Problem 14
Question
Calculate the discriminant and use it to determine the number and type of solutions. Do not solve. $$ 9 t 2-6 t+1=0 $$
Step-by-Step Solution
Verified Answer
One real repeated solution.
1Step 1: Identify coefficients
For the quadratic equation in the standard form \( ax^2 + bx + c = 0 \), identify the coefficients from the given quadratic equation \( 9t^2 - 6t + 1 = 0 \). Here, \( a = 9 \), \( b = -6 \), and \( c = 1 \).
2Step 2: Calculate the discriminant
The discriminant \( \Delta \) of a quadratic equation is calculated using the formula \( \Delta = b^2 - 4ac \). Substitute the identified coefficients into the formula: \( \Delta = (-6)^2 - 4 \cdot 9 \cdot 1 \).
3Step 3: Simplify the discriminant expression
First, calculate \( (-6)^2 = 36 \) and \( 4 \cdot 9 \cdot 1 = 36 \). Substitute these values back into the discriminant formula: \( \Delta = 36 - 36 = 0 \).
4Step 4: Determine the number and type of solutions
Since the discriminant \( \Delta = 0 \), the quadratic equation has exactly one real and repeated solution (a double root).
Key Concepts
Understanding the DiscriminantRole and Identification of CoefficientsIdentifying Real Solutions
Understanding the Discriminant
In quadratic equations, the discriminant is a key mathematical expression used to determine the nature and the number of solutions. It is denoted by the symbol \( \Delta \) and is calculated using the formula \( \Delta = b^2 - 4ac \). This formula involves the coefficients \( a \), \( b \), and \( c \) of the quadratic equation in the standard form \( ax^2 + bx + c = 0 \). The discriminant can inform us about the solutions without actually solving the equation.
After computing \( \Delta \):
After computing \( \Delta \):
- If \( \Delta > 0 \), there are two distinct real solutions.
- If \( \Delta = 0 \), there is exactly one real solution, known as a double root.
- If \( \Delta < 0 \), there are no real solutions, but two complex solutions.
Role and Identification of Coefficients
The coefficients in a quadratic equation are the numerical factors that multiply the variables. These coefficients are crucial as they form the basis for calculating the discriminant. A quadratic equation typically appears in the form \( ax^2 + bx + c = 0 \). Here:
In the exercise, the equation \( 9t^2 - 6t + 1 = 0 \) gives us: - \( a = 9 \) - \( b = -6 \) - \( c = 1 \) Understanding these coefficients helps in calculating the discriminant to predict the nature of the solutions easily.
- \( a \): the coefficient of \( x^2 \), controls the parabola's width and direction.
- \( b \): the coefficient of \( x \), affects the symmetry and roots of the parabola.
- \( c \): the constant term, shifts the parabola up or down.
In the exercise, the equation \( 9t^2 - 6t + 1 = 0 \) gives us: - \( a = 9 \) - \( b = -6 \) - \( c = 1 \) Understanding these coefficients helps in calculating the discriminant to predict the nature of the solutions easily.
Identifying Real Solutions
Real solutions of a quadratic equation correspond to the values of the variable that satisfy the equation. These solutions are points where the graph of the equation, a parabola, crosses the x-axis. The discriminant plays a crucial role in determining the number of real solutions a quadratic equation will have.
When the discriminant \( \Delta \) is:
When the discriminant \( \Delta \) is:
- Greater than zero \((\Delta > 0)\): the quadratic equation has two distinct real solutions.
- Equal to zero \((\Delta = 0)\): there is one real solution, creating a double root scenario.
- Less than zero \((\Delta < 0)\): no real solutions exist, indicating complex roots.
Other exercises in this chapter
Problem 14
Find a quadratic equation in standard form with the given solutions. $$ \pm 25 \mathrm{~V} $$
View solution Problem 14
Perform the operations. $$ (-10+15 i)+(15-20 i) $$
View solution Problem 15
Solve by factoring and then solve using the quadratic formula. Check answers. $$2 x_{2}-7 x-4=0$$
View solution Problem 15
Perform the operations. $$ (12+34 i)+(16-18 i) $$
View solution