Problem 14
Question
Are the two functions the same function? $$ h(t)=t^{2}-t(t-1) \text { and } g(t)=t $$
Step-by-Step Solution
Verified Answer
Answer: Yes, the functions h(t) and g(t) are the same function since their simplified expressions are equivalent (h(t) = t = g(t)).
1Step 1: Simplify h(t)
First, we simplify the given function h(t). We have:
$$
h(t) = t^2 - t(t-1)
$$
Apply the distributive property to expand the second term:
$$
h(t) = t^2 - (t^2 - t)
$$
Now, simplify the expression by combining like terms:
$$
h(t) = t^2 - t^2 + t
$$
$$
h(t) = t
$$
The simplified form of h(t) is just t.
2Step 2: Simplify and compare g(t)
The given function g(t) is already simplified:
$$
g(t) = t
$$
Now, compare the simplified forms of h(t) and g(t):
$$
h(t) = t = g(t)
$$
Since the simplified expressions of h(t) and g(t) are equivalent, the two functions are indeed the same function.
Key Concepts
Distributive PropertyLike TermsFunction Equivalence
Distributive Property
The distributive property is a fundamental concept that often helps simplify mathematical expressions. In the context of functions, it allows us to expand expressions by distributing terms over a sum or difference. For example, consider the function \( h(t) = t^2 - t(t-1) \). Here, the distributive property can be applied to the second term \( t(t-1) \). This means multiplying \( t \) by each term inside the parentheses individually:
- Multiply \( t \) by \( t \), resulting in \( t^2 \).
- Multiply \( t \) by \( -1 \), resulting in \( -t \).
Like Terms
Like terms are pieces of an expression that contain the same variable raised to the same power. Identifying and combining like terms is crucial when simplifying expressions. When simplifying an expression like \( h(t) = t^2 - (t^2 - t) \), it's important to recognize and group the like terms. Here are the steps:
- Start by expanding or simplifying any expressions using properties such as the distributive property.
- In the expression, identify the terms \( t^2 \) and \(- t^2 \), which cancel each other out when you're subtracting \( t^2 - t^2 \).
- The remaining term, \( + t \), is left as it is since it has no like terms to combine with in this case.
Function Equivalence
Determining if two functions are equivalent involves simplifying and comparing their forms. In the given exercise, once both \( h(t) \) and \( g(t) \) are simplified, the process for checking function equivalence becomes straightforward.
- Simplify each function independently to its most reduced or simple form.
- For \( h(t) \), after applying the distributive property and combining like terms, we found it simplifies to \( t \).
- \( g(t) \) is already in its simplest form, which is also \( t \).
- Since \( h(t) \) and \( g(t) \) both simplify to \( t \), they are indeed equivalent.
Other exercises in this chapter
Problem 14
In Exercises 14-17, assume the two quantities are directly proportional to each other. If \(r=36\) when \(s=4\), find \(r\) when \(s\) is 5.
View solution Problem 14
Table 4.14 gives values of \(D=f(t),\) the total US debt (in \$ billions) \(t\) years after \(2000 .{ }^{4}\) Answer based on this information. $$\begin{aligned
View solution Problem 14
Evaluate the expressions given that $$ f(x)=\frac{2 x+1}{3-5 x} \quad g(y)=\frac{1}{\sqrt{y^{2}+1}} $$ $$ g(\sqrt{8}) $$
View solution Problem 15
In Exercises 14-17, assume the two quantities are directly proportional to each other. If \(p=24\) when \(q=6,\) find \(q\) when \(p\) is 32 .
View solution