Problem 134
Question
In the following groups: -OAc (I), \(\quad\)-OMe (II) \(-\mathrm{OSO}_{2} \mathrm{Me}(\mathrm{III}), \quad-\mathrm{OSO}_{2} \mathrm{CF}_{3}(\mathrm{IV})\) the order of the leaving group ability is (a) \(\mathrm{I}>\mathrm{II}>\mathrm{III}>\mathrm{IV}\) (b) IV \(>\mathrm{III}>\mathrm{I}>\mathrm{II}\) (c) III > II \(>\mathrm{I}>\mathrm{IV}\) (d) \(\mathrm{II}>\mathrm{III}>\mathrm{IV}>\mathrm{I}\).
Step-by-Step Solution
Verified Answer
The order of leaving group ability is IV > III > I > II (option b).
1Step 1: Understand Leaving Groups
Leaving groups are atoms or groups of atoms that can be departed from a molecule, taking the bonding pair of electrons with them. The ability of a leaving group is primarily determined by its stability once it has left the parent molecule.
2Step 2: Evaluate Stability of Leaving Groups
The stability of a potential leaving group can be assessed by the strength of the acid from which it is derived. A weaker conjugate base corresponds to a stronger acid, which usually indicates a better leaving group. Stability can also be influenced by the ability to spread out charge via resonance or inductive effects.
3Step 3: Analyze the Given Groups
The given groups are -OAc, -OMe, -OSO2Me, and -OSO2CF3. Look at the functional groups: -OAc (acetate) is stabilized by resonance, -OMe (methoxide) is less stable than acetate, -OSO2Me (mesylate) is a stronger acid conjugate than -OMe, and -OSO2CF3 (triflate) is even more stable due to electronegative fluorine increasing acidity.
4Step 4: Order the Leaving Groups by Ability
Based on acid strength derived from these leaving groups, we have: -OSO2CF3 is the best leaving group due to its strongest acid conjugate. -OSO2Me comes next, followed by -OAc, and then -OMe as it is the least stable once departed.
5Step 5: Identify the Correct Answer
Looking at our analysis, the empirical order from best to worst leaving group is -OSO2CF3 > -OSO2Me > -OAc > -OMe. This corresponds to option (b) IV > III > I > II.
Key Concepts
Stability of Leaving GroupsResonance EffectsInductive EffectsAcid Strength
Stability of Leaving Groups
Leaving groups are essential in many organic reactions. A good leaving group is a group that can easily depart from the parent molecule while leaving behind a stable structure. This stability once the group leaves determines its leaving ability. Typically, the better a group can stabilize itself when separated, the better a leaving group it is.
A leaving group's stability often corresponds to the stability of its conjugate acid. A weaker conjugate base implies a stronger acid, indicating that the leaving group was stable before departing. For example, the triflate ion \(-\mathrm{OSO}_{2}\mathrm{CF}_{3}\) is an excellent leaving group. Its departing stability comes from the strong acid nature of its conjugate (trifluoromethanesulfonic acid).
A leaving group's stability often corresponds to the stability of its conjugate acid. A weaker conjugate base implies a stronger acid, indicating that the leaving group was stable before departing. For example, the triflate ion \(-\mathrm{OSO}_{2}\mathrm{CF}_{3}\) is an excellent leaving group. Its departing stability comes from the strong acid nature of its conjugate (trifluoromethanesulfonic acid).
- Good leaving groups are typically weak bases once they've left.
- The weak base is often the conjugate of a strong acid.
Resonance Effects
Resonance is a critical concept that impacts the stability of leaving groups. It involves the delocalization of electrons within a molecule or ion, which spreads the charge over several atoms rather than localizing it at one point. This electron delocalization can significantly enhance the stability of a leaving group.
For example, in acetate ion \(-\mathrm{OAc}\), resonance allows the negative charge to be dispersed between the oxygen atoms in the carboxylic group, leading to increased stability. Such delocalization lowers the energy of the system and stabilizes the product, making the leaving group more likely to separate.
