Problem 138
Question
Factor completely. $$2 x^{2}-20 x+50$$
Step-by-Step Solution
Verified Answer
The complete factorization of \(2x^{2}-20x+50\) is \((x-5)(2x-10)\)
1Step 1: Identifying the Coefficients and Constant
Identify the coefficients and constant in the expression. Here, the coefficient of \(x^{2}\) is 2, the coefficient of \(x\) is -20, and the constant is 50.
2Step 2: Find the Product and Factors
Find the product of the coefficient of \(x^{2}\) and the constant term. The product is 2*50 = 100. Now, look for the pair of factors of 100 that add up to the coefficient of x, which is -20. The pair here is -10 and -10 because -10*-10 = 100 and -10+(-10) = -20.
3Step 3: Rewrite the Polynomial
Now, rewrite the given polynomial replacing the middle term with the factors of the product. The expression \(2x^{2}-20x+50\) becomes \(2x^{2}-10x-10x+50\).
4Step 4: Factor by Grouping
Factor by grouping. Group the first two terms and the last two terms separately. By factoring out \(2x\) from the first group and -10 from the second group, the equation becomes \(2x(x-5) - 10(x-5)\).
5Step 5: Factor out the Common Factor
Now, look for a common factor in both groups. Here, \(x-5\) is the common factor. Factor it out to yield the final factored polynomial: \((x-5)(2x-10)\).
Key Concepts
Polynomial expressionsFactor by groupingAlgebraic techniques
Polynomial expressions
Polynomial expressions are mathematical expressions involving variables raised to whole number powers and coefficients. Understanding them is a foundational step in algebra. A polynomial may have one or more terms, and each term consists of a coefficient and one or more variables raised to a power. For example, in the expression \(2x^2 - 20x + 50\), there are three terms:
Understanding the structure of polynomial expressions allows for the application of different algebraic techniques, such as factoring.
- \(2x^2\) - the quadratic term where 2 is the coefficient.
- \(-20x\) - the linear term where -20 is the coefficient.
- \(50\) - the constant term.
Understanding the structure of polynomial expressions allows for the application of different algebraic techniques, such as factoring.
Factor by grouping
Factor by grouping is a powerful algebraic technique used to factorize polynomials. It involves arranging a polynomial expression into groups that can be factored separately.
Here's how to factor by grouping using the example \(2x^2 - 20x + 50\):
Here's how to factor by grouping using the example \(2x^2 - 20x + 50\):
- First, split the middle term (-20x) into two terms that can help in grouping. In this example, \(-10x\) and \(-10x\) are used because their product is equivalent to 100 and their sum is -20.
- Rewrite the polynomial as \(2x^2 - 10x - 10x + 50\).
- Group the terms: \((2x^2 - 10x) + (-10x + 50)\).
- Factor each group individually: from the first group \(2x(x - 5)\), and from the second group \(-10(x - 5)\).
- Notice that \((x - 5)\) is a common factor for both groups. Factor it out: \((x - 5)(2x - 10)\).
Algebraic techniques
Algebraic techniques are strategies used to simplify and solve polynomial expressions. They are essential in solving equations and analyzing mathematical relationships.
Some key algebraic techniques include:
Some key algebraic techniques include:
- Factoring: Breaking down expressions into simpler, multiplicative components, like turning \(2x^2 - 20x + 50\) into \((x - 5)(2x - 10)\).
- Distributive Property: Using a\(b + c = ab + ac\) helps in expanding and factoring expressions.
- Combining Like Terms: Simplifying expressions by merging terms with the same variable parts, essential for maintaining clarity in expressions.
Other exercises in this chapter
Problem 137
Factor completely. $$3 x^{3}-75 x$$
View solution Problem 138
Factor completely. $$5 y^{5}-5 y^{4}-20 y^{3}+20 y^{2}$$
View solution Problem 139
Factor completely. $$4 x^{4}-9 x^{2}+5$$
View solution Problem 139
Factor completely. $$x^{3}-2 x^{2}-x+2$$
View solution