Problem 14
Question
3-14. Show that if \(\therefore \cdot g: A \rightarrow \mathbf{R}\) are integrable, so is \(f \cdot g .\)
Step-by-Step Solution
Verified Answer
Since \( f \) and \( g \) are integrable, so is \( f \cdot g \), as confirmed by Hölder's Inequality ensuring a finite integral.
1Step 1: Understanding Integrability
A function is integrable over a set if the integral of its absolute value is finite. This ensures that the function can be integrated without encountering infinite discontinuities or unbounded areas.
2Step 2: Given Functions and Their Properties
We are given that \(f\) and \(g\) are integrable. Hence, \(\begin{cases} \int_{A} |f(x)| \, dx < \infty \int_{A} |g(x)| \, dx < \infty \end{cases}\)
3Step 3: Product Rule and Absolute Value
Consider \(f \cdot g\). We need to check whether \(|f(x) \cdot g(x)|\) is integrable over \(A\). Note that: \(|f(x) \cdot g(x)| = |f(x)| \cdot |g(x)|\)
4Step 4: Use Integrability Criteria
Since integration is linear for non-negative functions, we need: \(\begin{aligned} \int_{A} |f(x) \cdot g(x)| \, dx &= \int_{A} |f(x)| \cdot |g(x)| \, dx \end{aligned}\)
5Step 5: Applying Hölder's Inequality
Hölder's Inequality states that for \(p, q\) satisfying \(1/p + 1/q = 1\), the following holds: \(\begin{aligned} \int_{A} |fg| \, dx \leq \left( \int_{A} |f|^p \, dx \right)^{1/p} \left( \int_{A} |g|^q \, dx \right)^{1/q} \end{aligned}\)
6Step 6: Choosing Appropriate p and q
To simplify, choose \(p = q = 2\), satisfying \(1/p + 1/q = 1\). Therefore we get: \(\begin{aligned} \int_{A} |f \cdot g| \, dx \leq \left( \int_{A} |f|^2 \, dx \right)^{1/2} \left( \int_{A} |g|^2 \, dx \right)^{1/2} \end{aligned}\)
7Step 7: Ensuring Finite Integrals
Given that both \( \int_{A} |f(x)| \, dx < \infty \) and \( \int_{A} |g(x)| \, dx < \infty \), the Hölder's inequality assures that \( \int_{A} |f \cdot g| \, dx < \infty \). Thus, \( f \cdot g \) is integrable over \( A \).
Key Concepts
Integrability CriteriaHölder's InequalityProduct Rule in IntegrationMathematical Proofs
Integrability Criteria
To determine if a function is integrable on a given set, we need to ensure that the integral of its absolute value is finite. This means for a function to be integrable over a region, \(A\), \( \int_{A} |f(x)| \, dx < \infty \). By this criteria, we can avoid infinite discontinuities and unbounded areas while integrating.
For example, given functions \(f\) and \(g\), if both are integrable over \(A\), we have:
\( \int_{A} |f(x)| \, dx < \infty \)
\( \int_{A} |g(x)| \, dx < \infty \)
Thus, the key requirement is ensuring the finiteness of these integrals.
For example, given functions \(f\) and \(g\), if both are integrable over \(A\), we have:
\( \int_{A} |f(x)| \, dx < \infty \)
\( \int_{A} |g(x)| \, dx < \infty \)
Thus, the key requirement is ensuring the finiteness of these integrals.
Hölder's Inequality
Hölder's Inequality is an essential tool in mathematical analysis, particularly in proving the integrability of functions. It states that for any integrable functions \(f\) and \(g\) and for any conjugate exponents \(p\) and \(q\) (i.e., \(1/p + 1/q = 1 \)), we have:
\[ \int_{A} |f(x) g(x)| \, dx \leq \left( \int_{A} |f(x)|^p \, dx \right)^{1/p} \left( \int_{A} |g(x)|^q \, dx \right)^{1/q} \]
This inequality helps us in bounding the integral of the product of two functions by the product of their individual integrals raised to respective powers.
\[ \int_{A} |f(x) g(x)| \, dx \leq \left( \int_{A} |f(x)|^p \, dx \right)^{1/p} \left( \int_{A} |g(x)|^q \, dx \right)^{1/q} \]
This inequality helps us in bounding the integral of the product of two functions by the product of their individual integrals raised to respective powers.
Product Rule in Integration
When dealing with the product of two integrable functions, \(f\) and \(g\), we need to determine if \(f \cdot g\) is integrable over the same set. Using the absolute value property, we have:
\[ |f(x) \cdot g(x)| = |f(x)| \cdot |g(x)| \]
To check integrability, we consider the integral:
\[ \int_{A} |f(x) \cdot g(x)| \, dx = \int_{A} |f(x)| \cdot |g(x)| \, dx \]
According to the Hölder's Inequality, and by choosing appropriate values for \(p\) and \(q\) (commonly \(p = q = 2\)), we conclude:
\[ \int_{A} |f(x) g(x)| \, dx \leq \left( \int_{A} |f(x)|^2 \, dx \right)^{1/2} \left( \int_{A} |g(x)|^2 \, dx \right)^{1/2} \]
Thus, since \(f\) and \(g\) are integrable, their product is also integrable.
\[ |f(x) \cdot g(x)| = |f(x)| \cdot |g(x)| \]
To check integrability, we consider the integral:
\[ \int_{A} |f(x) \cdot g(x)| \, dx = \int_{A} |f(x)| \cdot |g(x)| \, dx \]
According to the Hölder's Inequality, and by choosing appropriate values for \(p\) and \(q\) (commonly \(p = q = 2\)), we conclude:
\[ \int_{A} |f(x) g(x)| \, dx \leq \left( \int_{A} |f(x)|^2 \, dx \right)^{1/2} \left( \int_{A} |g(x)|^2 \, dx \right)^{1/2} \]
Thus, since \(f\) and \(g\) are integrable, their product is also integrable.
Mathematical Proofs
Mathematical proofs are logical arguments used to prove the truth of mathematical statements. They follow precise steps established through theorems, axioms, and previously established results.
In the context of proving the integrability of \(f \cdot g\), we use:
In the context of proving the integrability of \(f \cdot g\), we use:
- Definition of integrability
- Algebraic manipulation of the integrand
- Application of Hölder's Inequality
- Adjust values of \(p\) and \(q\) to fit the problem
Other exercises in this chapter
Problem 10
\(3-10 .\) (a) If \(C^{\prime}\) is a set of content 0, show that the boundary of \(C\) has content 0 . (b) Give an example of a bounded set \(C\) of measure 0
View solution Problem 13
3 -13. \(^{*}\) (a) Show that the collection of all rectangles \(\left[a_{1}, b_{1}\right] \times \times \times\) \(\left[a_{n}, b_{n}\right]\) with all \(a_{i}
View solution Problem 18
3-18. If \(f: A \rightarrow \mathbf{R}\) is non-negative and \(\int_{A} f=0\), show that \(\\{x: f(x) \neq 0\\}\) has measure 0. Hint: Prove that \(\\{x: f(x)>1
View solution Problem 23
3-23. Let \(C \subset A \times B\) be a set of content \(0 .\) Let \(A^{\prime} \subset A\) be the set of all \(x \in A\) such that \(\\{y \in B:(x, y) \in C\\}
View solution