Problem 14
Question
A heat pump is an electrical device that heats a building by pumping heat in from the cold outside. In other words, it's the same as a refrigerator, but its purpose is to warm the hot reservoir rather than to cool the cold reservoir (even though it does both). Let us define the following standard symbols, all taken to be positive by convention: \(T_{h}=\) temperature inside building \(T_{c}=\) temperature outside \(Q_{h}=\) heat pumped into building in 1 day \(Q_{c}=\) heat taken from outdoors in 1 day \(W=\) electrical energy used by heat pump in 1 day (a) Explain why the "coefficient of performance" (COP) for a heat pump should be defined as \(Q_{h} / W\) (b) What relation among \(Q_{h}, Q_{c},\) and \(W\) is implied by energy conservation alone? Will energy conservation permit the COP to be greater than \(1 ?\) (c) Use the second law of thermodynamics to derive an upper limit on the \(\mathrm{COP},\) in terms of the temperatures \(T_{h}\) and \(T_{\mathrm{c}}\) alone. (d) Explain why a heat pump is better than an electric furnace, which simply converts electrical work directly into heat. (Include some numerical estimates.)
Step-by-Step Solution
VerifiedKey Concepts
Coefficient of Performance
- \( \text{COP} = \frac{Q_{h}}{W} \),
There’s another important aspect to keep in mind: the practical range of COP values. For a heat pump, the COP can exceed 1, meaning it delivers more heat energy than the electrical energy it uses. This is contrary to many other systems, where energy efficiency typically maxes out at a ratio of 1.
First Law of Thermodynamics
- \( Q_{h} = Q_{c} + W \).
- the heat extracted from the outside \(Q_{c}\),
- and the work done by the heat pump \(W\).
Second Law of Thermodynamics
\[\text{COP}_{\text{max}} = \frac{T_{h}}{T_{h} - T_{c}}\]
shows us the highest efficiency a heat pump can achieve when running in a reversible process. This formula takes into account:
- \(T_{h}\) - the temperature inside the building,
- \(T_{c}\) - the temperature outside,
Carnot Cycle
When we consider heat pumps, the Carnot efficiency informs us about the theoretical best performance we can aim for. It tells us that if we approach this efficiency, we minimize energy waste. For practical purposes, while real-world devices cannot reach Carnot efficiency due to factors like friction and heat loss, this cycle is the benchmark.
Thus, using the principles derived from the Carnot cycle, engineers strive to make devices as efficient as possible by reducing energy losses and maximizing the heat transfer between reservoirs effectively.
Energy Efficiency
To illustrate this: if a heat pump has a COP of 3, it means it delivers three times more heat than the electrical energy it consumes. Contrast this with an electric furnace, whose efficiency usually peaks at a COP of 1, delivering heat equivalent to the input of electrical energy.
So, in terms of raw numbers, the higher COP indicates more heat output per unit of energy, representing not only a cost-effective but also a more environmentally sustainable heating solution. This efficiency can help lower energy bills and decrease the carbon footprint of heating systems in buildings, aligning well with modern environmental goals.