Problem 137
Question
Let \(z=x^{2}+3 x y+2 y^{2} .\) Find \(\frac{\partial^{2} z}{\partial x^{2}}\) and \(\frac{\partial^{2} z}{\partial y^{2}}\).
Step-by-Step Solution
Verified Answer
\(\frac{\partial^{2} z}{\partial x^{2}} = 2\) and \(\frac{\partial^{2} z}{\partial y^{2}} = 4\).
1Step 1: Find the First Partial Derivative with Respect to x
First, we find the partial derivative of the function \(z\) with respect to \(x\). The function is \(z = x^{2} + 3xy + 2y^{2}\).The terms involving \(x\) are as follows:- For \(x^{2}\), the derivative with respect to \(x\) is \(2x\).- For \(3xy\), treating \(y\) as a constant, the derivative with respect to \(x\) is \(3y\).- \(2y^{2}\) is treated as constant and differentiates to 0.Therefore, the first partial derivative with respect to \(x\) is:\[ \frac{\partial z}{\partial x} = 2x + 3y \]
2Step 2: Differentiate Again to Find \(\frac{\partial^{2} z}{\partial x^{2}}\)
Now we take the second derivative with respect to \(x\) of \(\frac{\partial z}{\partial x} = 2x + 3y\).- The derivative of \(2x\) with respect to \(x\) is 2.- The derivative of \(3y\) with respect to \(x\) is 0.Thus, we have:\[ \frac{\partial^{2} z}{\partial x^{2}} = 2 \]
3Step 3: Find the First Partial Derivative with Respect to y
Next, we find the partial derivative of the function \(z\) with respect to \(y\). Start again with the original function \(z = x^{2} + 3xy + 2y^{2}\).- The derivative of \(x^{2}\) with respect to \(y\) is 0.- For \(3xy\), the derivative with respect to \(y\) is \(3x\).- For \(2y^{2}\), the derivative with respect to \(y\) is \(4y\).Thus, the first partial derivative with respect to \(y\) is:\[ \frac{\partial z}{\partial y} = 3x + 4y \]
4Step 4: Differentiate Again to Find \(\frac{\partial^{2} z}{\partial y^{2}}\)
Finally, differentiate \(\frac{\partial z}{\partial y} = 3x + 4y\) with respect to \(y\).- The derivative of \(3x\) with respect to \(y\) is 0.- The derivative of \(4y\) with respect to \(y\) is 4.Thus, the second partial derivative with respect to \(y\) is:\[ \frac{\partial^{2} z}{\partial y^{2}} = 4 \]
Key Concepts
Partial DerivativesMultivariable CalculusDifferentiation
Partial Derivatives
Partial derivatives are an essential part of multivariable calculus, dealing with functions that have more than one variable. Imagine we have a function like \[ f(x, y, z) \]This function depends on multiple variables. We use partial derivatives to study the function's rate of change concerning one variable at a time while keeping the others constant.For example:
- If you take the partial derivative of \( f \) with respect to \( x \), you hold \( y \) and \( z \) constant, and find out how \( f \) changes as \( x \) changes.
- Similarly, a partial derivative with respect to \( y \) keeps \( x \) and \( z \) constant.
Multivariable Calculus
Multivariable calculus extends concepts from basic calculus to functions involving several variables. Where single-variable calculus deals with functions in one-dimensional space,multivariable calculus handles functions mapped in multidimensional spaces.Some important topics include:
- Function of Several Variables: Unlike functions in simple calculus, these depend on two or more variables, e.g., \( f(x, y) \) or \( g(x, y, z) \).
- Partial Derivatives: These help us analyze the individual influence of each variable on the overall function.
- Gradient: A vector representing the direction and rate of the steepest ascent of a function.
Differentiation
Differentiation is a significant process in calculus used to find the rate of change of one variable with respect to another. It's like finding the slope or steepness of a function at any point.In the context of single-variable calculus, you're typically used to dealing with functions of a single variable, finding their derivatives. But in multivariable calculus, we expand this concept by using partial derivatives.
- Normal Differentiation: Involves functions like \( f(x) \) where you find the derivative with respect to that one variable \( x \).
- Partial Differentiation: Deals with functions like \( f(x, y) \) where you calculate partial derivatives for each variable \( x \) and \( y \). Each variable is differentiated separately in relation to the function, while keeping others constant.
Other exercises in this chapter
Problem 134
Calculate \(\frac{\partial w}{\partial z}\) for \(w=z \sin \left(x y^{2}+2 z\right)\).
View solution Problem 136
Find the indicated higher-order partial derivatives. $$f_{y x}\( for \)z=\ln (x-y)$$
View solution Problem 138
Given \(z=e^{x} \tan y,\) find \(\frac{\partial^{2} z}{\partial x \partial y}\) and \(\frac{\partial^{2} z}{\partial y \partial x}\).
View solution Problem 139
Given \(f(x, y, z)=x y z,\) find \(f_{x y y}, f_{y x y}, \quad\) and \(f_{y y x}\).
View solution