{1}{3}\right)^{-2} \) turns into \(3^2\), or 9. Take \( \left(\frac{1}{2}\right)^{-2} \), and the process is the same: take the reciprocal of \(\frac{1}{2}\), which is \(2\), and square it to get 4.
Understanding reciprocals provides a solid foundation for working with negative exponents and their applications in arithmetic and algebra.
Simply put, the reciprocal of a number is what you multiply it by to get 1.
For instance:
- The reciprocal of \(3\) is \(\frac{1}{3}\)
- The reciprocal of \(\frac{1}{3}\) is \(3\)
The fraction becomes its reciprocal, and the negative exponent becomes a positive one. That’s why \( \left(\frac{1}{3}\right)^{-2} \) turns into \(3^2\), or 9. Take \( \left(\frac{1}{2}\right)^{-2} \), and the process is the same: take the reciprocal of \(\frac{1}{2}\), which is \(2\), and square it to get 4.
Understanding reciprocals provides a solid foundation for working with negative exponents and their applications in arithmetic and algebra.
Simplifying Expressions
Simplifying expressions involving exponents can sometimes feel complex, yet it becomes significantly more manageable by applying consistent methods. When you simplify expressions with negative exponents, follow these straightforward steps:
* Convert any negative exponents to positive by using reciprocals.
* Compute any exponential values, essentially squaring or raising the number to the given power.In our example with \( \left(\frac{1}{3}\right)^{-2} - \left(\frac{1}{2}\right)^{-2}\), we handled each term individually first.
By dealing with \( \left(\frac{1}{3}\right)^{-2} \) and \(\left(\frac{1}{2}\right)^{-2}\), we performed a simplification for each term:* Convert \( \left(\frac{1}{3}\right)^{-2} \) to \(3^2 = 9\)* Convert \( \left(\frac{1}{2}\right)^{-2} \) to \(2^2 = 4\)Finally, to obtain the answer, subtract the simplified second term from the first:\[9 - 4 = 5\]Successfully simplifying expressions means tackling one part at a time, ensuring clarity and ease in the calculation process.
* Convert any negative exponents to positive by using reciprocals.
* Compute any exponential values, essentially squaring or raising the number to the given power.In our example with \( \left(\frac{1}{3}\right)^{-2} - \left(\frac{1}{2}\right)^{-2}\), we handled each term individually first.
By dealing with \( \left(\frac{1}{3}\right)^{-2} \) and \(\left(\frac{1}{2}\right)^{-2}\), we performed a simplification for each term:* Convert \( \left(\frac{1}{3}\right)^{-2} \) to \(3^2 = 9\)* Convert \( \left(\frac{1}{2}\right)^{-2} \) to \(2^2 = 4\)Finally, to obtain the answer, subtract the simplified second term from the first:\[9 - 4 = 5\]Successfully simplifying expressions means tackling one part at a time, ensuring clarity and ease in the calculation process.
Other exercises in this chapter
Problem 13
Solve each equation by factoring. [Hint for: First factor out a fractional power.] $$ 5 x^{3}-20 x=0 $$
View solution Problem 13
Find the slope (if it is defined) of the line determined by each pair of points. $$ (2,-1) \text { and }(2,5) $$
View solution Problem 14
For each function: a. Evaluate the given expression. b. Find the domain of the function. c. Find the range. $$ h(z)=\frac{1}{z+7} ; \text { find } h(-8) $$
View solution Problem 14
Solve each equation by factoring. [Hint for: First factor out a fractional power.] $$ 2 x^{5}-50 x^{3}=0 $$
View solution