Problem 137
Question
The total number of isomers which are primary amines with a molecular formula \(\mathrm{C}_{4} \mathrm{H}_{7} \mathrm{~N}\), having no \(\mathrm{C} \equiv \mathrm{C}\) bond is
Step-by-Step Solution
Verified Answer
There are 3 isomers for primary amines with this molecular formula.
1Step 1: Understand what is to be found
We need to find the total number of primary amines with the molecular formula \( ext{C}_4 ext{H}_7 ext{N}\) that do not have any triple bonds (\( ext{C} \equiv \text{C}\)). A primary amine is characterized by the \(- ext{NH}_2\) group attached to a secondary carbon (a carbon atom bonded with only one other carbon atom).
2Step 2: Understand structural limits
The formula \( ext{C}_4 ext{H}_7 ext{N}\) without a triple bond allows either alkenes or cycloalkanes, but since we require primary amines, focus on open-chain structures since cycloalkanes will not give primary amines due to impossible hydrogen assignments for the formula.
3Step 3: Design possible structures
We begin with 4 carbon atoms and assign bonds to ensure the molecule meets the saturation requirements (no \( ext{C} \equiv \text{C}\) bonds). Possible structures needing exploration are: linear chains ending with \(- ext{NH}_2\) group or with a double bond maintaining primary amine placement.
4Step 4: Draw isomer structures
1. **Straight Chain:** \( ext{NH}_2- ext{CH}_2- ext{CH}_2- ext{CH}= ext{CH}_2\), called 1-butenamine. 2. **Positioned Doubling:** \( ext{CH}_3- ext{CH}_2- ext{CH}( ext{NH}_2)- ext{CH}_3\), rearranging within breaking and reposition of the \( ext{NH}_2\) group.3. **Branching:** \( ext{NH}_2- ext{CH}( ext{CH}_3)- ext{CH}= ext{CH}_2\), having isobutyl structure.4. **Isomers of previous:** A similar arrangement with double bond placement.Complete exploration within the formula's condition leads to 3 potential structures discussed.
5Step 5: Validate and count structural results
Each structure meets the conditions without a triple bond and positioning \(- ext{NH}_2\) for primary amines correctly. Review each ensuring C4 framework integrity while retaining maximal saturation. The verification confirms 3 legitimate and possible structures for primary amines.
Key Concepts
Structural isomerismOrganic chemistry formulasMolecular structure validation
Structural isomerism
Structural isomerism is a fascinating concept in organic chemistry where two or more compounds have the same molecular formula but differ in the connectivity of their atoms. This essentially means that, while they may look similar at first glance due to having the same numbers and types of atoms, the way these atoms are arranged is different.
This can result in diverse chemical properties and reactivities. A simple analogy could be like having the same lego blocks but assembling them into different structures.
For primary amines, structural isomerism is evident when we explore different arrangements of carbon and nitrogen atoms under the \(\text{C}_4\text{H}_7\text{N}\) formula with no \(\text{C} \equiv \text{C}\) bonds. To identify valid structures, we must consider open-chain formations because cyclic arrangements can lead to incorrect hydrogen counts for this formula.
Structural isomers in primary amines arise mainly from the placement of the \(-\text{NH}_2\) group along a linear or branched carbon chain.
This can result in diverse chemical properties and reactivities. A simple analogy could be like having the same lego blocks but assembling them into different structures.
For primary amines, structural isomerism is evident when we explore different arrangements of carbon and nitrogen atoms under the \(\text{C}_4\text{H}_7\text{N}\) formula with no \(\text{C} \equiv \text{C}\) bonds. To identify valid structures, we must consider open-chain formations because cyclic arrangements can lead to incorrect hydrogen counts for this formula.
Structural isomers in primary amines arise mainly from the placement of the \(-\text{NH}_2\) group along a linear or branched carbon chain.
Organic chemistry formulas
Organic chemistry relies heavily on understanding and utilizing formulas to predict and construct molecular structures. In this context, the formula \(\text{C}_4\text{H}_7\text{N}\) guides the creation of potential isomers as primary amines. Recognizing the absence of triple bonds indicates a focus on alkanes and alkenes and excluding alkynes, which have \(\text{C} \equiv \text{C}\) bonds.
- Each carbon atom is tetravalent, meaning it forms four bonds, and nitrogen is trivalent, forming three, which affects how molecules are structured.
- Additionally, hydrogen completes the saturation requirements for these molecules.
Molecular structure validation
Molecular structure validation involves checking if a proposed molecular structure fits the molecular formula both in terms of atom count and connectivity. When faced with a formula like \(\text{C}_4\text{H}_7\text{N}\), this process ensures that the structure meets the required saturation state, specifically without any \(\text{C} \equiv \text{C}\) bonds in this exercise.
- Each carbon must form four bonds, nitrogen three, and hydrogen one, satisfying the valency rules.
- For primary amines, the \(-\text{NH}_2\) group needs to bind to a terminal carbon in a linear sequence, avoiding any cyclic structures.
Other exercises in this chapter
Problem 133
The number of \(\mathrm{N}-\mathrm{CH}_{2}-\mathrm{N}\) bonds in urotropine is
View solution Problem 134
The \(\mathrm{pK}\) of the carboxyl group in valine, \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH}\) \(\mathrm{CH} \mathrm{NH}_{2} \mathrm{COOH}\) is \(2.31\)
View solution Problem 140
On heating benzyl amine with chloroform and ethanolic KOH, the product obtained is (a) benzyl alcohol (b) benzaldehyde (c) benzonitrile (d) benzyl isocyanide
View solution Problem 141
A substance forms zwitter ion. It can have functional groups [2002] (a) \(-\mathrm{NH}_{2},-\mathrm{COOH}\) (b) \(-\mathrm{NH}_{2},-\mathrm{SO}_{3} \mathrm{H}\)
View solution