Problem 138
Question
The range of the function \(f(x)=\frac{\sin \left(\pi\left[x^{2}+1\right]\right)}{x^{4}+1}\), where \([\cdot]\) denotes the greatest integer function, is (A) \([0,1]\) (B) \([-1,1]\) (C) \(\\{0\\}\) (D) None of these
Step-by-Step Solution
Verified Answer
(C) \{0\}.
1Step 1: Understanding the Function Components
First, let's break down the function: \(f(x)=\frac{\sin \left(\pi\left[x^{2}+1\right]\right)}{x^{4}+1}\). The numerator involves the sine function of \(\pi[x^2+1]\), where \([\cdot]\) is the greatest integer function, or floor function, which rounds down to the nearest integer. The denominator is \(x^4 + 1\), which is always positive.
2Step 2: Analyzing the Numerator
For the expression \(\sin(\pi [x^2+1])\), \([x^2 + 1]\) can only take integer values because it uses the greatest integer function. This means \(\sin(\pi n)\) for some integer \(n\). Since \(\sin(\pi n) = 0\) for any integer \(n\), the numerator becomes 0 for all \(x\).
3Step 3: Determining the Denominator's Effect
The denominator \(x^4+1\) is always positive for all real numbers \(x\) because power 4 of any real number is non-negative, and adding 1 ensures it's positive. This means the division by \(x^4+1\) does not influence the zero value of the numerator.
4Step 4: Concluding the Range
Since the numerator is zero, regardless of the value of \(x\), the entire function evaluates to zero. Therefore, the range of the function is \(\{0\}\), as it takes only one constant value.
Key Concepts
Greatest Integer FunctionNumerator AnalysisDenominator Properties
Greatest Integer Function
The greatest integer function, often represented as \([ \cdot ]\), is a fundamental mathematical concept. It is also called the floor function. This function takes any real number and rounds it down to the nearest integer. For instance, if you take 3.7, the greatest integer function \[ [3.7] = 3 \]. Similarly, for -2.4, we have \[ [-2.4] = -3 \].
Because \(x^2 + 1\) is always non-integer (except for certain specific values), the greatest integer function changes it to the nearest lower integer. Understanding this helps us realize why \([x^2 + 1] = n\), and thus, \(\sin(\pi n)\) results in 0 for the numerator, maintaining a zero value throughout.
- The key aspect of this function is its rounding down property.
- It transforms any number into the largest integer that is less than or equal to the original number.
- This property makes it crucial in analyzing functions like the one in our exercise.
Because \(x^2 + 1\) is always non-integer (except for certain specific values), the greatest integer function changes it to the nearest lower integer. Understanding this helps us realize why \([x^2 + 1] = n\), and thus, \(\sin(\pi n)\) results in 0 for the numerator, maintaining a zero value throughout.
Numerator Analysis
The analysis of the numerator in functions is a vital step in understanding the function's overall behavior. In the exercise, the numerator is \(\sin(\pi [x^2 + 1])\).To break it down further:- The expression \([x^2 + 1]\) produces integer values due to the greatest integer function.- Applying \(\pi\) times an integer inside a sine function leads to interesting results.The sine function itself, \(\sin(\theta)\), returns a value between -1 and 1 for angles in radians.
However, the sine of any multiple of \(\pi\), such as \(\pi n\) where \(n\) is an integer, is precisely 0. This is because sine returns zero at every integer multiple of \(\pi\). Thus, regardless of \(x\), \(\sin(\pi [x^2 + 1])\) results in 0.With a zero in the numerator:
However, the sine of any multiple of \(\pi\), such as \(\pi n\) where \(n\) is an integer, is precisely 0. This is because sine returns zero at every integer multiple of \(\pi\). Thus, regardless of \(x\), \(\sin(\pi [x^2 + 1])\) results in 0.With a zero in the numerator:
- The function itself simplifies significantly.
- Even when divided by any positive denominator, the function's output remains zero.
Denominator Properties
The denominator of a function is crucial since it can determine the overall function's domain and range. In this exercise, the denominator is \(x^4 + 1\). Evaluating its properties:
- For any real algebraic expression \(x^4\), squaring ensures the output is non-negative. Since squaring a number makes even negative inputs positive, \(x^4\) is always zero or greater.
- Adding 1 to \(x^4\) ensures that \(x^4 + 1\) is positive for all real values of \(x\).
Other exercises in this chapter
Problem 136
The period of the function \(f(x)=\sin 5 x+\cos \sqrt{3} x\) is (A) \(\sqrt{3} \pi\) (B) \(\pi\) (C) non-periodic (D) None of these
View solution Problem 137
If \(e^{x}+e^{f(x)}=e\), then range of the function \(f\) is (A) \((-\infty, 1]\) (B) \((-\infty, 1)\) (C) \((1, \infty)\) (D) \([1, \infty)\)
View solution Problem 139
Range of values of \(f(x)=1+\sin x+\sin ^{3} x+\sin ^{3} x, x \in\) \(\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)\) is (A) \((0,1)\) (B) \((-\infty, \infty)\) (C
View solution Problem 140
If \([x]\) denotes the integral part of \(x\), then the domain of the function \(f(x)=\sin ^{-1}\left[2 x^{2}-3\right]+\log _{2}\left[\log _{1 / 2}\left(x^{2}-5
View solution