Problem 134
Question
Compound X (1) on strongly heating it gives two oxides of sulphur. (2) on adding aqueous \(\mathrm{NaOH}\) solution to its aqueous solution, a dirty green precipitate is obtained which starts turning brown on exposure to air. Identify \(\mathrm{X}\) here. (a) \(\mathrm{CuSO}_{4} .5 \mathrm{H}_{2} \mathrm{O}\) (b) \(\mathrm{FeSO}_{4} .7 \mathrm{H}_{2} \mathrm{O}\) (c) \(\mathrm{ZnSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}\) (d) \(\mathrm{Ag}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\)
Step-by-Step Solution
Verified Answer
Compound X is (b) ext{FeSO}_4 ext{H}_2 ext{O}.
1Step 1: Analyze Heating Reaction
When Compound X is strongly heated, it decomposes to produce two oxides of sulphur. These are typically sulphur dioxide (SO_2) and sulphur trioxide (SO_3). This behavior is characteristic of compounds containing hydrated sulfates, such as ext{FeSO}_4 .
2Step 2: Test Reaction with NaOH
When aqueous ext{NaOH} is added to a solution of Compound X, it produces a dirty green precipitate. This precipitate is likely iron (II) hydroxide, ext{Fe(OH)}_2, which is a common result when iron (II) sulfate reacts with ext{NaOH}.
3Step 3: Observing Precipitate Color Change
The green precipitate turns brown upon exposure to air, indicating the oxidation of iron (II) hydroxide to iron (III) hydroxide, ext{Fe(OH)}_3. The color change and oxidation are indicative of the presence of iron compounds, specifically ext{FeSO}_4 .
4Step 4: Identify the Compound
Based on the formation of two oxides of sulfur and the behavior of the precipitate, Compound X is identified as hydrated iron (II) sulfate, or ext{FeSO}_4 ext{H}_2 ext{O}. This matches with option (b).
Key Concepts
Hydrated SulfatesSulfate CompoundsOxidation ReactionsPrecipitation Reactions
Hydrated Sulfates
Hydrated sulfates are fascinating compounds where molecules of water are associated with the sulfate. Imagine tiny water molecules nestled like friends around each sulfate ion. These water molecules are called "water of crystallization."
- They form a significant part of the structure.
- Removing this water can significantly change the properties of the compound.
Sulfate Compounds
Sulfate compounds are one of the more common inorganic structures around. These compounds have the sulfate ion, \( \text{SO}_4^{2-} \), as a key player. Let's explore this wondrous ion.
In the exercise, our compound, probably \( \text{FeSO}_4 \, \cdot \, 7 \text{H}_2\text{O} \), gives off oxides of sulphur upon heating. This sooty transformation results directly from its sulfate nature.
- The sulfate ion is made of one sulfur atom surrounded by four oxygen atoms.
- Overall, it carries a negative two charge.
In the exercise, our compound, probably \( \text{FeSO}_4 \, \cdot \, 7 \text{H}_2\text{O} \), gives off oxides of sulphur upon heating. This sooty transformation results directly from its sulfate nature.
Oxidation Reactions
Oxidation reactions are chemical processes where a substance loses electrons. You might think of rust forming on metal or an apple turning brown. In our exercise, we see a similar process happening with iron.
- The dirty green \( \text{Fe(OH)}_2 \) turns brown as it oxidizes to \( \text{Fe(OH)}_3 \).
- This change tells us that the iron moves from a lower to a higher oxidation state.
Precipitation Reactions
Precipitation reactions are always exciting because you see something new forming right before your eyes. These reactions occur when two solutions are mixed, resulting in an insoluble solid, called a precipitate, coming out of solution.
In the context of our exercise, when sodium hydroxide, \( \text{NaOH} \), is added to a solution of our compound, it results in the formation of a dirty green precipitate of iron (II) hydroxide, \( \text{Fe(OH)}_2 \).
In the context of our exercise, when sodium hydroxide, \( \text{NaOH} \), is added to a solution of our compound, it results in the formation of a dirty green precipitate of iron (II) hydroxide, \( \text{Fe(OH)}_2 \).
- This type of reaction is essential to separate components in a mixture.
- It also helps identify ionic compounds in solution.
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