Problem 14
Question
\(9-14\) Evaluate the minor and cofactor using the matrix \(A\) $$ A=\left[\begin{array}{rrr}{1} & {0} & {\frac{1}{2}} \\ {-3} & {5} & {2} \\\ {0} & {0} & {4}\end{array}\right] $$ $$ M_{32}, A_{32} $$
Step-by-Step Solution
Verified Answer
The minor is 4 and the cofactor is -4.
1Step 1: Determine Minor M_32
To find minor \( M_{32} \), remove the 3rd row and 2nd column of the matrix. The remaining 2x2 matrix is \( \left[ \begin{array}{cc} 1 & \frac{1}{2} \ 0 & 4 \end{array} \right] \). The minor is the determinant of this matrix: \( M_{32} = \left(1\cdot4\right) - \left(\frac{1}{2}\cdot0\right) = 4 - 0 = 4 \)
2Step 2: Determine Cofactor A_32
The cofactor \( A_{32} \) is given by the formula \( A_{32} = (-1)^{3+2} \cdot M_{32} \). Here, \((-1)^{3+2} = (-1)^5 = -1\). Thus, \( A_{32} = -1 \cdot 4 = -4 \).
Key Concepts
Matrix DeterminantMatrix MinorMatrix Cofactor
Matrix Determinant
The concept of a determinant is fundamental in working with matrices. The determinant of a matrix is a scalar value that provides important properties about the matrix. In practical terms, it can indicate whether a matrix is invertible or not. For 2x2 matrices, such as the minor matrix found in the problem, the determinant can be calculated using the formula: \(\text{det}(\begin{bmatrix} a & b \ c & d \end{bmatrix}) = ad - bc\).
Let's break it down:
Let's break it down:
- Choose the elements of the matrix: here, we have the matrix \(\begin{bmatrix} 1 & \frac{1}{2} \ 0 & 4 \end{bmatrix}\).
- The formula becomes \(1\cdot4 - \frac{1}{2}\cdot0 = 4\).
- Thus, in this example, the determinant of the 2x2 matrix is \(4\).
Matrix Minor
A matrix minor is essential for higher-dimensional determinants. The minor of an element in a matrix is the determinant of a smaller matrix, derived by removing the row and column containing that element. This reduced matrix, particularly in this exercise, leads to a 2x2 matrix. Here's how you find it:
- Focus on the desired element—in the exercise, the element is positioned at \((3,2)\).
- Remove the 3rd row and 2nd column from the original 3x3 matrix \(A\).
- The remaining elements form the matrix \(\begin{bmatrix} 1 & \frac{1}{2} \ 0 & 4 \end{bmatrix}\).
Matrix Cofactor
Cofactors build on the concept of minors to assist in calculations needed for matrix operations such as finding the determinant of larger matrices or solving systems of linear equations. A cofactor is essentially a signed version of the minor. The sign is determined by the position of the element in the matrix: if the sum of the row and column is even, the sign is positive; if odd, the sign is negative. Here's how you calculate it:
- Use the minor already found: \(M_{32} = 4\).
- Identify the position of the element in the original matrix, here \((3,2)\).
- Calculate the sign using \((-1)^{3+2} = -1\).
- The cofactor is then \(A_{32} = -1 \cdot 4 = -4\).
Other exercises in this chapter
Problem 14
1–14 Graph the inequality. $$x^{2}+(y-1)^{2} \leq 1$$
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Find the partial fraction decomposition of the rational function. \(\frac{x+6}{x(x+3)}\)
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A matrix is given. (a) Determine whether the matrix is in row-echelon form. (b) Determine whether the matrix is in reduced row-echelon form. (c) Write the syste
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Find the inverse of the matrix if it exists. \(\left[\begin{array}{lll}{4} & {2} & {3} \\ {3} & {3} & {2} \\ {1} & {0} & {1}\end{array}\right]\)
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