Problem 134
Question
Write the rational expression in simplest form. $$\frac{5 x^{2} y^{2}+25 x^{2} y}{x y+5 x}$$
Step-by-Step Solution
Verified Answer
The simplified form of the given expression is \(5xy\).
1Step 1: Factorize the numerator
To simplify a rational function, first factorize the numerator. For \(5x^{2}y^{2} + 25x^{2}y\), factor out the common term to get \(5x^{2}y(y + 5)\).
2Step 2: Factorize the denominator
Continue by factorizing the denominator \(xy + 5x\). Factor out the common term 'x' to get \(x(y + 5)\).
3Step 3: Simplify the fraction
Now, simplify the expression \(\frac{5x^{2}y(y + 5)}{x(y + 5)}\). The common term ads (y+5) in the numerator and the denominator can be shortened, also divide \(5x^{2}y\) by 'x' to give the final simplified expression.
Key Concepts
FactorizationSimplificationNumerator and DenominatorAlgebraic Fractions
Factorization
Factorization is a key step when working with rational expressions. It involves breaking down complex algebraic expressions into products of simpler factors. This process makes it easier to identify common factors in the numerator and the denominator, which can eventually be canceled out. In this particular problem, we start by factorizing both the numerator and the denominator separately.
- For the numerator, \(5x^{2}y^{2} + 25x^{2}y\), we notice that both terms share common factors \(5x^{2}y\). Extracting these common factors results in \(5x^{2}y(y + 5)\).
- Similarly, for the denominator, \(xy + 5x\), the common factor is \(x\), leading us to \(x(y + 5)\).
Simplification
Simplification is the process of reducing complex expressions to their simplest forms. After the factorization step, simplification becomes straightforward as it primarily involves canceling out common factors. This exercise provides a clear example of how simplification can take a tedious expression and make it much more manageable.
In our expression \(\frac{5x^{2}y(y + 5)}{x(y + 5)}\), both the numerator and the denominator contain the term \((y+5)\). Since they are common factors, they can be canceled from both the top and bottom. Now we are left with the simplified expression \(\frac{5x^{2}y}{x}\).
Canceling the \(x\) gives us \(5xy\). Performing these cancellations leads to the simplest form of the given expression, making it easier to handle.
In our expression \(\frac{5x^{2}y(y + 5)}{x(y + 5)}\), both the numerator and the denominator contain the term \((y+5)\). Since they are common factors, they can be canceled from both the top and bottom. Now we are left with the simplified expression \(\frac{5x^{2}y}{x}\).
Canceling the \(x\) gives us \(5xy\). Performing these cancellations leads to the simplest form of the given expression, making it easier to handle.
Numerator and Denominator
A vital component of dealing with rational expressions is understanding the roles of the numerator and the denominator. These are the top and bottom parts of a fraction, respectively.
- The **numerator** is the expression above the fraction line which represents the portion of the whole that is being considered. In our case, the initial numerator is \(5x^{2}y^{2} + 25x^{2}y\).
- The **denominator** is the expression below the fraction line, functioning as the divisor. Here, it begins as \(xy + 5x\).
Algebraic Fractions
Algebraic fractions are fractions where the numerator and/or the denominator contain algebraic expressions (expressions involving variables). Simplifying these fractions involves steps similar to those used with numerical fractions.
In algebraic fractions, we apply factorization to both the numerator and the denominator to seek out common terms. These common terms, once identified, allow us to simplify the fraction by dividing both parts by these terms, similar to how you might with regular numbers.
For example, if we identify \((y+5)\) in both the numerator and the denominator, we can eliminate it from the expression.
This process not only simplifies the expression, making it easier to work with but also reveals deeper mathematical insights into the relationships between the component parts of the fraction.
In algebraic fractions, we apply factorization to both the numerator and the denominator to seek out common terms. These common terms, once identified, allow us to simplify the fraction by dividing both parts by these terms, similar to how you might with regular numbers.
For example, if we identify \((y+5)\) in both the numerator and the denominator, we can eliminate it from the expression.
This process not only simplifies the expression, making it easier to work with but also reveals deeper mathematical insights into the relationships between the component parts of the fraction.
Other exercises in this chapter
Problem 132
Proof Prove that if \(f\) is a one-to-one odd function, then \(f^{-1}\) is an odd function.
View solution Problem 133
Write the rational expression in simplest form. $$\frac{27 x^{3}}{3 x^{2}}$$
View solution Problem 135
Write the rational expression in simplest form. $$\frac{x^{2}-36}{6-x}$$
View solution Problem 136
Write the rational expression in simplest form. $$\frac{x^{2}+3 x-40}{x^{2}-3 x-10}$$
View solution