Problem 14
Question
(a) Define the variables. (b) Write a differential equation to describe the relationship. (c) Solve the differential equation. In \(2010,\) the population of India was 1.15 billion people and increasing at a rate proportional to its population. If the population is measured in billions of people and time is measured in years, the constant of proportionality is 0.0135.
Step-by-Step Solution
Verified Answer
The population model is \( P(t) = 1.15e^{0.0135t} \).
1Step 1: Define Variables
Let's define the variables to model the population growth of India. Let \( P(t) \) represent the population in billions of people at time \( t \), where \( t \) is the number of years after 2010. Therefore, at \( t = 0 \), \( P(0) = 1.15 \) billion.
2Step 2: Construct the Differential Equation
The population growth rate is proportional to the current population. Therefore, we can express this relationship with the differential equation \( \frac{dP}{dt} = kP \), where \( k \) is the constant of proportionality, given as 0.0135.
3Step 3: Solve the Differential Equation
We solve the differential equation \( \frac{dP}{dt} = 0.0135P \) using separation of variables. First, separate the variables: \( \frac{1}{P} \, dP = 0.0135 \, dt \). Integrate both sides: \( \int \frac{1}{P} \, dP = \int 0.0135 \, dt \). This results in \( \ln |P| = 0.0135t + C \). Exponentiate both sides to solve for \( P \): \( P = e^{0.0135t + C} = e^C \cdot e^{0.0135t} \). Let \( A = e^C \). Thus, \( P(t) = Ae^{0.0135t} \).
4Step 4: Determine the Constant A
Use the initial condition to determine \( A \). At \( t = 0 \), \( P(0) = 1.15 \). Substitute into the equation: \( 1.15 = A \cdot e^{0.0135 \cdot 0} = A \). Therefore, \( A = 1.15 \). So, the function becomes \( P(t) = 1.15e^{0.0135t} \).
Key Concepts
Population GrowthSeparation of VariablesInitial Condition
Population Growth
Population growth describes the increase or decrease in the size of a population over time. It is often modeled in mathematics using differential equations. Why are differential equations crucial? Because they can describe how the rate of change of a population relates to the population itself. In our problem, we're looking at the population of India, which is growing over time.
This relationship is expressed with a differential equation, making it a powerful tool in understanding population trends.
- The population is measured in billions of people.
- Time is measured in years since 2010.
This relationship is expressed with a differential equation, making it a powerful tool in understanding population trends.
Separation of Variables
Separation of variables is a technique for solving differential equations. It involves rearranging an equation so that each variable is on a different side. In our problem, we started with the differential equation \( \frac{dP}{dt} = kP \), where \( P \) is population and \( k \) is a constant.
Here's a step-by-step breakdown of how it works:
Finally, we solve for \( P \) by exponentiating both sides to get \( P = e^{kt + C} = A \cdot e^{kt} \). This step-by-step method simplifies complex relationships into manageable parts.
Here's a step-by-step breakdown of how it works:
- First, we move the terms around to get \( \frac{1}{P} \, dP = k \, dt \), which places \( P \) and \( t \) on opposite sides of the equation.
- Next, we integrate both sides: \( \int \frac{1}{P} \, dP = \int k \, dt \).
Finally, we solve for \( P \) by exponentiating both sides to get \( P = e^{kt + C} = A \cdot e^{kt} \). This step-by-step method simplifies complex relationships into manageable parts.
Initial Condition
An initial condition is vital for finding a particular solution to a differential equation. It provides a specific starting point you can use to solve for an unknown constant. In our case, we need the initial condition to determine \( A \) in the equation \( P(t) = A e^{0.0135t} \).
With the problem for India's population, we know:
This tells us that the constant \( A \), which determines our specific solution, is 1.15. Applying the initial condition pinpoints the unique behavior of the system from that starting point.
With the problem for India's population, we know:
- In 2010 (\( t = 0 \)), the population \( P(0) = 1.15 \) billion.
This tells us that the constant \( A \), which determines our specific solution, is 1.15. Applying the initial condition pinpoints the unique behavior of the system from that starting point.
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