Problem 14
Question
After exercising on a hot summer day and working up a sweat, you often become cool when you stop. What is the molecular-level explanation of this phenomenon?
Step-by-Step Solution
Verified Answer
Evaporation of sweat absorbs heat, cooling the skin.
1Step 1: Understand the Process of Sweating
Sweating is the body's natural mechanism to cool itself down by releasing moisture (sweat) onto the skin's surface. This process requires heat energy, which is taken from the body's surface.
2Step 2: Evaporation of Sweat
When the sweat on your skin evaporates, it changes from a liquid to a gas. This process requires energy in the form of heat. The heat needed for the evaporation comes from your skin and the immediate environment.
3Step 3: Heat Absorption and Cooling Effect
As the sweat evaporates, it absorbs heat from your skin due to the endothermic nature of the process, meaning it takes in heat rather than releases it. This absorption of heat energy from your skin leads to a decrease in skin temperature, creating a cooling sensation.
4Step 4: Resulting Body Temperature Drop
After exercising, your body's surface temperature is high, but as sweat continues to evaporate, your skin cools down more rapidly, often resulting in a chilling sensation once physical activity ceases.
Key Concepts
SweatingPhase ChangeEndothermic Process
Sweating
Sweating is a crucial bodily function that helps regulate temperature. When we exercise or find ourselves in a hot environment, our bodies produce sweat through sweat glands located all over our skin. This liquid comprises mostly water, with small amounts of salts and other substances. Its main function is cooling.
This is because the sweat on the skin's surface can capture heat from the body. It's an efficient way of transferring excess body heat to the environment and helps in maintaining an optimal core temperature.
This is because the sweat on the skin's surface can capture heat from the body. It's an efficient way of transferring excess body heat to the environment and helps in maintaining an optimal core temperature.
- Regulation of body temperature: Sweat cools us down by releasing moisture on the skin.
- Evaporation mechanism: Heat from the body gets used in the evaporation process.
Phase Change
Phase change refers to the transition from one state of matter to another. In the context of sweating, it involves changing from a liquid (sweat) to a gas. This specific shift is known as evaporation.
Evaporation occurs when molecules at the surface of a liquid gain enough energy to escape into a gaseous state.
Evaporation occurs when molecules at the surface of a liquid gain enough energy to escape into a gaseous state.
- Liquid to gas transition: Sweat evaporating from the skin.
- Energy requirement: Molecules absorb energy to change phase.
Endothermic Process
An endothermic process is one that absorbs energy from its surroundings. In the case of sweating, the evaporation of sweat from the skin is an endothermic reaction.
As sweat evaporates, it absorbs heat from your skin and the surrounding environment. This energy absorption is what drives the moisture from a liquid into a vapor, resulting in the phase change.
As sweat evaporates, it absorbs heat from your skin and the surrounding environment. This energy absorption is what drives the moisture from a liquid into a vapor, resulting in the phase change.
- Heat absorption: Energy is taken from the body to facilitate evaporation.
- Cooling effect: The absorbed heat lowers skin temperature.
Other exercises in this chapter
Problem 12
Rank these substances in order of increasing noncovalent intermolecular attractions. For each substance, name the types of intermolecular attractions that occur
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Explain on the molecular scale the processes of condensation and vaporization.
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The chlorofluorocarbon \(\mathrm{CCl}_{3} \mathrm{~F}\) has a vaporization enthalpy of \(24.8 \mathrm{~kJ} / \mathrm{mol}\). Calculate the heat energy transfer
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The molar vaporization enthalpy of methanol is \(38.0 \mathrm{~kJ} / \mathrm{mol}\) at \(25^{\circ} \mathrm{C} .\) Calculate the heat energy transfer required t
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