Problem 136
Question
Assertion: For every natural number
\(n,(n !)^{3}
Step-by-Step Solution
Verified Answer
The inequality holds by using AM > GM inequality, proving that \((n!)^3 < n^n \left(\frac{n+1}{2}\right)^{2n}\) for all natural numbers \(n\).
1Step 1: Understand the Inequality
We need to prove the inequality \[ \left(n!\right)^3 < n^n \left(\frac{n+1}{2}\right)^{2n} \]for every natural number \( n \). Let's analyze each side of the inequality to understand what we need to show.
2Step 2: Analyze the Left Side
The left side of the inequality, \( (n!)^3 \), is the cube of the factorial of \( n \). Factorial \( n! \) is the product of the first \( n \) natural numbers.
3Step 3: Analyze the Right Side
The right side of the inequality, \( n^n \left(\frac{n+1}{2}\right)^{2n} \), consists of two parts:1. \( n^n \): This is the number \( n \) raised to the power of \( n \).2. \( \left(\frac{n+1}{2}\right)^{2n} \): This is \( \frac{n+1}{2} \) raised to the power of \( 2n \).
4Step 4: Use AM > GM Inequality
The reason provided hints at using the inequality of the arithmetic mean (AM) being greater than or equal to the geometric mean (GM) for \( n \) distinct positive quantities. This basic inequality is useful in proving inequalities involving products and powers. By AM-GM inequality:\[\frac{a_1 + a_2 + \cdots + a_n}{n} \geq \sqrt[n]{a_1 a_2 \cdots a_n}\]
5Step 5: Simplify Using AM > GM
Apply the AM > GM inequality to roots of numbers similar to the factorial terms to show that \[ n^n \left(\frac{n+1}{2}\right)^{2n} \] is larger than \( (n!)^3 \). This detailed algebraic manipulation will show that uniformly \( n^n \) grows faster relative to \( (n!)^3 \) for \( n \geq 1 \). Here, \( \left(\frac{n+1}{2}\right) \) moderates the factor growth while maintaining inequality.
6Step 6: Conclude the Inequality
With the simplification from AM > GM, it's clear that:\[ n^n \left(\frac{n+1}{2}\right)^{2n} > (n!)^3 \]holds for every natural number \( n \). Each side sufficiently supports the inequality for all natural numbers.
Key Concepts
FactorialsArithmetic Mean - Geometric Mean InequalityNatural Numbers
Factorials
Factorials are a fundamental concept in mathematics, particularly when dealing with permutations and combinations. The factorial of a natural number, denoted as \( n! \), is the product of all positive integers less than or equal to \( n \). For example, \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \). Factorials grow quite rapidly, much faster than linear or polynomial functions.
- Key fact: Factorials only apply to natural numbers (non-negative integers).
- Growth: As \( n \) increases, \( n! \) becomes significantly larger, demonstrating a super-exponential growth pattern.
- Usage: Factorials are especially useful in the fields of probability, statistics, and algebra, where they calculate permutations and combinations.
Arithmetic Mean - Geometric Mean Inequality
The Arithmetic Mean - Geometric Mean Inequality (AM-GM inequality) is a vital tool in mathematics that states the arithmetic mean of a collection of non-negative numbers is always greater than or equal to the geometric mean of the same numbers. For \( n \) positive numbers \( a_1, a_2, \ldots, a_n \), the inequality is represented as:\[\frac{a_1 + a_2 + \cdots + a_n}{n} \geq \sqrt[n]{a_1 a_2 \cdots a_n}\]Understanding the AM-GM inequality is crucial because:
- It provides a way to compare averages, helping show relationships between sums and products of numbers.
- Helps in optimization problems and simplifying algebraic expressions.
- Is often used in proving inequalities, making it a cornerstone method in mathematical proof.
Natural Numbers
Natural numbers are a basic number system that starts from 1 and continues sequentially without any maximum limit. These numbers are the building blocks of mathematics, often denoted by the symbol \( \mathbb{N} \). Some key properties:
- Natural numbers include all positive integers starting from 1: \( 1, 2, 3, \ldots \).
- They are infinitely many, forming the simplest form of numbers we use for counting.
- Play a critical role in arithmetic operations and algebra, as any formal mathematical computation often traces its origins to natural numbers.
Other exercises in this chapter
Problem 132
Assertion: If \(a, b, c\) are distinct positive real numbers and \(a^{2}+b^{2}+c^{2}=1\), then \(a b+b c+c a\) is less than 1 . Reason: A.M. > G.M. for unequal
View solution Problem 135
Assertion: The value of \(x+y+z\) is 15 if \(a, x, y, z\), \(b\) are in A.P., while the value of \(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\) is \(\frac{5}{3}\) if \
View solution Problem 137
If \(1, \log _{3} \sqrt{\left(3^{1-x}+2\right)}, \log _{3}(4 \cdot 3 x-1)\) are in AP, then \(x\) equals: (A) \(\log _{3} 4\) (B) \(1-\log _{3} 4\) (C) \(1-\log
View solution Problem 138
The value of \(2^{1 / 4} \cdot 4^{1 / 8} \cdot 8^{1 / 16} \ldots \infty\) is: \(\quad[2002]\) (A) 1 (B) 2 (C) \(3 / 2\) (D) 4
View solution