Problem 138
Question
A is a coloured crystalline solid which is easily soluble in water. Addition of aqueous KCN gives a precipitate which dissolves in excess of reagent whereas addition of KI aqueous solution gives a white grey precipitate with the liberation of iodine. On gently heating, A loses \(80 \%\) of its water of crystallization. Identify A here? (a) \(\mathrm{ZnSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}\) (b) \(\mathrm{FeSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}\) (c) \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\) (d) \(\mathrm{Hg}_{2} \mathrm{Cl}_{2}\)
Step-by-Step Solution
Verified Answer
Compound A is CuSO₄·5H₂O.
1Step 1: Understanding the Problem
We need to identify the compound A based on its reactions and properties. We know it is a coloured crystalline solid, easily soluble in water, and reacts with additional reagents, specifically aqueous KCN and KI, resulting in specific changes.
2Step 2: Analyzing Solubility and Reactivity
Examine the options. Options (a) and (b),
ZnSO₄·7H₂O and FeSO₄·7H₂O, are typically not colored crystalline solids consistently with the description, while CuSO₄·5H₂O, option (c), is a known colored compound. Option (d), Hg₂Cl₂, is a colored solid but doesn't react with aqueous solutions as described.
3Step 3: Reaction with KCN
With KCN, option (c) CuSO₄ can form a precipitate that dissolves in excess reagent due to the complex ion formation, Cu(CN)₄²⁻, which is consistent with the given reaction observation.
4Step 4: Reaction with KI
Considering the KI reaction, addition of KI to CuSO₄ can result in a greyish precipitate due to the formation of CuI and the iodine liberation reaction, forming a consistent procedural result.
5Step 5: Checking Water of Crystallization
CuSO₄·5H₂O, upon gentle heating, loses some of its water of crystallization, matching the description of losing 80% of its water. This makes option (c) the most plausible choice.
Key Concepts
Transition Metal ComplexesHydration of CompoundsReactivity with CyanidePrecipitation Reactions
Transition Metal Complexes
Transition metals are known for their ability to form complexes, thanks to their partially filled d orbitals. This unique property allows them to form coordinate bonds with other molecules, typically known as ligands. Key Characteristics of Transition Metal Complexes:
- Coordination Chemistry: Transition metals can coordinate with various ligands, forming complex structures. For instance, copper(II) sulfate forms complexes like \[\text{Cu(CN)}_4^{2-}\] with cyanide ions.
- Variable Oxidation States: Transition metals can exist in multiple oxidation states, making them versatile in chemical reactions.
- Colored Compounds: Many complexes are intensely colored, such as the blue color of CuSO₄ · 5H₂O. This is due to the d-d electronic transitions.
Hydration of Compounds
Hydration refers to the incorporation of water molecules into a compound, forming a hydrated structure. This happens in various crystalline solids, where water molecules are integrated into the crystal lattice.
Important Notes on the Hydration:
- Water of Crystallization: It represents water molecules that become an integral part of the crystalline structure. An example is CuSO₄·5H₂O, which contains five water molecules per formula unit.
- Role of Hydration in Physical Properties: Hydration can significantly affect the appearance, stability, and solubility of the compounds.
- Dehydration Process: When heated, hydrated compounds can lose their water of crystallization, often resulting in a color change. For example, blue CuSO₄·5H₂O turns white when it loses its water and becomes anhydrous CuSO₄.
Reactivity with Cyanide
Cyanide, often regarded for its potent reactivity, interacts with metal ions to form complex ions. The reaction of transition metal ions with cyanide is important for various analytical and chemical processes. Cyanide and Metal Reactions:
- Complex Formation: Transition metals such as copper with cyanide form complex anions, such as \[\text{Cu(CN)}_4^{2-}\], which can dissolve back in the solution, explaining why excess cyanide can redissolve a precipitate.
- Stability of Complexes: These complexes are often stable due to the strong binding affinity of cyanide ions to metal centers, impacting the solubility and reactivity of the compounds.
- Precipitation and Resolution: Initially, complexes might precipitate out of solution, but in presence of excess reagent, they can redissolve, as seen with the reaction of KCN with CuSO₄.
Precipitation Reactions
Precipitation reactions are fundamental in chemistry, occurring when two soluble solutions react to form an insoluble solid, known as a precipitate. Transition metal salts often participate in these reactions due to their varying solubility characteristics. Key Points on Precipitation Reactions:
- Formation of Precipitates: These reactions involve the formation of a solid from a solution, such as the reaction between CuSO₄ and KI forming a CuI precipitate.
- Solubility Product: The concept of the solubility product constant (\(K_{sp}\)) helps predict the formation of a precipitate based on the ion concentrations in a solution.
- Color Change and Indicators: Precipitation often goes with a color change, like the greyish color due to the formation of CuI.
- Applications: Precipitation is useful in purification processes, qualitative analysis, and removing ions from solutions.
Other exercises in this chapter
Problem 136
Two ores of the same metal \((\mathrm{M})\) are \(\left(\mathrm{A}_{1}\right)\) and \(\left(\mathrm{A}_{2}\right)\). (1) \(\mathrm{A}_{1} \stackrel{\text { calc
View solution Problem 137
Which compound is formed when excess of \(\mathrm{KCN}\) is added to an aqueous solution of copper sulphate? (a) \(\mathrm{Cu}(\mathrm{CN})_{2}\) (b) \(\mathrm{
View solution Problem 139
Which of the following alloys contain \(\mathrm{Cu}\) and \(\mathrm{Zn}\) ? 1\. bronze 2\. brass 3\. gun metal 4\. type metal (a) \(2,3,4\) (b) \(1,2,3\) (c) 1,
View solution Problem 140
A white, water insoluble solid A turns yellow on heating and becomes white on cooling. A gives a clear solution B when treated with dilute HCl or \(\mathrm{NaOH
View solution