Problem 134
Question
Aluminium chloride exists as dimer \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\) in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives (a) \(\mathrm{Al}_{2} \mathrm{O}_{3}+6 \mathrm{HCl}\) (b) \(\mathrm{Al}^{3+}+3 \mathrm{Cl}\) (c) \([\mathrm{Al}(\mathrm{OH})]^{3-}+3 \mathrm{HCl}\) (d) \(\left[\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}+3 \mathrm{Cl}^{-}\)
Step-by-Step Solution
Verified Answer
(d) \(\left[\mathrm{Al}\left(\mathrm{H}_2\mathrm{O}\right)_6\right]^{3+}+3 \mathrm{Cl}^-\)
1Step 1: Analyze given compound
Aluminium chloride exists as a dimer, \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\), both in the solid state and in solution when in non-polar solvents like benzene. However, this form changes when dissolved in water.
2Step 2: Identify possible interactions with water
Aluminium chloride is a Lewis acid, and when it is dissolved in water, it undergoes hydrolysis. This means it reacts with water to form different species than when it is in a non-polar solvent or solid-state.
3Step 3: Expect resulting species in water
In water, the \(\mathrm{AlCl}_3\) part of \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\) will dissociate and undergo hydrolysis. As a result, \(\mathrm{Al}^{3+}\) generally coordinates with water molecules to form the hexaaqua complex \(\left[\mathrm{Al}\left(\mathrm{H}_2\mathrm{O}\right)_6\right]^{3+}\).
4Step 4: Identify release of other ions
When \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\) dissociates in water and hydrolyzes, chloride ions \(\mathrm{Cl}^-\) are released into solution as the counter ion to the positively charged complex.
5Step 5: Choose the correct option based on reaction
The process ultimately leads to the formation of \(\left[\mathrm{Al}\left(\mathrm{H}_2\mathrm{O}\right)_6\right]^{3+}\) and \(3 \mathrm{Cl}^-\) ions per aluminum chloride unit. This corresponds to option (d) \(\left[\mathrm{Al}\left(\mathrm{H}_2\mathrm{O}\right)_6\right]^{3+}+3 \mathrm{Cl}^-\).
Key Concepts
DimerizationHydrolysisLewis AcidsCoordination Complexes
Dimerization
Dimerization is the process through which two identical compounds, or monomers, chemically bond to form a dimer. In the case of aluminum chloride, \(\mathrm{AlCl}_3\) units link together to create the dimer \(\mathrm{Al}_{2}\mathrm{Cl}_{6}\). This occurs because aluminum, a small atom with a high charge density, needs to satisfy its coordination number.A few reasons why dimerization happens include:
- Stabilization: Forming a dimer can lower the system's energy, making it more stable in non-polar solvents or solid states.
- Coordination Satisfaction: The aluminum in \(\mathrm{AlCl}_3\) aims to achieve six coordinated chloride ions, which the dimer can accommodate.
Hydrolysis
Hydrolysis is a chemical reaction that involves breaking down a compound by reacting it with water. For aluminum chloride \(\mathrm{AlCl}_3\), which behaves differently in water, hydrolysis plays a crucial role.When \(\mathrm{AlCl}_3\) is dissolved in water:
- It reacts with water because of its basic and acidic balance disturbance.
- The \(\mathrm{Al}^{3+}\) ions undergo hydrolysis, leading to the formation of acidic species, such as \([\mathrm{Al}(\mathrm{OH})]^{3-}\).
- Hydrolysis results in the evolution of \(\mathrm{Cl}^{-}\) ions.
Lewis Acids
A Lewis acid is a compound or element that can accept an electron pair. In the realm of aluminum chloride chemistry, \(\mathrm{AlCl}_3\) is a classic example of a Lewis acid.Key attributes of \(\mathrm{AlCl}_3\) as a Lewis acid include:
- Electron Deficiency: Aluminum in \(\mathrm{AlCl}_3\) has an empty orbital, making it thirsty for electron pairs.
- Bond Formation: Its electron-accepting ability allows it to form bonds with electron donors—referred to as Lewis bases.
- Hydrolysis: When \(\mathrm{AlCl}_3\) encounters water, its Lewis acid characteristic promotes the uptake of hydroxide ions, leading to hydrolysis.
Coordination Complexes
Coordination complexes involve a central atom that binds to surrounding molecules or ions, known as ligands. When aluminum chloride reacts in water, it forms a well-known coordination complex.Here's how it works with \(\mathrm{AlCl}_3\):
- The \(\mathrm{Al}^{3+}\) ion coordinates with water molecules due to their polar nature, forming the hexaaqua complex \(\left[\mathrm{Al}(\mathrm{H}_2\mathrm{O})_6\right]^{3+}\).
- The coordination number refers to the number of ligand bonds with the central atom. Here, aluminum coordinates with six water molecules.
- This forms a stable complex in solution, vital to the hydrolysis process.
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