Problem 136
Question
For the following exercises, \(P\) is a point on the unit circle. a. Find the (exact) missing coordinate value of each point and b. find the values of the six trigonometric functions for the angle \(\theta\) with a terminal side that passes through point \(P .\) Rationalize denominators. $$P\left(\frac{-15}{17}, y\right), y<0$$
Step-by-Step Solution
Verified Answer
y-coordinate is \(\frac{-8}{17}\); \(\sin(\theta) = \frac{-8}{17}\), \(\cos(\theta) = \frac{-15}{17}\), \(\tan(\theta) = \frac{8}{15}\), \(\csc(\theta) = \frac{-17}{8}\), \(\sec(\theta) = \frac{-17}{15}\), \(\cot(\theta) = \frac{15}{8}\).
1Step 1: Use the Unit Circle Equation
Since point \(P\left(\frac{-15}{17}, y\right)\) is on the unit circle, it satisfies the equation \(x^2 + y^2 = 1\). Substitute \(x = \frac{-15}{17}\) into the equation: \(\left(\frac{-15}{17}\right)^2 + y^2 = 1\).
2Step 2: Solve for y
Calculate \(\left(\frac{-15}{17}\right)^2 = \frac{225}{289}\). Substitute and simplify the equation: \(\frac{225}{289} + y^2 = 1\). This simplifies to \(y^2 = 1 - \frac{225}{289} = \frac{64}{289}\). Taking the square root of both sides gives \(y = \pm \frac{8}{17}\). Since \(y < 0\), \(y = \frac{-8}{17}\).
3Step 3: Find Sine and Cosine
For angle \(\theta\), \(\sin(\theta) = y = \frac{-8}{17}\) and \(\cos(\theta) = x = \frac{-15}{17}\).
4Step 4: Find the Remaining Trigonometric Functions
Using \(\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} = \frac{\frac{-8}{17}}{\frac{-15}{17}} = \frac{8}{15}\). Using the reciprocal identities: \(\csc(\theta) = \frac{1}{\sin(\theta)} = \frac{-17}{8}\), \(\sec(\theta) = \frac{1}{\cos(\theta)} = \frac{-17}{15}\), \(\cot(\theta) = \frac{1}{\tan(\theta)} = \frac{15}{8}\). Ensure to rationalize the denominators.
Key Concepts
Trigonometric Functions in the Unit CircleRationalizing DenominatorsAngle Calculation on the Unit Circle
Trigonometric Functions in the Unit Circle
Trigonometric functions are essential for understanding relationships within circles and solving real-world problems involving rotation and oscillation. When dealing with the unit circle, these functions take on simplified yet powerful forms.
The unit circle has a radius of 1, which means any point on the unit circle can be represented by the coordinates \( (x, y) \). The coordinate \( x \) is equivalent to \( \cos(\theta) \) and \( y \) is \( \sin(\theta) \), where \( \theta \) is the angle formed by the line from the origin to the point and the positive x-axis. This relationship helps to find function values directly.
The unit circle has a radius of 1, which means any point on the unit circle can be represented by the coordinates \( (x, y) \). The coordinate \( x \) is equivalent to \( \cos(\theta) \) and \( y \) is \( \sin(\theta) \), where \( \theta \) is the angle formed by the line from the origin to the point and the positive x-axis. This relationship helps to find function values directly.
- For sine, \( \sin(\theta) \), use the y-coordinate.
- For cosine, \( \cos(\theta) \), use the x-coordinate.
- Tangent, \( \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} \) is the ratio of the y-coordinate to the x-coordinate.
- Cosecant, \( \csc(\theta) = \frac{1}{\sin(\theta)} \)
- Secant, \( \sec(\theta) = \frac{1}{\cos(\theta)} \)
- Cotangent, \( \cot(\theta) = \frac{1}{\tan(\theta)} \)
Rationalizing Denominators
Rationalizing denominators is a useful algebraic technique that makes expressions simpler or more elegant. This process involves eliminating any irrational or radical expressions found in the denominator of a fraction.
Let's see how rationalizing works in the context of trigonometric functions derived from the unit circle:
Let's see how rationalizing works in the context of trigonometric functions derived from the unit circle:
- Consider the function \( \csc(\theta) = \frac{1}{\sin(\theta)} \) with \( \sin(\theta) = \-\frac{8}{17} \).
- Initially, this becomes \( \csc(\theta) = \,\frac{1}{\frac{-8}{17}} = \frac{-17}{8} \).
- This fraction is already rational, but ensure this process for irrational or complex denominators.
Angle Calculation on the Unit Circle
Calculating angles in the unit circle involves understanding their coordinates and the relationships they have with trigonometric functions. Point \( P(x, y) \) on the unit circle directly corresponds to an angle \( \theta \), where \( \cos(\theta) = x \) and \( \sin(\theta) = y \).
Every point intersects with a particular angle from the origin, traveling counter-clockwise from the positive x-axis.
Steps to determine the angle include:
Every point intersects with a particular angle from the origin, traveling counter-clockwise from the positive x-axis.
Steps to determine the angle include:
- Identify \( x \) and \( y \) coordinates, use them to find \( \sin, \cos, \tan \) from your known point.
- Recognize which quadrant the point resides in to determine the sign of \( \sin \) and \( \cos \).
- Consider full-circle symmetry: for example, if \( \theta \) is negative, the angle's position is measured from clockwise rotation.
Other exercises in this chapter
Problem 135
For the following exercises, \(P\) is a point on the unit circle. a. Find the (exact) missing coordinate value of each point and b. find the values of the six t
View solution Problem 135
\(P\) is a point on the unit circle. a. Find the (exact) missing coordinate value of each point and b. find the values of the six trigonometric functions for th
View solution Problem 136
\(P\) is a point on the unit circle. a. Find the (exact) missing coordinate value of each point and b. find the values of the six trigonometric functions for th
View solution Problem 137
For the following exercises, \(P\) is a point on the unit circle. a. Find the (exact) missing coordinate value of each point and b. find the values of the six t
View solution