Problem 134
Question
Basic Car Rental charges \(\$ 20\) a day plus \(\$ 0.10\) per mile, whereas Acme Car Rental charges \(\$ 30\) a day plus \(\$ 0.05\) per mile. How many miles must be driven to make the daily cost of a Basic Rental a better deal than an Acme Rental? (Section 1.7, Example 11)
Step-by-Step Solution
Verified Answer
You must drive more than 200 miles for the Basic Rental to be a better deal than the Acme Rental.
1Step 1: Set up the inequality
Determine the daily cost for Basic and Acme in terms of miles. For Basic, it is \(20 + 0.10m\). For Acme, it is \(30 + 0.05m\). To make Basic a better deal, its total cost should be less than Acme's. So set the inequality: \(20 + 0.10m < 30 + 0.05m\).
2Step 2: Solve the inequality
In order to solve this inequality, first simplify it by subtracting \(0.05m\) from both sides and subtracting 20 from both sides. This gives us \(0.05m > 10\). By further simplifying, we get \(m > 200\).
3Step 3: Interpret any result
The solution of the inequality is \(m > 200\). This means that the Basic Rental becomes a better deal than the Acme Rental when more than 200 miles are driven.
Key Concepts
Linear InequalitiesCost ComparisonMathematical ReasoningInequality Solving
Linear Inequalities
Linear inequalities are mathematical expressions used to compare two quantities with a less than, greater than, or not equal to relationship. They are similar to linear equations, but instead of "equals," you use inequality signs like \(<\), \(>\), \(\leq\), or \(\geq\). Here, we compared two expressions:
- Basic Car Rental: \(20 + 0.10m\)
- Acme Car Rental: \(30 + 0.05m\)
Cost Comparison
Comparing costs using inequalities is a practical application in daily life. In this exercise, the cost comparison was between two car rental companies, focusing on determining which option was more economical given a certain number of miles driven.
- Basic Car Rental: Charges a base rate of \\(20 per day with an additional \\)0.10 per mile.
- Acme Car Rental: Charges a base rate of \\(30 per day with an additional \\)0.05 per mile.
Mathematical Reasoning
Mathematical reasoning involves critical thinking and problem-solving skills to arrive at a conclusion. This exercise requires understanding and translating a word problem into a mathematical inequality. Let's break it down:
- Translate the scenario into mathematical expressions: \(20 + 0.10m\) and \(30 + 0.05m\).
- Decide what we want: Basic should be cheaper, so set \(20 + 0.10m < 30 + 0.05m\).
Inequality Solving
Solving inequalities involves steps similar to solving equations, but with one crucial difference when multiplying or dividing by a negative number (the inequality sign flips, though this is not applicable in this particular problem).Here's the process for our problem:
- Start with: \(20 + 0.10m < 30 + 0.05m\)
- Subtract \(0.05m\) from both sides: \(20 + 0.05m < 30\)
- Subtract 20 from both sides: \(0.05m > 10\)
- Divide both sides by \(0.05\): \(m > 200\)
Other exercises in this chapter
Problem 132
Write the equation of a rational function$$ f(x)=\frac{p(x)}{q(x)} \text {having the indicated properties in which the degrees} $$ of p and q are as small as po
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Write the equation of a rational function$$ f(x)=\frac{p(x)}{q(x)} \text {having the indicated properties in which the degrees} $$ of p and q are as small as po
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Will help you prepare for the material covered in the next section. $$ \text { Solve: } 2 x^{2}+x=15 $$
View solution Problem 138
Will help you prepare for the material covered in the next section. $$ \text { Solve: } x^{3}+x^{2}=4 x+4 $$
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