For example, in acetate ion \(-\mathrm{OAc}\), resonance allows the negative charge to be dispersed between the oxygen atoms in the carboxylic group, leading to increased stability. Such delocalization lowers the energy of the system and stabilizes the product, making the leaving group more likely to separate.
- Resonance allows for the charge to be spread across more atoms, reducing overall energy.
- This spread can stabilize ions, making them better leaving groups.
Inductive Effects
The inductive effect is another significant consideration in determining the ability of leaving groups. It involves the shifting of electrons through sigma bonds in a molecule due to electronegativity differences between atoms. This effect can stabilize or destabilize a leaving group.
For instance, in triflate \(-\mathrm{OSO}_{2}\mathrm{CF}_{3}\), the presence of highly electronegative fluorine atoms exerts a strong inductive effect. These atoms pull electron density away from the sulfur center, thus stabilizing the leaving group. Similarly, mesylate \(-\mathrm{OSO}_{2}\mathrm{Me}\) benefits from inductive effects, but to a lesser extent than triflate due to less electronegative groups.
For instance, in triflate \(-\mathrm{OSO}_{2}\mathrm{CF}_{3}\), the presence of highly electronegative fluorine atoms exerts a strong inductive effect. These atoms pull electron density away from the sulfur center, thus stabilizing the leaving group. Similarly, mesylate \(-\mathrm{OSO}_{2}\mathrm{Me}\) benefits from inductive effects, but to a lesser extent than triflate due to less electronegative groups.
- Inductive effects arise from electronegativity differences, influencing electron distributions.
- Fluorine atoms, due to high electronegativity, can enhance the stability of leaving groups.
Acid Strength
Acid strength plays a pivotal role in determining leaving group ability. The strength of an acid is inversely related to the strength of its conjugate base, which can often serve as a leaving group in reactions.
A strong acid implies a weak conjugate base, making it an excellent candidate for a leaving group. Considering our earlier analysis, triflate \(-\mathrm{OSO}_{2}\mathrm{CF}_{3}\) derives from trifluoromethanesulfonic acid, one of the strongest known acids. This results in a weak and stable conjugate base, ideal for leaving group functionality. In contrast, methoxide \(-\mathrm{OMe}\) comes from methanol, a much weaker acid, leading to a stronger, less stable conjugate base.
A strong acid implies a weak conjugate base, making it an excellent candidate for a leaving group. Considering our earlier analysis, triflate \(-\mathrm{OSO}_{2}\mathrm{CF}_{3}\) derives from trifluoromethanesulfonic acid, one of the strongest known acids. This results in a weak and stable conjugate base, ideal for leaving group functionality. In contrast, methoxide \(-\mathrm{OMe}\) comes from methanol, a much weaker acid, leading to a stronger, less stable conjugate base.
- Strong acids result in weak conjugate bases, beneficial for leaving group roles.
- Evaluating the acid strength of the parent molecule helps predict leaving group behavior.
Other exercises in this chapter
Problem 126
The correct increasing order of the reactivity of halides for \(\mathrm{SN}_{1}\) reaction is (a) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{X}
View solution Problem 129
Which of the following statements are correct. (1) \(\overline{\mathrm{N}} \mathrm{H}_{2}\) is better nucleophile than \(\mathrm{NH}_{3}\), but latter \(\left(\
View solution Problem 136
Consider the following amines: (1) \(\mathrm{C}_{6} \mathrm{H}_{3}-\mathrm{NH}_{2}\) (2) \(0-\mathrm{NO}_{2}-\mathrm{C}_{6} \mathrm{H}_{4}-\mathrm{NH}_{2}\) (3)
View solution Problem 141
Match the following: List I (Type of reaction) 1\. \(\mathrm{SN}_{1}^{2}\) 2\. \(\mathrm{SN}^{1}\) 3\. \(\mathrm{E}_{2}\) 4\. \(\mathrm{E}_{1 \mathrm{cs}}\) Lis
View solution