Problem 138
Question
If the Kelvin temperature of a sample of ideal gas doubles (e.g., from 200 K to 400 K), what happens to the root-mean-square speed, \(u_{\mathrm{rms}}\) ? (a) \(u_{\mathrm{rms}}\) increases by a factor of \(\sqrt{2} ;\) (b) \(u_{\mathrm{rms}}\) increases by a factor of \(2 ;(\mathrm{c}) u_{\mathrm{rms}}\) decreases by a factor of 2 (d) \(u_{\mathrm{rms}}\) increases by a factor of \(4 ;\) (e) \(u_{\mathrm{rms}}\) decreases by a factor of 4.
Step-by-Step Solution
Verified Answer
The root-mean-square speed, \(u_{\mathrm{rms}}\) increases by a factor of \( \sqrt{2} \).
1Step 1: Identify the relationship between temperature and rms speed
We know that \(u_{rms} = \sqrt{ \frac {3kT} {m} }\). This equation shows us that the rms speed is proportional to the square root of the temperature.
2Step 2: Calculate the change in rms speed due to temperature doubling
If we double the temperature i.e., \( T \rightarrow 2T \), the new rms speed \( u_{new} \) will be \( u_{new} = \sqrt{ \frac {3k(2T)} {m} } \). This can also be written as \(u_{new} = \sqrt{2} \cdot \sqrt{ \frac {3kT} {m} } \) = \( \sqrt{2} \cdot u_{rms} \). This shows us that the rms speed increases by a factor of \( \sqrt{2} \).
3Step 3: Choose the correct option
Based on our calculations, the root mean square speed increases by a factor of \( \sqrt{2} \) which corresponds to option (a).
Key Concepts
Root-Mean-Square SpeedKelvin TemperatureProportional RelationshipTemperature Doubling
Root-Mean-Square Speed
The root-mean-square speed, often referred to as rms speed, is a measure of the speed of particles in a gas. It reflects how fast, on average, gas molecules are moving. This concept is essential in understanding the behavior of gases from a microscopic perspective.
While individual gas molecules move at different speeds, the rms speed provides a useful average that simplifies calculations and predictions about gas behavior. It is given by the formula:
While individual gas molecules move at different speeds, the rms speed provides a useful average that simplifies calculations and predictions about gas behavior. It is given by the formula:
- \( u_{rms} = \sqrt{ \frac {3kT} {m} } \)
- \( u_{rms} \) is the root-mean-square speed.
- \( k \) is the Boltzmann constant, a fundamental physical constant that relates energy to temperature.
- \( T \) is the absolute temperature of the gas in Kelvin.
- \( m \) is the mass of a gas molecule.
Kelvin Temperature
Kelvin temperature is a scale that is essential when dealing with gases. Unlike Celsius or Fahrenheit, the Kelvin scale starts at absolute zero, the theoretical point where particles have no kinetic energy at all.
The Kelvin scale is crucial because it maintains a direct relationship with energy. In chemical and physical calculations, using Kelvin avoids the complications that negative temperatures or arbitrary freezing points might introduce on other scales.
When dealing with gases, particularly, Kelvin helps make sense of the proportional relationship between temperature and molecular speed, as the formula for rms speed directly uses Kelvin. This ensures that zero on the scale accurately represents no thermal energy, making it a preferred unit in scientific equations involving temperature.
The Kelvin scale is crucial because it maintains a direct relationship with energy. In chemical and physical calculations, using Kelvin avoids the complications that negative temperatures or arbitrary freezing points might introduce on other scales.
When dealing with gases, particularly, Kelvin helps make sense of the proportional relationship between temperature and molecular speed, as the formula for rms speed directly uses Kelvin. This ensures that zero on the scale accurately represents no thermal energy, making it a preferred unit in scientific equations involving temperature.
Proportional Relationship
In physics, understanding proportional relationships helps us predict how changes in one quantity might affect another. In the context of the ideal gas law, the root-mean-square speed of gas molecules is directly proportional to the square root of the temperature. This is evident from the equation:
Instead, it increases by a factor of \( \sqrt{2} \). This spatial understanding of proportionality helps us make accurate predictions and understand the behavior of gases under different thermal conditions without performing exhaustive calculations each time. In practical terms, it lets us see the direct link between heat energy input and molecular motion.
- \( u_{rms} \propto \sqrt{T} \)
Instead, it increases by a factor of \( \sqrt{2} \). This spatial understanding of proportionality helps us make accurate predictions and understand the behavior of gases under different thermal conditions without performing exhaustive calculations each time. In practical terms, it lets us see the direct link between heat energy input and molecular motion.
Temperature Doubling
Doubling the temperature of a gas sample can be quite significant, especially in terms of molecular kinetics. A common question arises, what happens to various properties such as rms speed when the Kelvin temperature of an ideal gas doubles?
Upon doubling the temperature (
By understanding this, students can better appreciate why temperature adjustments have the effects they do and apply this understanding to solve problems related to kinetic molecular energies in gases.
Upon doubling the temperature (
- \( T \rightarrow 2T \)
- \( u_{new} = \sqrt{2} \cdot u_{rms} \)
By understanding this, students can better appreciate why temperature adjustments have the effects they do and apply this understanding to solve problems related to kinetic molecular energies in gases.
Other exercises in this chapter
Problem 136
Which of the following choices represents the molar volume of an ideal gas at \(25^{\circ} \mathrm{C}\) and 1.5 atm? (a) \((298 \times 1.5 / 273) \times 22.4 \m
View solution Problem 137
The gas with the greatest density at STP is (a) \(\mathrm{N}_{2} \mathrm{O}\) (b) \(\mathrm{Kr} ;\) (c) \(\mathrm{SO}_{3} ;\) (d) \(\mathrm{Cl}_{2}\).
View solution Problem 139
Consider the statements (a) to (e) below. Assume that \(\mathrm{H}_{2}(\mathrm{g})\) and \(\mathrm{O}_{2}(\mathrm{g})\) behave ideally. State whether each of th
View solution Problem 140
A sample of \(\mathrm{O}_{2}(\mathrm{g})\) is collected over water at \(23^{\circ} \mathrm{C}\) and a barometric pressure of 751 Torr. The vapor pressure of wat
View solution