Problem 134
Question
For the following exercises, prove the identity given. $$ \cot x-\tan x=2 \cot (2 x) $$
Step-by-Step Solution
Verified Answer
The identity \( \cot x - \tan x = 2\cot(2x) \) is true.
1Step 1: Express Cotangent and Tangent in terms of Sine and Cosine
The identities for cotangent and tangent in terms of sine and cosine are \( \cot x = \frac{\cos x}{\sin x} \) and \( \tan x = \frac{\sin x}{\cos x} \). Let's rewrite the left side of the equation using these identities: \[ \cot x - \tan x = \frac{\cos x}{\sin x} - \frac{\sin x}{\cos x}.\]
2Step 2: Find a Common Denominator
To combine these fractions, we need a common denominator. The common denominator of \( \sin x \) and \( \cos x \) is \( \sin x \cos x \). Rewrite each fraction with this common denominator:\[ \frac{\cos x}{\sin x} = \frac{\cos^2 x}{\sin x \cos x} \]\[ \frac{\sin x}{\cos x} = \frac{\sin^2 x}{\sin x \cos x}. \]
3Step 3: Subtract the Fractions
Now subtract the two fractions:\[ \frac{\cos^2 x}{\sin x \cos x} - \frac{\sin^2 x}{\sin x \cos x} = \frac{\cos^2 x - \sin^2 x}{\sin x \cos x}.\]
4Step 4: Utilize Trigonometric Identities
Recall the identity \( \cos 2x = \cos^2 x - \sin^2 x \).Substitute this identity into the expression:\[ \frac{\cos^2 x - \sin^2 x}{\sin x \cos x} = \frac{\cos 2x}{\sin x \cos x}.\]
5Step 5: Simplify the Expression
Notice that the right side of the original identity is \( 2\cot(2x) \). The identity for \( \cot(2x) \) is \( \frac{\cos 2x}{\sin 2x} \). Given \( \sin 2x = 2 \sin x \cos x \), we have:\[ \cot(2x) = \frac{\cos 2x}{2 \sin x \cos x}. \]Thus, \( 2\cot(2x) \) is:\[ 2 \times \frac{\cos 2x}{2 \sin x \cos x} = \frac{\cos 2x}{\sin x \cos x}. \]
6Step 6: Confirm the Identity
Since the simplified left side \( \frac{\cos 2x}{\sin x \cos x} \) is identical to the expression we found for \( 2\cot(2x) \), this confirms that:\[ \cot x - \tan x = 2 \cot(2x). \]
Key Concepts
CotangentTangentSine and Cosine IdentitiesCommon Denominator in Fractions
Cotangent
The cotangent function, often abbreviated as "cot," is one of the fundamental trigonometric functions. It is the reciprocal of the tangent function. This means that instead of looking at the ratio of the opposite side to the adjacent side in a right triangle (as tangent does), cotangent is the ratio of the adjacent side to the opposite side. Mathematically, we express it as:
- \( \cot x = \frac{1}{\tan x} \)
- \( \cot x = \frac{\cos x}{\sin x} \)
Tangent
The tangent function, abbreviated as "tan," is another core trigonometric function. It relates the angle in a right triangle to the ratio of the length of the opposite side over the length of the adjacent side. In mathematical terms:
- \( \tan x = \frac{\sin x}{\cos x} \)
- \( \tan x = \frac{1}{\cot x} \)
Sine and Cosine Identities
Sine and cosine are the foundational building blocks of trigonometry. Many identities revolve around these two functions due to their integral role in defining other trigonometric functions. Key identities to know include:
- Using the Pythagorean identity: \( \sin^2 x + \cos^2 x = 1 \)
- Double angle identities: \( \cos(2x) = \cos^2 x - \sin^2 x \) or \( \sin(2x) = 2 \sin x \cos x \)
Common Denominator in Fractions
A common denominator is essential when adding or subtracting fractions. It is the least common multiple of the denominators of the fractions involved.For trigonometric identities involving fractions, such as our exercise, finding a common denominator allows the fractions to be combined into a single one.When dealing with symbolic fractions like those in trigonometry:
- For \( \frac{\cos x}{\sin x} \) and \( \frac{\sin x}{\cos x} \), the common denominator is \( \sin x \cos x \).
- Transform each term: \( \frac{\cos x}{\sin x} = \frac{\cos^2 x}{\sin x \cos x} \) and \( \frac{\sin x}{\cos x} = \frac{\sin^2 x}{\sin x \cos x} \).
Other exercises in this chapter
Problem 132
For the following exercises, prove the identity given. $$ (\sin t-\cos t)^{2}=1-\sin (2 t) $$
View solution Problem 133
For the following exercises, prove the identity given. $$ \sin (2 x)=-2 \sin (-x) \cos (-x) $$
View solution Problem 135
For the following exercises, prove the identity given. $$ \frac{\sin (2 \theta)}{1+\cos (2 \theta)} \tan ^{2} \theta=\tan \theta $$
View solution Problem 136
For the following exercises, rewrite the expression with an exponent no higher than 1. $$ \cos ^{2}(5 x) $$
View solution