Problem 134
Question
Compound \(\mathrm{X}\) (1) on strongly heating it gives two oxides of sulphur. (2) on adding aqueous \(\mathrm{NaOH}\) solution to its aqueous solution, a dirty green precipitate is obtained which starts turning brown on exposure to air. Identify X here. (a) \(\mathrm{CuSO}_{4} .5 \mathrm{H}_{2} \mathrm{O}\) (b) \(\mathrm{FeSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}\) (c) \(\mathrm{ZnSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}\) (d) \(\mathrm{Ag}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\)
Step-by-Step Solution
Verified Answer
The compound X is FeSO₄·7H₂O (option b).
1Step 1: Identifying the Reaction with Heating Sulphates
When strongly heated, sulphates like FeSO₄ can decompose to release sulphur oxides which are SO₂ and SO₃. Other options do not release these oxides under strong heating.
2Step 2: Observing the Reactivity with NaOH
Adding aqueous NaOH to FeSO₄ solution results in the formation of a green precipitate. This green precipitate is ferrous hydroxide, Fe(OH)₂, and it slowly oxidizes to a brownish compound, ferric hydroxide Fe(OH)₃, when exposed to air.
3Step 3: Analyzing Other Options
CuSO₄ and ZnSO₄ do not produce a green precipitate under these conditions. Ag₂S₂O₃ is thiosulfate and, when reacted with NaOH, does not fit the described behaviors.
4Step 4: Conclusion
Based on the characteristics of decomposition and reactivity with NaOH forming a green precipitate, compound X is FeSO₄·7H₂O.
Key Concepts
Thermal Decomposition of SulfatesPrecipitation ReactionsOxidation of Iron
Thermal Decomposition of Sulfates
Thermal decomposition is a chemical reaction where a single compound breaks down into two or more elements or simpler compounds when heated. Iron(II) sulfate, or \( \text{FeSO}_4 \cdot 7 \text{H}_2\text{O} \), undergoes thermal decomposition when strongly heated. This process leads to the breakdown of the compound into iron(III) oxide \( \text{Fe}_2\text{O}_3 \) and two oxides of sulfur, namely sulfur dioxide \( \text{SO}_2 \) and sulfur trioxide \( \text{SO}_3 \).
The reaction can be represented as:\[2 ext{FeSO}_4 \rightarrow ext{Fe}_2\text{O}_3 + ext{SO}_2 + ext{SO}_3\]This reaction highlights the conversion from a hydrated compound to an anhydrous form along with the liberation of gases. It is essential to understand how heat affects such compounds in chemistry, as this knowledge can be applied to predict the behavior of other substances under similar conditions. Thermal decomposition not only helps identify the presence of sulfates like \( \text{FeSO}_4 \) but also aids in deducing the conditions of a reaction based on gas evolution.
The reaction can be represented as:\[2 ext{FeSO}_4 \rightarrow ext{Fe}_2\text{O}_3 + ext{SO}_2 + ext{SO}_3\]This reaction highlights the conversion from a hydrated compound to an anhydrous form along with the liberation of gases. It is essential to understand how heat affects such compounds in chemistry, as this knowledge can be applied to predict the behavior of other substances under similar conditions. Thermal decomposition not only helps identify the presence of sulfates like \( \text{FeSO}_4 \) but also aids in deducing the conditions of a reaction based on gas evolution.
Precipitation Reactions
Precipitation reactions occur when two soluble salts react in solution to form one or more insoluble products, known as precipitates. In the exercise, when aqueous sodium hydroxide \( \text{NaOH} \) is added to a solution of iron(II) sulfate \( \text{FeSO}_4 \), a dirty green precipitate of ferrous hydroxide \( \text{Fe(OH)}_2 \) is formed.
This can be represented by the equation:\[\text{FeSO}_4 + 2\text{NaOH} \rightarrow \text{Fe(OH)}_2 \downarrow + \text{Na}_2\text{SO}_4\]
This can be represented by the equation:\[\text{FeSO}_4 + 2\text{NaOH} \rightarrow \text{Fe(OH)}_2 \downarrow + \text{Na}_2\text{SO}_4\]
- The "\( \downarrow \)" symbol denotes the formation of a solid precipitate in the mixture.
- Notably, other compounds like copper sulfate \( \text{CuSO}_4 \) or zinc sulfate \( \text{ZnSO}_4 \) do not form the same green precipitate under these conditions.
Oxidation of Iron
Oxidation is a process where an element’s oxidation state increases, often involving the loss of electrons. For iron, this can be typically observed when \( \text{Fe(OH)}_2 \), the green precipitate formed in a reaction, is exposed to air. It undergoes oxidation to become \( \text{Fe(OH)}_3 \), a brown substance.
The reaction can be summarized as:\[4 \text{Fe(OH)}_2 + \text{O}_2 + 2\text{H}_2\text{O} \rightarrow 4\text{Fe(OH)}_3\]This transformation indicates that exposure to oxygen significantly alters the properties of a compound. The oxidation of iron is a common occurrence and is important in understanding processes like rusting, where iron reacts with oxygen and water to form iron oxides.
Here are some additional points to consider about oxidation:
The reaction can be summarized as:\[4 \text{Fe(OH)}_2 + \text{O}_2 + 2\text{H}_2\text{O} \rightarrow 4\text{Fe(OH)}_3\]This transformation indicates that exposure to oxygen significantly alters the properties of a compound. The oxidation of iron is a common occurrence and is important in understanding processes like rusting, where iron reacts with oxygen and water to form iron oxides.
Here are some additional points to consider about oxidation:
- Oxidation reactions are typically part of larger redox processes, where one species is oxidized, and another is reduced.
- Understanding oxidation is crucial in diverse applications, such as metallurgy, corrosion prevention, and energy storage.
Other exercises in this chapter
Problem 132
A certain metal \(\mathrm{A}\) is boiled in dilute nitric acid to give a salt B and an oxide of nitrogen \(\mathrm{C}\). An aqueous solution of \(\mathrm{B}\) w
View solution Problem 133
A certain metal \(\mathrm{A}\) is boiled in dilute nitric acid to give a salt B and an oxide of nitrogen \(\mathrm{C}\). An aqueous solution of \(\mathrm{B}\) w
View solution Problem 135
A solution, when diluted with water and boiled, gives a white precipitate. On addition of excess \(\mathrm{NH}_{4} \mathrm{Cl} /\) \(\mathrm{NH}_{4} \mathrm{OH}
View solution Problem 137
Which compound is formed when excess of \(\mathrm{KCN}\) is added to an aqueous solution of copper sulphate? (a) \(\mathrm{Cu}(\mathrm{CN})_{2}\) (b) \(\mathrm{
View solution