Problem 137
Question
The colligative properties of electrolytes require a slightly different approach than the one used for the colligative properties of non- electrolytes. The electrolytes dissociate into ions in solution. It is the number of solute particles that determine the colligative properties of a solution. The electrolyte solutions, therefore show abnormal colligative properties. To account for this effect we define a quantity; called the van't Hoff factor which is given by [solution] \(i=\) \(\frac{\text { Actual number of particles in solution after dissociation }}{\text { Number of formula units initally dissolved in solution }}\) \(\mathrm{i}=1\) (for non - electrolytes); \(\mathrm{i}>1\) (for electrolytes, undergoing dissociation) \(\mathrm{i}<1\) (for solute, undergoing association) \(0.1 \mathrm{M} \mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) is \(60 \%\) ionized. What will be its van't Hoff factor? (a) \(3.4\) (b) \(1.7\) (c) \(2.4\) (d) \(2.2\)
Step-by-Step Solution
VerifiedKey Concepts
Colligative Properties
- Boiling Point Elevation: More solute particles cause the boiling point of a solution to increase, requiring more energy to achieve the gaseous state.
- Freezing Point Depression: Solute particles interfere with the formation of a solid, lowering the freezing point.
- Vapor Pressure Lowering: More solute particles result in fewer solvent molecules escaping into the vapor state, reducing vapor pressure.
- Osmotic Pressure: The pressure required to stop solvent molecules from passing through a semipermeable membrane into the solution increases with more solute particles.
Whether they are electrolytes or non-electrolytes, the number of particles present directly influences these properties.
Electrolyte Dissociation
Strong electrolytes fully dissociate into their ions, while weak electrolytes only partially dissociate. For example, the compound \( \mathrm{K}_{4}[\mathrm{Fe}(\mathrm{CN})_{6}] \) dissociates into 4 potassium (\( \mathrm{K}^+ \)) ions and one \([\mathrm{Fe}(\mathrm{CN})_{6}]^{4-}\) ion, making a total of 5 ions per formula unit when fully dissociated.
This means solutions with electrolytes may have abnormal colligative properties, as there are more solute particles than initially expected. This increase in particle number can significantly enhance or affect the noted colligative effects.
Degree of Ionization
For instance, in the given example, \( \mathrm{K}_{4}[\mathrm{Fe}(\mathrm{CN})_{6}] \) is 60% ionized. This means that out of the full potential to dissociate into 5 ions, only 60% of that potential is realized.
Knowing the degree of ionization is crucial for calculating the actual number of particles in a solution, which is needed for determining the van’t Hoff factor. This factor aids in quantifying how the solution deviates from ideal behavior due to ionization.
Always consider this degree, as it dictates the real solute particle count affecting colligative properties.
Number of Solute Particles
To find the number of particles, one must consider both the dissociated and undissociated parts of the solute. The undissociated portion remains as formula units, while the dissociated part forms multiple ionic particles.
Using the previous example, if \( \mathrm{K}_{4}[\mathrm{Fe}(\mathrm{CN})_{6}] \) is 60% ionized, there would be 1 undissociated unit and 3 particles from dissociation. This results in a total of 4 solute particles.
Why is this crucial? Because the number of particles directly influences the solution's colligative properties and helps in calculating the van’t Hoff factor, which assesses the extent of dissociation. It's pivotal for understanding solutions that deviate from ideal conditions, notably in electrolyte solutions.