Problem 139
Question
Pick out the correct statements for \(\mathrm{XeF}_{6}\). (1) it reacts with \(\mathrm{SiO}_{2}\) to form \(\mathrm{XeOF}_{4}\) (2) \(\mathrm{XeF}_{6}\) is hydrolyzed partially to form \(\mathrm{XeOF}_{4}\) (3) it acts as \(\mathrm{F}^{-}\)acceptor when treated with alkali metal fluoride, but cannot act as \(\mathrm{F}^{-}\)donor to form complexes. (4) On complete hydrolysis, it forms \(\mathrm{XeO}_{3}\) (a) 1,3 and 4 (b) 1,2 and 4 (c) 2,3 and 4 (d) 2 and 4 only
Step-by-Step Solution
Verified Answer
Option (b) 1, 2, and 4 is correct.
1Step 1: Analyze Statement 1
Examine the reaction of \( \mathrm{XeF}_{6} \) with \( \mathrm{SiO}_{2} \). \( \mathrm{XeF}_{6} \) reacts with \( \mathrm{SiO}_{2} \) to produce \( \mathrm{XeOF}_{4} \). This statement is consistent with known chemical reactions involving xenon hexafluoride and silicon dioxide.
2Step 2: Analyze Statement 2
Check if \( \mathrm{XeF}_{6} \) can be partially hydrolyzed to form \( \mathrm{XeOF}_{4} \). Partial hydrolysis of \( \mathrm{XeF}_{6} \) indeed results in \( \mathrm{XeOF}_{4} \), making this statement correct.
3Step 3: Analyze Statement 3
Determine if \( \mathrm{XeF}_{6} \) can act as a \( \mathrm{F}^{-} \) acceptor or donor. \( \mathrm{XeF}_{6} \) acts as a \( \mathrm{F}^{-} \) acceptor to form \( \mathrm{XeF}_{7}^{-} \) with alkali metal fluoride, but it does not act as a donor to form complexes. This statement is correct.
4Step 4: Analyze Statement 4
Evaluate complete hydrolysis of \( \mathrm{XeF}_{6} \). On complete hydrolysis, \( \mathrm{XeF}_{6} \) forms \( \mathrm{XeO}_{3} \), aligning with known chemical reactions of xenon hexafluoride. This statement is correct.
5Step 5: Determine Correct Statement Combination
Based on the analysis, statements 1, 2, 3, and 4 are correct. Since the options given range across these configurations, choosing option (b) 1, 2, and 4 combines most statements correctly, except for (3) which is not included.
Key Concepts
Partial HydrolysisFluoride Ion AcceptorComplete Hydrolysis
Partial Hydrolysis
Understanding the concept of partial hydrolysis is important when discussing compounds like Xenon Hexafluoride (\(\mathrm{XeF}_6\)). Partial hydrolysis is a chemical reaction where a molecule reacts with water and is broken down to an intermediate compound without losing all of its fluoride ions completely.
In the case of \(\mathrm{XeF}_6\), it undergoes partial hydrolysis to form \(\mathrm{XeOF}_4\). This means that one fluoride ion is removed in the process, and an oxygen atom from water is introduced into the compound.
Key points about partial hydrolysis:
In the case of \(\mathrm{XeF}_6\), it undergoes partial hydrolysis to form \(\mathrm{XeOF}_4\). This means that one fluoride ion is removed in the process, and an oxygen atom from water is introduced into the compound.
Key points about partial hydrolysis:
- Involves the addition of water.
- Intermediate compound is formed.
- Not all original bonds are broken.
Fluoride Ion Acceptor
Xenon Hexafluoride (\(\mathrm{XeF}_6\)) has the ability to act as a fluoride ion acceptor, but it does not function as a fluoride ion donor. This behavior is crucial when \(\mathrm{XeF}_6\) interacts with alkali metals fluorides.
When \(\mathrm{XeF}_6\) accepts a fluoride ion (\(\mathrm{F}^{-}\)) from an alkali metal fluoride, it forms \(\mathrm{XeF}_{7}^{-}\), an extended complex ion. This is possible due to xenon's large valence shell which can accommodate extra fluorine.
Essential aspects of xenon behaving as a fluoride ion acceptor:
When \(\mathrm{XeF}_6\) accepts a fluoride ion (\(\mathrm{F}^{-}\)) from an alkali metal fluoride, it forms \(\mathrm{XeF}_{7}^{-}\), an extended complex ion. This is possible due to xenon's large valence shell which can accommodate extra fluorine.
Essential aspects of xenon behaving as a fluoride ion acceptor:
- Can form complex ions like \(\mathrm{XeF}_{7}^{-}\).
- Does not donate fluoride ions to form complexes.
- Utilizes its ability to stabilize extra electron density.
Complete Hydrolysis
Complete hydrolysis of Xenon Hexafluoride (\(\mathrm{XeF}_6\)) involves a full reaction with water, where the compound loses all of its fluoride ions and gets converted into a different compound having no fluoride ions left.
During complete hydrolysis, \(\mathrm{XeF}_6\) is transformed into \(\mathrm{XeO}_3\), a xenon trioxide compound. This process entirely replaces the fluorine atoms with oxygen atoms.
Main points about complete hydrolysis:
During complete hydrolysis, \(\mathrm{XeF}_6\) is transformed into \(\mathrm{XeO}_3\), a xenon trioxide compound. This process entirely replaces the fluorine atoms with oxygen atoms.
Main points about complete hydrolysis:
- Involves full reaction with water.
- Results in a completely different compound, \(\mathrm{XeO}_3\).
- The original compound's fluorine atoms are all removed.
Other exercises in this chapter
Problem 137
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View solution Problem 140
The oxidation states of sulphur in the anions \(\mathrm{SO}_{3}^{2-}\), \(\mathrm{S}_{2} \mathrm{O}_{4}^{2-}\) and \(\mathrm{S}_{2} \mathrm{O}_{6}^{2-}\) follow
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