Problem 14
Question
An equation for loudness \(L\) in decibels, is \(L=10 \log _{10} R\) where \(R\) is the relative intensity of the sound. Solve \(75=10 \log _{10} R\) to find the relative intensity of a concert with a loudness of 75 decibels.
Step-by-Step Solution
Verified Answer
The relative intensity is approximately 3,162,277.66.
1Step 1: Understand the Equation
The given equation is \(L=10 \log_{10} R\), which relates loudness \(L\) in decibels to the relative intensity \(R\). You need to solve for \(R\) when \(L = 75\).
2Step 2: Substitute Values
Substitute 75 for \(L\) in the equation: \(75 = 10 \log_{10} R\).
3Step 3: Isolate Logarithmic Term
Divide both sides of the equation by 10 to isolate the logarithmic term: \(\frac{75}{10} = \log_{10} R\), which simplifies to \(7.5 = \log_{10} R\).
4Step 4: Exponentiate to Remove the Logarithm
To solve for \(R\), rewrite the logarithmic equation in its exponential form: \(R = 10^{7.5}\).
5Step 5: Calculate the Exponential
Calculate \(10^{7.5}\) to find \(R\). This evaluates to \(R \approx 3,162,277.66\).
Key Concepts
Sound IntensityDecibelsExponential Equations
Sound Intensity
Sound intensity is a measure of the power per unit area of a sound wave. It describes how much sound energy passes through a certain area in a given time. This is crucial when considering how loud or quiet a sound is perceived.
Understanding sound intensity allows us to quantify the force of vibrations that reach our ear. The stronger the vibrations, the higher the intensity. It involves the actual physical properties of the sound wave such as:
Understanding sound intensity allows us to quantify the force of vibrations that reach our ear. The stronger the vibrations, the higher the intensity. It involves the actual physical properties of the sound wave such as:
- The amplitude of the wave
- The distance from the sound source
Decibels
Decibels are units of measurement that express the loudness of a sound. They provide a logarithmic way to describe sound levels, which is more in line with how humans perceive changes in loudness. If you are unfamiliar with logarithms, think of them as a way to transform large numbers into more manageable ones.
The formula to calculate decibels in terms of relative sound intensity is:\[L = 10 \log_{10} R\]
The formula to calculate decibels in terms of relative sound intensity is:\[L = 10 \log_{10} R\]
- "\(L\)" stands for loudness in decibels.
- "\(R\)" represents the relative intensity in comparison to a reference level.
Exponential Equations
Exponential equations are equations where the variables appear as exponents. In the context of logarithmic equations, which are the inverse of exponential equations, they help us solve measures of growth or intensity, like sound.In our earlier example, to find relative intensity, we used the exponential form of a logarithmic equation: By setting \(7.5 = \log_{10} R\), we rewrote it as an exponential equation:\[R = 10^{7.5}\]The logarithmic form helps to solve for an unknown exponent (relative intensity \(R\)). Then we compute the actual value using the exponential equation, finding that \(R \approx 3,162,277.66\), showcasing sound's "growing" effect as perceived through its relative intensity.
- Exponential equations like these are powerful in modeling relationships that change rapidly, such as compound interest or population growth.
- They can appear daunting, but breaking them down through related logarithmic forms makes them manageable and easier to understand.
Other exercises in this chapter
Problem 14
Use a calculator to evaluate each expression to four decimal places. $$ \log 5 $$
View solution Problem 14
Solve each equation. Check your solution. $$ 4^{3 x+2}=\frac{1}{256} $$
View solution Problem 15
Solve each equation or inequality. Round to the nearest ten-thousandth. \(2 \ln 3 x+1=5\)
View solution Problem 15
Use \(\log _{5} 2 \approx 0.4307\) and \(\log _{5} 3 \approx 0.6826\) to approximate the value of each expression. \(\log _{5} \frac{2}{3}\)
View solution