Problem 14
Question
Among the period 4 transition metals \((\mathrm{Sc}-\mathrm{Zn}),\) which elements do not form ions where there are partially filled \(3 d\) orbitals?
Step-by-Step Solution
Verified Answer
The period 4 transition metals that do not form ions with partially filled 3d orbitals are Scandium (Sc), Titanium (Ti), Vanadium (V), Copper (Cu), and Zinc (Zn).
1Step 1: Write down the electron configurations of the period 4 transition metals
We can determine the electron configurations of the period 4 transition metals through the periodic table:
1. Scandium (Sc): [Ar] 4s² 3d¹
2. Titanium (Ti): [Ar] 4s² 3d²
3. Vanadium (V): [Ar] 4s² 3d³
4. Chromium (Cr): [Ar] 4s¹ 3d⁵
5. Manganese (Mn): [Ar] 4s² 3d⁵
6. Iron (Fe): [Ar] 4s² 3d⁶
7. Cobalt (Co): [Ar] 4s² 3d⁷
8. Nickel (Ni): [Ar] 4s² 3d⁸
9. Copper (Cu): [Ar] 4s¹ 3d¹⁰
10. Zinc (Zn): [Ar] 4s² 3d¹⁰
2Step 2: Identify the elements that form stable cations without partially filled 3d orbitals
Now, we need to determine which of these elements do not form ions with partially filled 3d orbitals. To do this, we'll examine their possible cations and the resulting electron configurations:
1. Scandium (Sc): Sc³⁺ has the electron configuration [Ar], with no remaining 3d electrons.
2. Titanium (Ti): Ti⁴⁺ has the electron configuration [Ar], with no remaining 3d electrons.
3. Vanadium (V): V⁵⁺ has the electron configuration [Ar], with no remaining 3d electrons.
4. Chromium (Cr): Cr²⁺ has the electron configuration [Ar] 3d⁴.
5. Manganese (Mn): Mn²⁺ has the electron configuration [Ar] 3d⁵.
6. Iron (Fe): Fe³⁺ has the electron configuration [Ar] 3d⁵.
7. Cobalt (Co): Co³⁺ has the electron configuration [Ar] 3d⁶.
8. Nickel (Ni): Ni²⁺ has the electron configuration [Ar] 3d⁸.
9. Copper (Cu): Cu⁺ has the electron configuration [Ar] 3d¹⁰.
10. Zinc (Zn): Zn²⁺ has the electron configuration [Ar] 3d¹⁰.
3Step 3: List the elements that do not form ions with partially filled 3d orbitals
From the information in Step 2, we can determine that Scandium (Sc), Titanium (Ti), Vanadium (V), Copper (Cu), and Zinc (Zn) are the period 4 transition metals that do not form ions with partially filled 3d orbitals.
Key Concepts
Electron ConfigurationPeriod 4 ElementsIon Formation
Electron Configuration
Electron configuration refers to how electrons are distributed in different atomic orbitals. Understanding electron configuration is critical to comprehending chemical properties and behaviors. For atoms in their ground state, electrons are filled in such a way to achieve the lowest possible energy.
For the period 4 transition metals, electron configurations start with the noble gas configuration of Argon \(\text{[Ar]}\), followed by additional electrons in the 4s and 3d orbitals.
For the period 4 transition metals, electron configurations start with the noble gas configuration of Argon \(\text{[Ar]}\), followed by additional electrons in the 4s and 3d orbitals.
- Scandium (Sc): \([\text{Ar}] \ 4s^2 \ 3d^1\)
- Titanium (Ti): \([\text{Ar}] \ 4s^2 \ 3d^2\)
- Vanadium (V): \([\text{Ar}] \ 4s^2 \ 3d^3\)
- ... ending with Zinc (Zn): \([\text{Ar}] \ 4s^2 \ 3d^{10}\)
Period 4 Elements
Period 4 elements on the periodic table are fascinating, particularly the transition metals from Scandium (Sc) to Zinc (Zn). These elements have electrons entering the 3d sublevel, setting them apart from other elements.
They are known for their unique chemical behaviors and variable oxidation states. In period 4, transition metals' noteworthy features include:
They are known for their unique chemical behaviors and variable oxidation states. In period 4, transition metals' noteworthy features include:
- High melting points
- Variable oxidation states
- Formation of colored compounds
- Magnetic properties, particularly among the first few elements
Ion Formation
Ion formation in transition metals is an intriguing process due to their variable oxidation states. When transition metals form ions, they typically lose electrons from both the s and d orbitals. The number of electrons removed corresponds to their oxidation state.
For example:
For example:
- Scandium (Sc) loses 3 electrons to form \(\text{Sc}^{3+}\), resulting in \(\text{[Ar]}\)
- Titanium (Ti) can form \(\text{Ti}^{4+}\), emptying the 3d orbital
- Copper (Cu) forms a stable \(\text{Cu}^+ \) ion with a full 3d orbital \(\text{[Ar] 3d}^{10}\)
Other exercises in this chapter
Problem 12
Which periodic trend is partially responsible for the observation that the maximum oxidation state of the transition-metal elements peaks near groups 7 and \(8
View solution Problem 13
For each of the following compounds, determine the electron configuration of the transition-metal ion. (a) CuO, (b) \(\mathrm{Cu}_{2} \mathrm{O}\) (c) \(\mathrm
View solution Problem 15
Write out the ground-state electron configurations of (a) \(\mathrm{Sc}^{2+}\) (b) \(\mathrm{Mo}^{2+}\) (c) \(\mathrm{Rh}^{3+}\), (d) \(\mathrm{Fe}^{3+}\).
View solution Problem 16
How many electrons are in the valence \(d\) orbitals in these transition-metal ions? \((\mathbf{a}) \mathrm{Ru}^{3+},(\mathbf{b}) \mathrm{Pd}^{2+},(\mathbf{c})
View solution