Problem 139
Question
Write the correct chemical formula for each compound. (Chapter 7\()\) a. a. calcium carbonate b. potassium chlorate c. silver acetate d. copper (II) sulfate e. ammonium phosphate
Step-by-Step Solution
Verified Answer
a. \( \text{CaCO}_3 \), b. \( \text{KClO}_3 \), c. \( \text{AgC}_2\text{H}_3\text{O}_2 \), d. \( \text{CuSO}_4 \), e. \( (\text{NH}_4)_3\text{PO}_4 \).
1Step 1: Identify the Ions in the Compounds
First, identify the ions that make up each compound. - For calcium carbonate: Calcium is represented as \( \text{Ca}^{2+} \) and carbonate is represented as \( \text{CO}_3^{2-} \).- For potassium chlorate: Potassium is \( \text{K}^+ \) and chlorate is \( \text{ClO}_3^{-} \).- For silver acetate: Silver is \( \text{Ag}^+ \) and acetate is \( \text{C}_2\text{H}_3\text{O}_2^{-} \), commonly abbreviated as \( \text{CH}_3\text{COO}^{-} \).- For copper (II) sulfate: Copper (II) is \( \text{Cu}^{2+} \) and sulfate is \( \text{SO}_4^{2-} \).- For ammonium phosphate: Ammonium is \( \text{NH}_4^+ \) and phosphate is \( \text{PO}_4^{3-} \).
2Step 2: Determine the Chemical Formula by Balancing Charges
Balance the charges of the ions to obtain a neutral compound for each of the given compounds:- Calcium carbonate: Combine as \( \text{CaCO}_3 \) because the charges \( 2^+ \) and \( 2^- \) balance out.- Potassium chlorate: Combine as \( \text{KClO}_3 \) since \( \text{K}^+ \) and \( \text{ClO}_3^- \) are both 1.- Silver acetate: Form \( \text{AgC}_2\text{H}_3\text{O}_2 \) because \( \text{Ag}^+ \) and \( \text{C}_2\text{H}_3\text{O}_2^- \) each have 1 charge.- Copper (II) sulfate: Use \( \text{CuSO}_4 \) as \( 2^+ \) and \( 2^- \) charges balance.- Ammonium phosphate: Combine 3 ammonium ions with 1 phosphate ion to balance the total positive \( 3 \times (+1) = +3 \) with \( (-3) \), resulting in \( (\text{NH}_4)_3\text{PO}_4 \).
Key Concepts
Ion IdentificationCharge BalancingIonic CompoundsPolyatomic Ions
Ion Identification
Identifying ions is a crucial first step in determining the chemical formula of a compound. The ions can either be cations (positive ions) or anions (negative ions). For every compound, you must know which ions are present to figure out how they combine. This involves recognizing the elemental symbol and its associated charge.
- Cations: Metals like calcium, potassium, and copper often form cations, such as \( \text{Ca}^{2+} \), \( \text{K}^+ \), and \( \text{Cu}^{2+} \).
- Anions: These are negatively charged ions like carbonate \( \text{CO}_3^{2-} \) and sulfate \( \text{SO}_4^{2-} \).
Charge Balancing
Charge balancing is about ensuring that the total positive charge equals the total negative charge in a chemical compound, leading to an overall neutral molecule. Remember, in a stable compound, the positive and negative charges must cancel out.
- For calcium carbonate \( \text{CaCO}_3 \), \( \text{Ca}^{2+} \) pairs with \( \text{CO}_3^{2-} \), cancelling out the charges.
- For ammonium phosphate \( (\text{NH}_4)_3\text{PO}_4 \), three ammonium ions \( 3 \times \text{NH}_4^+ \) provide a total charge of \(+3\), which balances the phosphate’s \(-3\) charge.
Ionic Compounds
Ionic compounds are formed from the electrostatic attraction between cations and anions. They typically contain a metal and a non-metal or a non-metal component acting as a polyatomic ion. These compounds have distinct formulas reflecting the minimal ratio of ions needed to achieve charge balance.
- Example: Silver acetate \( \text{AgC}_2\text{H}_3\text{O}_2 \) involves \( \text{Ag}^+ \) and \( \text{C}_2\text{H}_3\text{O}_2^- \) ions.
- The compound forms when these positively and negatively charged ions attract and stick together in a fixed proportion, dictated by their charges.
Polyatomic Ions
Polyatomic ions are clusters of atoms bonded together that carry a charge, acting as a single ion in chemical reactions. They can be either positively or negatively charged.Examples from the exercise include:
- Chlorate: \( \text{ClO}_3^- \)
- Acetate: \( \text{C}_2\text{H}_3\text{O}_2^- \) or \( \text{CH}_3\text{COO}^- \)
- Phosphate: \( \text{PO}_4^{3-} \)
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