Problem 137
Question
Which compound is formed when excess of \(\mathrm{KCN}\) is added to an aqueous solution of copper sulphate? (a) \(\mathrm{Cu}(\mathrm{CN})\), (b) \(\mathrm{K}_{2}\left[\mathrm{Cu}(\mathrm{CN})_{6}\right]\) (c) \(\mathrm{K}\left[\mathrm{Cu}(\mathrm{CN})_{2}\right]\) (d) \(\mathrm{K}_{3}\left[\mathrm{Cu}(\mathrm{CN})_{4}\right]\)
Step-by-Step Solution
Verified Answer
The compound formed is \( \mathrm{K}_3\left[\mathrm{Cu(CN)}_4\right] \). Option (d).
1Step 1: Understand the Reaction
When potassium cyanide (\( \mathrm{KCN} \)) is added to copper sulphate (\( \mathrm{CuSO}_4 \)), a displacement reaction occurs. Copper ions \( (\mathrm{Cu}^{2+}) \) from the copper sulfate are precipitated by \( \mathrm{CN}^- \) ions from potassium cyanide.
2Step 2: Formation of Basic Complex
Initially, \( \mathrm{Cu}^{2+} \) ions react with \( \mathrm{CN}^- \) ions forming a copper cyanide complex \( \mathrm{Cu(CN)}_2 \), but in the presence of excess \( \mathrm{KCN} \), the complex undergoes further reaction.
3Step 3: Complexation with Excess KCN
In excess \( \mathrm{KCN} \), the \( \mathrm{Cu}^{2+} \) from \( \mathrm{Cu(CN)}_2 \) further complexes to form \( \left[\mathrm{Cu(CN)}_4\right]^{3-} \), which, with potassium ions \((\mathrm{K}^+)\) from \( \mathrm{KCN} \), forms the compound \( \mathrm{K}_3\left[\mathrm{Cu(CN)}_4\right] \).
4Step 4: Conclusion and Answer Selection
The correct compound formed is \( \mathrm{K}_3\left[\mathrm{Cu(CN)}_4\right] \), which corresponds to option (d).
Key Concepts
Displacement ReactionComplex IonsCopper Sulfate reactions
Displacement Reaction
In coordination chemistry, a displacement reaction is one where ions or atoms replace others within a compound. A classic example is when copper ions (\( \mathrm{Cu}^{2+} \)) within copper sulfate are replaced. This occurs when potassium cyanide (\( \mathrm{KCN} \)) is added to the copper sulfate solution. Here’s how it happens:
- The cyanide ions (\( \mathrm{CN}^- \)) added to the solution are highly reactive.
- The copper ions, which are positive, are attracted to the negative cyanide ions.
- This reaction results in the formation of a new compound where copper from the copper sulfate is no longer bonded to sulfate.
Complex Ions
Complex ions play a crucial role in the reactions involving copper sulfate and excess potassium cyanide. But what are complex ions?Complex ions consist of a central metal ion bonded to molecules or ions, known as ligands. In this specific reaction:
- The central metal ion is copper (\( \mathrm{Cu}^{2+} \)).
- The ligands are cyanide ions (\( \mathrm{CN}^- \)).
Copper Sulfate reactions
Copper sulfate is a blue crystalline solid commonly used in chemistry for its distinct properties. It becomes particularly interesting in reaction stages involving complex ions:1. **Initial Formation**: - Copper sulfate dissolves in water to release copper ions (\( \mathrm{Cu}^{2+} \)) and sulfate ions (\( \mathrm{SO}_4^{2-} \)).2. **Reaction with \( \mathrm{KCN} \)**: - The addition of \( \mathrm{KCN} \) to the copper sulfate solution leads to a rearrangement. Initially, a compound \( \mathrm{Cu(CN)}_2 \), which is unstable, appears but rapidly changes.
- In scenarios where \( \mathrm{KCN} \) is in excess, the situation progresses further, leading to yet another transformation into \( \left[\mathrm{Cu(CN)}_4\right]^{3-} \).
Other exercises in this chapter
Problem 135
A solution, when diluted with water and boiled, gives a white precipitate. On addition of excess \(\mathrm{NH}_{4} \mathrm{Cl} /\) \(\mathrm{NH}_{4} \mathrm{OH}
View solution Problem 136
Two ores of the same metal \((\mathrm{M})\) are \(\left(\mathrm{A}_{1}\right)\) and \(\left(\mathrm{A}_{2}\right)\) (1) \(\mathrm{A}_{1} \stackrel{\text { calci
View solution Problem 138
A is a coloured crystalline solid which is easily soluble in water. Addition of aqueous KCN gives a precipitate which dissolves in excess of reagent whereas add
View solution Problem 139
Which of the following alloys contain Cu and \(\mathrm{Zn}\) ? 1\. bronze \(\quad\) 2. brass 3\. gun metal 4\. type metal (a) \(2,3,4\) (b) \(1,2,3\) (c) 1,2 (d
View solution