Problem 14
Question
Evaluate each expression. $$ \frac{3^{-2}}{9} $$
Step-by-Step Solution
Verified Answer
The value of the expression is \( \frac{1}{81} \).
1Step 1: Evaluate the Exponent
First, simplify the expression by evaluating the exponent in the numerator. The expression given is \( \frac{3^{-2}}{9} \). \(3^{-2}\) is equivalent to \(\frac{1}{3^2}\), which simplifies to \(\frac{1}{9}\).
2Step 2: Substitute and Simplify
Substitute \(\frac{1}{9}\) for \(3^{-2}\) in the original expression. Now, the expression becomes \(\frac{\frac{1}{9}}{9}\), which simplifies to \(\frac{1}{9} \times \frac{1}{9}\).
3Step 3: Perform the Multiplication
Multiply the fractions: \(\frac{1}{9} \times \frac{1}{9}\). This results in \(\frac{1 \times 1}{9 \times 9} = \frac{1}{81}\).
Key Concepts
Negative ExponentsFraction SimplificationMultiplication of Fractions
Negative Exponents
Understanding negative exponents is crucial to solving expressions like \( \frac{3^{-2}}{9} \). A negative exponent means you are dividing by that number instead of multiplying. For instance, \( 3^{-2} \) flips the base and turns the exponent positive, resulting in \( \frac{1}{3^2} \).
Why this change, you ask? It's all about creating fractions. A negative in the exponent shifts the number from the numerator to the denominator, or vice-versa. This is a compact way to represent division and can make calculation easier.
Why this change, you ask? It's all about creating fractions. A negative in the exponent shifts the number from the numerator to the denominator, or vice-versa. This is a compact way to represent division and can make calculation easier.
- \( x^{-n} = \frac{1}{x^n} \)
- \( 3^{-2} = \frac{1}{3^2} = \frac{1}{9} \)
Fraction Simplification
When working with fractions, simplifying them is a key step to finding an accurate solution. After converting the negative exponent, the expression becomes \( \frac{\frac{1}{9}}{9} \). Simplifying complex fractions like this involves understanding mixed operations.
Think of a complex fraction as a stacked operation. You're essentially performing division between the fractions, which converts into a multiplication process later. The main goal is to make the fraction easier to handle by eliminating unnecessary parts.
Think of a complex fraction as a stacked operation. You're essentially performing division between the fractions, which converts into a multiplication process later. The main goal is to make the fraction easier to handle by eliminating unnecessary parts.
- \( \frac{\frac{a}{b}}{c} = \frac{a}{b} \times \frac{1}{c} \)
Multiplication of Fractions
Multiplying fractions is a straightforward but vital arithmetic operation. In our exercise, once we simplified the complex fraction \( \frac{\frac{1}{9}}{9} \) into \( \frac{1}{9} \times \frac{1}{9} \), the process becomes simple multiplication.To multiply fractions:
- Multiply the numerators (top numbers) together.
- Multiply the denominators (bottom numbers) together.
Other exercises in this chapter
Problem 13
Evaluate each expression. (a) \(\left(\frac{4}{9}\right)^{-1 / 2}\) (b) \((-32)^{2 / 5}\) (c) \((-125)^{-1 / 3}\)
View solution Problem 13
Write an algebraic formula for the given quantity.. The sum \(S\) of two consecutive integers, the first integer being \(n\)
View solution Problem 14
\(7-20=\) Simplify the rational expression. $$ \frac{x^{2}-x-2}{x^{2}-1} $$
View solution Problem 14
Perform the indicated operations and simplify. $$ (5-3 x)+(2 x-8) $$
View solution