Problem 137
Question
Let us explore a reaction with a limiting reactant. Here, zinc metal is added to a flask containing aqueous HCl, and \(\mathrm{H}_{2}\) gas is a product. $$\mathrm{Zn}(\mathrm{s})+2 \mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{ZnCl}_{2}(\mathrm{aq})+\mathrm{H}_{2}(\mathrm{g})$$ The three flasks each contain 0.100 mol of HCl. Zinc is added to each flask in the following quantities. When the reactants are combined, the \(\mathrm{H}_{2}\) inflates the balloon attached to the flask. The results are as follows: Flask 1: Balloon inflates completely, but some \(\mathrm{Zn}\) remains when inflation ceases. Flask 2: Balloon inflates completely. No Zn remains. Flask 3: Balloon does not inflate completely. No Zn remains. Explain these results. Perform calculations that support your explanation.
Step-by-Step Solution
VerifiedKey Concepts
Chemical Reaction Stoichiometry
- The chemical equation must first be balanced.
- The balanced equation will provide the molar ratios of reactants and products.
Balanced Chemical Equation
- This indicates one mole of zinc reacts with two moles of hydrochloric acid.
- It produces one mole of zinc chloride and one mole of hydrogen gas.
Reaction Products Analysis
- Flask 1 shows hydrochloric acid as the limiting reactant since extra zinc remains unreacted.
- In Flask 2, zinc is the limiting reactant, fully consumed without any excess reactant.
- In Flask 3, again zinc limits the reaction but is present in insufficient quantity to use up all the hydrochloric acid.
Stoichiometric Calculations
- Each flask has 0.100 mol of \( \text{HCl} \). According to the balanced equation, 0.050 mol of \( \text{Zn} \) is needed for complete reaction.
- Flask 1 used more than this amount, suggesting \( \text{HCl} \) was the limitation.
- Flask 2 had exactly 0.050 mol of \( \text{Zn} \), aligning perfectly with the stoichiometric ratio.
- Flask 3 had less than 0.050 mol, meaning \( \text{Zn} \) was insufficient to react fully with the \( \text{HCl} \).